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Project 3_Final3_ChengyaoWang.py
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Project 3_Final3_ChengyaoWang.py
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#!/usr/bin/env python2
# -*- coding: utf-8 -*-
"""
Created on Sun Mar 10 12:11:18 2019
Project3 for EE511
Author:Chengyao Wang
USCID:6961599816
Contact Email:chengyao@usc.edu
"""
import numpy as np
import matplotlib.pyplot as plt
import random as rd
import math
from scipy.stats import expon
from scipy.stats import norm
from scipy.stats import beta
def func_1a(repeat_times,total_sample_number,plot):
x=[0.0]*total_sample_number
y=[0.0]*total_sample_number
area=[0.0]*repeat_times
sample_mean=0.0
sample_variance=0.0
for repeat in range(0,repeat_times):
for i in range(0,total_sample_number):
x[i]=rd.uniform(0,1)
y[i]=rd.uniform(0,1)
area[repeat]+=((x[i]**2+y[i]**2)<=1)&(((x[i]-1)**2+(y[i]-1)**2)<=1)
area[repeat]/=total_sample_number
sample_mean+=area[repeat]/repeat_times
for i in range(0,repeat_times):
sample_variance+=(area[i]-sample_mean)**2/repeat_times
if plot==1:
plt.scatter(np.arange(0,repeat_times),area)
plt.title("Area estimation of the samples")
plt.xlabel("Samples")
plt.ylabel("Area Estimation")
plt.grid(True)
plt.show()
print "The average of this ",repeat_times," samples is: ",sample_mean
print "The sample variance of this ",repeat_times," samples is :",sample_variance
return sample_variance
print "\n\n\n\n"
def func_1b():
variance=[0]*100
for i in range(1,101):
variance[i-1]=func_1a(50,500*i,0)
plt.scatter(np.arange(500,50500,500),variance,s=1)
plt.title("Variance-Number of Samples")
plt.xlabel("Number of Samples")
plt.ylabel("Variance")
plt.ylim(ymin=-0.00075)
plt.ylim(ymax=0.00075)
plt.grid(True)
plt.show()
def function1(x):
return 1/(1+np.sinh(x)*np.log(x))
def function2(x,y):
return np.exp(-x*x*x*x-y*y*y*y)
def function3(x,y):
return 20+x**2+y**2-10*(np.cos(2*math.pi*x)+np.cos(2*math.pi*y))
def func_2a1(repeat_times,sample_number):
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j in range(0,sample_number):
result[i]+=2.2*function1(rd.uniform(0.8,3))/sample_number
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 1 with standard Monte Carlo Estimation")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_2a2(repeat_times,sample_number):
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j in range(0,sample_number):
result[i]+=39.478*function2(rd.uniform(-math.pi,math.pi),rd.uniform(-math.pi,math.pi))/sample_number
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 2 with standard Monte Carlo Estimation")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_2b1(repeat_times,sample_number):
#use pdf of exponential distribution to determine the importance of each interval
#determine the parameter for exponential pdf
lamda=1.0/(np.log(function1(0.8)/function1(1.8)))
sample_allocation=[0]*10
for i in range(0,10):
x1=expon.cdf(0.22*i+0.8,loc=0,scale=lamda)
x2=expon.cdf(0.22*i+1.02,loc=0,scale=lamda)
sample_allocation[i]=sample_number*(x2-x1)
condition=expon.cdf(3,loc=0,scale=lamda)-expon.cdf(0.8,loc=0,scale=lamda)
sum_allocation=0
for i in range(0,9):
sample_allocation[9-i]=int(sample_allocation[9-i]/condition)
sum_allocation+=sample_allocation[9-i]
sample_allocation[0]=sample_number-sum_allocation
print "The allocation of Sample Numbers Derived from Exponential pdf with Lamda=",lamda,"is:\n"
print sample_allocation
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j in range(0,10):
for k in range(0,sample_allocation[j]):
result[i]+=0.22*function1(rd.uniform(0.22*j+0.8,0.22*j+1.02))/sample_allocation[j]
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 1 with Monte Carlo Estimation Imported with stratification")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
#Monte Carlo Method Using Importance Sampling
#Use Exponential pdf with lamda=1.0/(np.log(function1(0.8)/function1(1.8)))
def func_2b11(repeat_times,sample_number):
result=[0]*repeat_times
result_mean=0
result_variance=0
lamda=1.0/(np.log(function1(0.8)/function1(1.8)))
envelope_size=expon.cdf(3,loc=0,scale=lamda)-expon.cdf(0.8,loc=0,scale=lamda)
for i in range(0,repeat_times):
for j in range(0,sample_number):
x=rd.uniform(0.8,3)
result[i]+=(function1(x)*envelope_size)/(expon.pdf(x,loc=0,scale=lamda)*sample_number)
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 1 with Monte Carlo Estimation Imported with Importance Sampling")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_2b2(repeat_times,sample_number):
#use bivariate normal distribution of uncorrelated X & Y to determine the importance of each interval
#use normal distribution with mean=0, variance=0.8
sample_allocation=np.empty((5,5),dtype=float)
allocation=[0.0]*5
sum_allocation=0.0
for i in range(0,5):
x1=norm.cdf((2.0*i/5-1)*math.pi,loc=0,scale=0.8)
x2=norm.cdf((2.0*i/5-0.6)*math.pi,loc=0,scale=0.8)
allocation[i]=(x2-x1)
condition=(norm.cdf(-math.pi,loc=0,scale=1)-norm.cdf(math.pi,loc=0,scale=1))**2
for i in range(0,5):
for j in range(0,5):
sample_allocation[i][j]=int(allocation[i]*allocation[j]*sample_number/condition)
sum_allocation+=sample_allocation[i][j]
sample_allocation[2][2]+=(sample_number-sum_allocation)
print "The allocation of Sample Numbers Derived from Exponential pdf is:\n"
print sample_allocation
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j1 in range(0,5):
for j2 in range(0,5):
if sample_allocation[j1][j2]!=0:
for k in range(0,int(sample_allocation[j1][j2])):
x=rd.uniform((2.0*j1/5-1)*math.pi,(2.0*j1/5-0.6)*math.pi)
y=rd.uniform((2.0*j2/5-1)*math.pi,(2.0*j2/5-0.6)*math.pi)
result[i]+=1.579*function2(x,y)/sample_allocation[j1][j2]
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 2 with Monte Carlo Estimation Imported with stratification")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
#Monte Carlo Method Using Importance Sampling
def func_2b21(repeat_times,sample_number):
result=[0.0]*repeat_times
result_mean=0.0
result_variance=0.0
envelope_size=np.sqrt(2)*math.pi*(norm.cdf(math.pi)-norm.cdf(-math.pi))**2
for i in range(0,repeat_times):
for j in range(0,sample_number):
x=rd.uniform(-math.pi,math.pi)
y=rd.uniform(-math.pi,math.pi)
result[i]+=(function2(x,y)*envelope_size)/(norm.pdf(x)*norm.pdf(y)*sample_number)
#((function2(x,y)*envelope_size)/(norm.pdf(x)*norm.pdf(y)*sample_number))
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 2 with Monte Carlo Estimation Imported with Importance Sampling")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_3a1(repeat_times):
#Normal Monte Carlo Integration Estimate
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j in range(0,10000):
result[i]+=100*function3(rd.uniform(-5,5),rd.uniform(-5,5))/10000
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 3 with Standard Monte Carlo Estimation")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_3a2(repeat_times,sample_number):
#use bivariate beta distribution which are uncorrelated to determine the allocation of samples
#and make them even symmetric
#use beta distribution with a=3 b=1
sample_allocation=np.empty((5,5),dtype=float)
allocation=[0.0]*5
sum_allocation=0.0
condition=0
alpha_1=0.8
beta_1=0.7
allocation[4]=beta.cdf(1,alpha_1,beta_1)-beta.cdf(0.6,alpha_1,beta_1)
allocation[3]=beta.cdf(0.6,alpha_1,beta_1)-beta.cdf(0.2,alpha_1,beta_1)
allocation[2]=2*(beta.cdf(0.2,alpha_1,beta_1)-beta.cdf(0,alpha_1,beta_1))
allocation[1]=allocation[3]
allocation[0]=allocation[4]
for i in range(0,5):
condition+=allocation[i]
condition=condition**2
for i in range(0,5):
for j in range(0,5):
sample_allocation[i][j]=int(allocation[i]*allocation[j]*sample_number/condition)
sum_allocation+=sample_allocation[i][j]
sample_allocation[2][2]+=(sample_number-sum_allocation)
print "The allocation of Sample Numbers Derived from Exponential pdf is:\n"
print sample_allocation
result=[0.0]*repeat_times
result_mean=0.0
result_variance=0.0
for i in range(0,repeat_times):
for j1 in range(0,5):
for j2 in range(0,5):
if sample_allocation[j1][j2]!=0:
for k in range(0,int(sample_allocation[j1][j2])):
x=rd.uniform(2.0*j1-5,2.0*j1-3)
y=rd.uniform(2.0*j2-5,2.0*j2-3)
result[i]+=4*function3(x,y)/sample_allocation[j1][j2]
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 3 with Monte Carlo Estimation Imported with stratification")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
def func_3a3(repeat_times):
#devide the interval into 5*5 bins
#Initial the number of samples in each bin equally
sample_allocation=np.full((5,5),400,dtype=float)
mean=[0.0]*1000
iteration_count=0
func_val_store=[0]*10000
#make sure to iterate at least once
while iteration_count<999:
iteration_count+=1
count=0
func_val_avg=np.empty((5,5))
for i in range(0,5):
for j in range(0,5):
step=int(math.sqrt(sample_allocation[i][j]))
for k1 in range(1,step+1):
for k2 in range(1,step+1):
x=2*i-5+float(2*k1)/(step+1)
y=2*j-5+float(2*k2)/(step+1)
func_val_store[count]=function3(x,y)
func_val_avg[i][j]+=func_val_store[count]
count+=1
if step==0:
func_val_avg[i][j]=0
else:
func_val_avg[i][j]/=(step**2)
#estimated integration in this iteration
for i in range(0,5):
for j in range(0,5):
mean[iteration_count]+=func_val_avg[i][j]*4
#Compare with the estimated mean in the last iteration
if abs(mean[iteration_count]-mean[iteration_count-1])<0.00001:
break
#re-distribute the number in each bins, with totol sample_number of samples
#The sample numbers in each bin is linearly positively propotional to abs of funv_val
func_val_total=0
number_in_bin_count=0
for i in range(0,5):
for j in range(0,5):
func_val_total+=abs(func_val_avg[i][j])
for i in range(0,5):
for j in range(0,5):
sample_allocation[i][j]=int(10000*abs(func_val_avg[i][j])/func_val_total)
number_in_bin_count+=sample_allocation[i][j]
#add the rest few sample to the interval that has the largest func_val
sample_allocation[2][2]+=(10000-number_in_bin_count)
#use the optimized sample_allocation to estimate the Integration
print "The allocation of Sample Numbers Derived from Exponential pdf is:\n"
print sample_allocation
result=[0]*repeat_times
result_mean=0
result_variance=0
for i in range(0,repeat_times):
for j1 in range(0,5):
for j2 in range(0,5):
if sample_allocation[j1][j2]!=0:
for k in range(0,int(sample_allocation[j1][j2])):
x=rd.uniform(2*j1-5,2*j1-3)
y=rd.uniform(2*j2-5,2*j2-3)
result[i]+=4*function3(x,y)/sample_allocation[j1][j2]
result_mean+=result[i]/repeat_times
for i in range(0,repeat_times):
result_variance+=(result[i]-result_mean)**2
result_variance/=repeat_times
print "The Variance of the 50 samples is ",result_variance
print "The average of this",repeat_times,"samples is: ",result_mean
plt.scatter(np.arange(0,repeat_times),result)
plt.title("Function 3 with Monte Carlo Estimation Imported with own sample allocation strategy")
plt.xlabel("Trial")
plt.ylabel("Estimation Result")
plt.grid(True)
plt.show()
print "\n\n\n\n"
func_1a(50,500,1)
func_1a(50,5000,1)
func_1a(50,50000,1)
func_1b()
func_2a1(50,1000)
func_2a2(50,1000)
func_2b1(50,1000)
func_2b11(50,1000)
func_2b2(50,1000)
func_2b21(50,1000)
func_3a1(50)
func_3a2(50,10000)
func_3a3(50)