class SearchServiceIterable(SearchService):
"""A SearchService that can be used as an iterator"""
def __init__(self, service_manager, name, query=None):
"""Constructor for Service."""
super(SearchServiceIterable, self).__init__(service_manager, name)
# for iterator
self.query = query
self.resultsBuffer = Response()
# This is an indication about the Response is not a real response, and we need to ask for a real response in Next
self.resultsBuffer.feed['opensearch_totalresults'] = sys.maxint
self.next_result = 0
def set_query(self, query):
"""
Sets the query
It is mandatory to set a query, here or in the constractor.
"""
self.query = query
def __iter__(self):
"""
Iterator member function
Parameters:
* None
Returns:
* An iterarator for the object, in this case, the object itself
"""
return self
def next(self):
"""
Iterator member function
Parameters:
* None
Returns:
* The next item of the iterator, the next entry in the results
"""
#print " total results ", self.resultsBuffer.get_totalresults()
#print " items per page ", self.resultsBuffer.get_itemsperpage()
if self.query == None:
print "None to search!!"
#None to search!! The loop has finished
raise StopIteration
if len(self.resultsBuffer.entries) == 0:
#print self.resultsBuffer.get_totalresults(), " == ", self.next_result
if (int(self.resultsBuffer.get_totalresults()) <=
self.next_result):
raise StopIteration
self.resultsBuffer = self.search(self.query, self.next_result)
self.next_result += int(self.resultsBuffer.get_itemsperpage())
if len(self.resultsBuffer.entries) == 0:
raise StopIteration
else:
return self.resultsBuffer.entries.pop(0)
def pull(self, numberItems):
"""
Iterator member function. It gives a list of results.
Note: Usually, "pull" returns an iterator. Here it returns a list (that, in turn, is iterable), The reason is
that the list is easy to store in a variable. It is the only easy way to repear the results, because when
the exclusion filter change el number of responses, going backwards
Parameters:
* NumberItems: Number of demanded items
Returns:
* A list with the next numberItems items.
"""
listItems = []
for i, item in enumerate(self):
if i < numberItems:
listItems.append(item)
else:
break
return listItems
class SearchServiceIterable(SearchService):
"""A SearchService that can be used as an iterator"""
def __init__(self, service_manager, name, query=None):
"""Constructor for Service."""
super(SearchServiceIterable,self).__init__(service_manager,name)
# for iterator
self.query = query
self.resultsBuffer = Response()
# This is an indication about the Response is not a real response, and we need to ask for a real response in Next
self.resultsBuffer.feed['opensearch_totalresults'] = sys.maxint
self.next_result = 0
def set_query(self,query):
"""
Sets the query
It is mandatory to set a query, here or in the constractor.
"""
self.query = query
def __iter__(self):
"""
Iterator member function
Parameters:
* None
Returns:
* An iterarator for the object, in this case, the object itself
"""
return self
def next(self):
"""
Iterator member function
Parameters:
* None
Returns:
* The next item of the iterator, the next entry in the results
"""
#print " total results ", self.resultsBuffer.get_totalresults()
#print " items per page ", self.resultsBuffer.get_itemsperpage()
if self.query == None:
print "None to search!!"
#None to search!! The loop has finished
raise StopIteration
if len(self.resultsBuffer.entries) == 0:
#print self.resultsBuffer.get_totalresults(), " == ", self.next_result
if (int(self.resultsBuffer.get_totalresults()) <= self.next_result):
raise StopIteration
self.resultsBuffer = self.search(self.query, self.next_result)
self.next_result += int(self.resultsBuffer.get_itemsperpage())
if len(self.resultsBuffer.entries) == 0:
raise StopIteration
else:
return self.resultsBuffer.entries.pop(0)
def pull(self, numberItems):
"""
Iterator member function. It gives a list of results.
Note: Usually, "pull" returns an iterator. Here it returns a list (that, in turn, is iterable), The reason is
that the list is easy to store in a variable. It is the only easy way to repear the results, because when
the exclusion filter change el number of responses, going backwards
Parameters:
* NumberItems: Number of demanded items
Returns:
* A list with the next numberItems items.
"""
listItems = []
for i,item in enumerate(self):
if i < numberItems:
listItems.append(item)
else:
break
return listItems
