def _match(self, lab_l1, lab_l2, equal):
d1, d2 = self._d1, self._d2
mapping = self._mapping
# for each leaf label in both tree1 and tree2
l = intersection(lab_l1.keys(), lab_l2.keys())
# sort list to avoid differences between python version
l.sort()
for label in l:
s1 = lab_l1[label]
s2 = lab_l2[label]
# compute the longest common subsequence
common = lcs2(s1, s2, equal)
# for each pair of nodes (x,y) in the lcs
for x, y in common:
# add (x,y) to the mapping
mapping.append((x, y))
# mark node from tree 1 as mapped
x[N_MAPPED] = TRUE
# fill the mapping cache
for n in get_ancestors(x, []):
d1[(id(n), id(x))] = 1
for n in get_ancestors(y, []):
d2[(id(n), id(y))] = 1
def _align_children(self, w, x):
""" align children to correct misaligned nodes
"""
_partner = partner
# mark all children of w an d as "out of order"
self._childs_out_of_order(w)
self._childs_out_of_order(x)
# s1: children of w whose partner is children of x
s1 = [n for n in w[N_CHILDS] if in_ref(x[N_CHILDS], _partner(0,n))]
# s2: children of x whose partners are children of w
s2 = [n for n in x[N_CHILDS] if in_ref(w[N_CHILDS], _partner(1,n))]
# compute the longest common subsequence
s = lcs2(s1, s2, has_couple)
# mark each (a,b) from lcs in order
for a, b in s:
a[N_INORDER] = b[N_INORDER] = TRUE
s1.pop(index_ref(s1, a))
# s: a E T1, b E T2, (a,b) E M, (a;b) not E s
for a in s1:
b = _partner(0, a)
# mark a and b in order
a[N_INORDER] = b[N_INORDER] = TRUE
k = self._find_pos(b)
self._make_move(a, w, k)
