def test(n=100*1000):
    print("%dth Fibonacci number of various types:" % n)
    for z in 0, gmpy.mpz(0), gmpy.mpf(0):
        tip, tim, tot = timedfib(n, z)
        print("    %5.3f %s %s" % (tim, gmpy.fdigits(tot,10,6), tip))
    tip, tim, tot = timedfibsp(n, 1)
    print("    %5.3f %s %s" % (tim, gmpy.fdigits(tot,10,6), "gmpy.fib"))
Ejemplo n.º 2
0
#!/usr/bin/python

# Calculate digits of e
# Marcus Kazmierczak, [email protected]
# July 29th, 2004

# the formula
#  e = 1/0! + 1/1! + 1/2! + 1/3! + 1/4! + ... 1/N!

# You should chop off the last five digits returned
# they aren't necessarily accurate



# precision library 
import gmpy

# how many digits (roughly)
N = 1000


gmpy.set_minprec(int(N*3.5+16))
e = gmpy.mpf('1.0')
    
for n in range(1,N+3):
    e = gmpy.fdigits(gmpy.mpf(e) + (gmpy.mpf('1.0') / gmpy.fac(n)))

print e
Ejemplo n.º 3
0
import gmpy, time

def timedfib(n, zero):
    start=time.clock()
    a=zero; b=a+1
    for i in range(n):
        a,b=b,a+b
    stend=time.clock()
    return type(zero), stend-start, a

def timedfibsp(n, one):
    start=time.clock()
    result=gmpy.fib(n)
    stend=time.clock()
    return type(one), stend-start, result

def test(n=100*1000):
    print "%dth Fibonacci number of various types:" % n
    for z in 0L, gmpy.mpz(0), gmpy.mpf(0):
        tip, tim, tot = timedfib(n, z)
        print "    %5.3f %s %s" % (tim, gmpy.fdigits(tot,10,6), tip)
    tip, tim, tot = timedfibsp(n, 1)
    print "    %5.3f %s %s" % (tim, gmpy.fdigits(tot,10,6), "gmpy.fib")


if __name__=='__main__':
    test()