def showTilsForConcursos(concFrom=None, concTo=None, tilN=None):
concursos = sl.getListAllConcursosObjs()
if concTo == None:
concTo = len(concursos)
if concFrom == None:
concFrom = concTo - 100
if concFrom < 1:
concFrom = 1
if tilN == None:
tilN = 5
count=0; tilPatternDict = {}
for concurso in concursos[concFrom - 1 : concTo]:
count+=1
concursoExt = ConcursoExt(concurso) # an empty obj, just to clue its getTilN() method into concurso obj.
#tilPatternStr = concursoExt.getTilN(5)
# concurso.getTilN = concursoExt.getTilN
tilPatternStr = concursoExt.getTilN(tilN)
if tilPatternStr == None:
print 'tilPatternStr == None'
continue
if tilPatternStr in tilPatternDict.keys():
tilPatternDict[tilPatternStr]+=1
else:
tilPatternDict[tilPatternStr]=1
nDoConc = concursoExt['nDoConc']
dezenasStr = concursoExt.getDezenasPrintableInOrder()
print nDoConc, dezenasStr, tilPatternStr, 'sum =', tilMod.sumUpTilPattern(tilPatternStr)
#concursoExt.concurso.getTilN =
patterns = tilPatternDict.keys()
patterns.sort()
for pattern in patterns:
print pattern, 'happened', tilPatternDict[pattern], 'times'
def testAdHoc2(): listWithFrequencyFrontiers = fm.calculateTilOfNUpToConcursoI() print 'listWithFrequencyFrontiers', listWithFrequencyFrontiers freqAtEachConcurso = fm.FrequenciesThruConcursos() frequencies = freqAtEachConcurso.frequenciesOfAllDezenasAtConcursoI() print 'frequencies', frequencies concursos = sl.getListAllConcursosObjs() nDoConcurso = len(concursos) print 'nDoConcurso', nDoConcurso, freqAtEachConcurso[nDoConcurso]
def test_totalOfFreqsConsistency(self):
'''
This test does the following
6 * n_concs_total = sum of each dezena's frequency at n_concs_total
Eg
given n_concs_total = 1330, it results:
6 * 1330 = 7980 = f(1) + f(2) + ... + f(60)
ie.
the summation of every dezena frequency must equal 7980
'''
concursos = sl.getListAllConcursosObjs()
n_concs_total = len(concursos)
#freqAtEachConcurso = fm.statsStore['freqAtEachConcurso']
freqAtEachConcurso = fm.FrequenciesThruConcursos()
for i in range(1, n_concs_total+1):
shouldBeSum = 6 * i
self.assertEqual(freqAtEachConcurso.sumUpTo(i), shouldBeSum)
def test_mountDezenasFrequencies(self):
'''
The fm.mountDezenasFrequencies() sums up all dezenas frequencies concurso by concurso
The simplest case is for the very 1st concurso where any dezena frequency should be 1
So the simplest case is a Test Case in here, the first one below
The second Test Case is just to check if passing in parameter ate_concurso_n=0 will return the same as passing no parameter at all
The two must equal and then pass the assertEqual
Some other test combinations may be seen below
'''
concursos = sl.getListAllConcursosObjs()
concurso1 = concursos[0]
dictForConc1 = {}
for dezena in concurso1.getDezenas():
dictForConc1[dezena] = 1
self.assertEqual(fm.mountDezenasFrequencies(ate_concurso_n=1), dictForConc1)
# self.assertEqual(type(mountDezenasFrequencies()), dict)
self.assertEqual(fm.mountDezenasFrequencies(ate_concurso_n=0), fm.mountDezenasFrequencies())
