auth_url="https://api.instagram.com/oauth/authorize/?client_id=" + client_id + "&redirect_uri=" + redirect_uri + "&response_type=code"

print auth_url

print "Take this url and paste in your browser. Authorize the app: "+auth_url #authorization step. need a better way to do this

redirected_url=raw_input("Now enter the url returned after authorization.\n") #browser will redirect to a new page whose url will have the code as a response

code=redirected_url.split('code=')[1]

req_params={"client_id":client_id, "client_secret":client_secret, "redirect_uri":redirect_uri, "grant_type":grant_type, "code":code}

request_url="https://api.instagram.com/oauth/access_token"

r=requests.post(request_url, data=req_params) #making a POST request with the client details as parameters

data=json.loads(r.text)

access_token=str(data["access_token"])

url="https://api.instagram.com/v1/media/search?lat="+lat+"&lng="+lng+"&distance=5000"+"&access_token="+access_token

print url

r=requests.get(url)

resp=json.loads(r.text)

for i in range(10): #just getting 10 images. can be changed

pic_url=resp['data'][i]['images']['standard_resolution']['url'] #getting the image url

p=requests.get(pic_url)

f_name=str(location)+ ' pic '+str(i)+'.jpg'

with open(f_name,'wb') as f:

f.write(p.content)

f.close()