def expression_valid_windows(windows, candidate):
valid_window = []
valid_windows = []
buff = []
for window in windows:
if (ana_useful.exists_linkword(window) == True
and ana_useful.count_cand(window) == 2):
if ana_useful.is_cand(
window[-1]): #list[-1] returns last item of the list
cand2 = ana_useful.which_cand([window[-1]])
if cand2[2] not in candidate.split(
): #to avoid building expression like "bâtiment de cet ensemble de bâtiments" -> "batiment de bâtiment"
buff.append(
window
) #dans ce cas la fenetre valide est de type (CAND1 + "aword" + CAND2) avec un mot de schéma quelque part.
# in the buffer because we need to know if the aword in center is not the same 3 times or more (this case it would be better to build an expansion first, then an expression)
else:
short_window = ana_useful.cut_window(window, 2)
#Puisqu'on a 2 CAND et que la fenetre fait 3 mots et que le dernier mot n'est pas un CAND alors la fenetre était de type CAND + CAND + mot quelconque
if ana_useful.exists_linkword(short_window) == True:
valid_windows.append(
short_window
) #dans ce cas la fenetre valide est de type (CAND1 + CAND2) avec un mot de schéma entre eux .
# check if the aword in center is not the same 3 times or more (this case it would be better to build an expansion first, then an expression)
valid_windows.extend(not_expa_inside_expre(buff))
return valid_windows
def nucleus_valid_window(window):
if ana_useful.exists_linkword(window):
for occurrence in window:
index_cand = 0
if ana_useful.is_cand(occurrence):
index_cand = window.index(occurrence)
break
right_window = window[index_cand:]
if ana_useful.count_cand(right_window) < 2 and ana_useful.exists_linkword(right_window):
return right_window
def nucleus_valid_window(window):
if ana_useful.exists_linkword(window):
for occurrence in window:
index_cand = 0
if ana_useful.is_cand(occurrence):
index_cand = window.index(occurrence)
break
right_window = window[index_cand:]
if ana_useful.count_cand(
right_window) < 2 and ana_useful.exists_linkword(right_window):
return right_window
def expression_valid_windows(windows, candidate):
valid_window = []
valid_windows = []
buff = []
for window in windows:
if (ana_useful.exists_linkword(window) == True and ana_useful.count_cand(window) == 2):
if ana_useful.is_cand(window[-1]): #list[-1] returns last item of the list
cand2 = ana_useful.which_cand([window[-1]])
if cand2[2] not in candidate.split(): #to avoid building expression like "bâtiment de cet ensemble de bâtiments" -> "batiment de bâtiment"
buff.append(window) #dans ce cas la fenetre valide est de type (CAND1 + "aword" + CAND2) avec un mot de schéma quelque part.
# in the buffer because we need to know if the aword in center is not the same 3 times or more (this case it would be better to build an expansion first, then an expression)
else:
short_window = ana_useful.cut_window(window, 2)
#Puisqu'on a 2 CAND et que la fenetre fait 3 mots et que le dernier mot n'est pas un CAND alors la fenetre était de type CAND + CAND + mot quelconque
if ana_useful.exists_linkword(short_window) == True:
valid_windows.append(short_window) #dans ce cas la fenetre valide est de type (CAND1 + CAND2) avec un mot de schéma entre eux .
# check if the aword in center is not the same 3 times or more (this case it would be better to build an expansion first, then an expression)
valid_windows.extend(not_expa_inside_expre(buff))
return valid_windows
