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util_lec_3.py
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util_lec_3.py
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import numpy as np
import scipy.sparse as sp
import scipy.sparse.linalg as splinalg
from scipy.sparse import csc_matrix,csr_matrix,coo_matrix
from scikits import umfpack
from scikits.umfpack import UMFPACK_A,UMFPACK_At,UMFPACK_Aat
import time
from enum import Enum,unique
#############################
## 一些与数值误差相关的常数的定义
INF = 1e16
PRIMAL_TOL = 1e-7
PRIMAL_RELA_TOL = 1e-9
DUAL_TOL = 1e-7
CON_TOL = 1e-5
PIVOT_TOL = 1e-5
REMOVE_TOL = 1e-14
ZERO_TOL = 1e-12
#############################
#############################
## 一些用于记录状态的枚举类型
@unique
class VarStatus(Enum):
AT_UPPER_BOUND = -1 ## 对应U
AT_LOWER_BOUND = 1 ## 对应L
OTHER = 0 ## 对应B
@unique
class BoundType(Enum):
## 变量的上下界类型
BOTH_BOUNDED = 3
UPPER_BOUNDED = 2
LOWER_BOUNDED = 1
FREE = 0
@unique
class SolveStatus(Enum):
'''
求解状态,每步DS迭代后返回,用于判断后续动作
'''
ONGOING = 0 ## 继续迭代
OPT = 1 ## 最优
PRIMAL_INFEAS = 2 ## 原始不可行
DUAL_INFEAS = 3 ## 对偶不可行
OTHER = -2
ERR = -1
## 以下是一些需要用到的新状态
REFACTOR = 5 ## LU重分解
ROLLBACK = 6 ## 回滚
PHASE1 = 8 ## 需进行第一阶段
PHASE2 = 9 ## 需进行第二阶段
@unique
class LinearSolver(Enum):
'''
用于对线性方程求解/LU分解工具的选用,默认是UMFPACK;
计算实验表明UMFPACK比SUPERLU快20%以上
'''
UMFPACK = 0
SUPERLU = 1
LINEAR_SOLVER_TYPE = LinearSolver.UMFPACK
#############################
#############################
## 求解过程用到的元素类
class Solution(object):
def __init__(self,x,lam,s,sign):
self.x = x ## 原始问题解,实数
self.lam = lam ## 对偶问题解,实数
self.s = s ## 对偶问题解,实数
self.sign = sign ## 基(B,L,U)的标记,值的类型为上面定义的VarStatus
def copy(self):
## 该函数可以复制解,用于需要保留多组解的场景。
return Solution(x=self.x.copy(),s=self.s.copy(),
lam=self.lam.copy(),sign=self.sign.copy())
class Problem(object):
def __init__(self,A,b,c,l,u,AT=None):
## 基本输入:A,b,c,l,u
## 对应问题 min c^T x
## s.t. A x = b,
## l <= x <= u.
## 为了提高计算效率,A采用稀疏矩阵存储;b,c,l,u则是dense的向量
self.A,self.b,self.c,self.l,self.u = A,b,c,l,u
## 保存矩阵A的转置
if AT is None:
self.AT = self.A.T
else:
self.AT = AT
## 保存一些后续不会变的中间变量,可以提高后续评估的计算速度
self.n,self.m = self.A.shape
self.bounds_gap = self.u - self.l
self.bool_upper_unbounded = self.u >= INF ## 是否上界无界
self.bool_lower_unbounded = self.l <= -INF ## 是否下界无界
self.bool_not_both_bounded = self.bool_upper_unbounded | self.bool_lower_unbounded
self.bound_type = np.zeros((self.m,),dtype=int) ## 上下界类型
self.bound_type[self.bool_lower_unbounded & self.bool_upper_unbounded] = BoundType.FREE.value
self.bound_type[self.bool_lower_unbounded & ~self.bool_upper_unbounded] = BoundType.UPPER_BOUNDED.value
self.bound_type[~self.bool_lower_unbounded & self.bool_upper_unbounded] = BoundType.LOWER_BOUNDED.value
self.bound_type[~self.bool_lower_unbounded & ~self.bool_upper_unbounded] = BoundType.BOTH_BOUNDED.value
self.primal_lower_bound_tol = - (np.abs(self.l) * PRIMAL_RELA_TOL + PRIMAL_TOL)
self.primal_upper_bound_tol = (np.abs(self.u) * PRIMAL_RELA_TOL + PRIMAL_TOL)
self.l_margin = self.l + self.primal_lower_bound_tol ## 考虑数值误差的下界
self.u_margin = self.u + self.primal_upper_bound_tol ## 考虑数值误差的上界
def copy(self):
## 复制函数,in case我们需要保留多组问题
return Problem(self.A,b=self.b.copy(),c=self.c.copy(),l=self.l.copy(),u=self.u.copy())
## **************************
## 原始/对偶目标函数的评估
def eval_primal_obj(self,sol):
## z = c^T x
return np.dot(self.c,sol.x)
def eval_dual_obj(self,sol):
## z = b^T \lambda + u^T s_u + l^T s_l
return (np.dot(self.b,sol.lam) + \
np.dot(self.u * (sol.sign == VarStatus.AT_UPPER_BOUND.value),sol.s) + \
np.dot(self.l * (sol.sign == VarStatus.AT_LOWER_BOUND.value),sol.s))
## **************************
## 原始/对偶线性约束的可行性评估
def eval_primal_con_infeas(self,sol):
## A x - b
return (self.A._mul_vector(sol.x) - self.b)
def eval_dual_con_infeas(self,sol):
## A^T \lambda + s - c
return (self.AT._mul_vector(sol.lam) + sol.s - self.c)
## **************************
## 原始/对偶变量和基的可行性评估
## 是否存在原始变量无界,也可以看作是基的对偶可行程度
def eval_unbnd(self,sol):
## x = INF or -INF
return ( ((self.bool_upper_unbounded) & (sol.sign == VarStatus.AT_UPPER_BOUND.value)) | \
((self.bool_lower_unbounded) & (sol.sign == VarStatus.AT_LOWER_BOUND.value)) )
## 解的原始可行程度
def eval_primal_inf(self,sol):
## l <= x <= u
primal_inf = np.maximum(sol.x - self.u,0) - np.maximum(self.l - sol.x,0)
bool_unbnd = self.eval_unbnd(sol)
primal_inf[bool_unbnd] += INF
return primal_inf
## 解的对偶可行程度
def eval_dual_inf(self,sol):
## s_u <= 0, s_l >= 0
dual_inf = np.maximum(sol.s,0) * (sol.sign == VarStatus.AT_UPPER_BOUND.value) + \
np.maximum(-sol.s,0) * (sol.sign == VarStatus.AT_LOWER_BOUND.value)
bool_unbnd = self.eval_unbnd(sol)
dual_inf[bool_unbnd] += np.abs(sol.s[bool_unbnd])
return dual_inf
## 基(B,L,U)与解(x,\lambda,s)的一致程度,也可以看作是基的原始可行程度
def eval_sign(self,sol):
## x_L = l_L, x_U = u_U
bool_sign = np.zeros((self.m,),dtype=bool)
bool_lower = sol.sign == VarStatus.AT_LOWER_BOUND.value
bool_upper = sol.sign == VarStatus.AT_UPPER_BOUND.value
bool_sign[bool_lower] = sol.x[bool_lower] != self.l[bool_lower]
bool_sign[bool_upper] = sol.x[bool_upper] != self.u[bool_upper]
return bool_sign
## **************************
## 计算对偶目标函数对对偶变量s变化的梯度
def eval_dual_grads(self,sol,lam_grad,s_grad):
dual_grads = (np.dot(self.b,lam_grad) + \
np.dot(self.u * (sol.sign == VarStatus.AT_UPPER_BOUND.value),s_grad) + \
np.dot(self.l * (sol.sign == VarStatus.AT_LOWER_BOUND.value),s_grad))
return dual_grads
## **************************
## 整合上述评估结果,形成字符串输出
def check_sol_status(self,sol,print_func=None,print_header=''):
infeas_dict = {'primal':False,'dual':False,'cons':False,'unbnd':False,'sign':False}
## 目标函数
primal_obj,dual_obj = self.eval_primal_obj(sol),self.eval_dual_obj(sol)
status_str = 'Obj Primal {:.4e} Dual {:.4e}'.format(primal_obj,dual_obj)
## 原始变量的infeasibility
primal_inf = self.eval_primal_inf(sol)
primal_inf_cnt = np.sum((primal_inf > self.primal_upper_bound_tol) | \
(primal_inf < self.primal_lower_bound_tol))
if primal_inf_cnt > 0:
status_str += ' Primal Inf {:.4e} ({:d})'.format(np.sum(np.abs(primal_inf)),primal_inf_cnt)
infeas_dict['primal'] = True
## 对偶变量的infeasibility
dual_inf = self.eval_dual_inf(sol)
dual_inf_cnt = np.sum(np.abs(dual_inf) > DUAL_TOL)
if dual_inf_cnt > 0:
status_str += ' Dual Inf {:.4e} ({:d})'.format(np.sum(np.abs(dual_inf)),dual_inf_cnt)
infeas_dict['dual'] = True
## 原始和对偶问题的线性约束的infeasibility
primal_con_inf,dual_con_inf = self.eval_primal_con_infeas(sol),self.eval_dual_con_infeas(sol)
con_inf_cnt = np.sum(np.abs(primal_con_inf) > CON_TOL) + np.sum(np.abs(dual_con_inf) > CON_TOL)
if con_inf_cnt > 0:
status_str += ' Con Inf {:.4e} ({:d})'.format(np.sum(np.abs(primal_con_inf)) + np.sum(np.abs(dual_con_inf)),con_inf_cnt)
infeas_dict['cons'] = True
## 上下界的consistency
bool_unbnd = self.eval_unbnd(sol)
bool_unbnd_cnt = np.sum(bool_unbnd)
if bool_unbnd_cnt > 0:
status_str += ' Bnd err {:d}'.format(bool_unbnd_cnt)
infeas_dict['unbnd'] = True
## 解与基的consistency
bool_sign = self.eval_sign(sol)
bool_sign_cnt = np.sum(bool_sign)
if bool_sign_cnt > 0:
status_str += ' Sign err {:d}'.format(bool_sign_cnt)
infeas_dict['sign'] = True
## 打印输出
if print_func is not None:
print_func('{} {}'.format(print_header,status_str))
return infeas_dict,status_str
class Basis(object):
'''
对$B和N=L or U的元素、以及线性代数相关的计算(相乘/方程求解/LU分解更新)进行管理
'''
def __init__(self,A,AT=None):
self.A = A
if AT is None:
self.AT = self.A.T
else:
self.AT = AT
self.n,self.m = self.A.shape
self.idxB,self.idxN,self.boolN = None,None,None
self.DSE_weights = None ## DSE权重
self.invB = None ## LU 分解结果
self.etas = [] ## PFI的连乘部分
self.eta_count = 0
def copy(self):
basis_new = Basis(self.A,self.AT)
basis_new.invB = self.invB
basis_new.eta_count = self.eta_count
basis_new.idxB = self.idxB.copy()
basis_new.idxN = self.idxN.copy()
basis_new.boolN = self.boolN.copy()
basis_new.DSE_weights = self.DSE_weights.copy()
basis_new.etas = self.etas.copy()
return basis_new
def reset_basis_idx(self,idxB):
self.idxB = idxB.copy()
self.boolN = np.ones((self.m,),dtype=bool)
self.boolN[self.idxB] = False
self.idxN = np.where(self.boolN)[0]
self.lu_factorize()
def lu_update(self,eta):
## 在PFI中,只需要增加\eta向量和对应的位置i_B即可
self.etas += [eta]
self.eta_count += 1
def lu_factorize(self):
## 重新做LU分解
self.B = self.A[:,self.idxB]
self.etas = []
self.eta_count = 0
if LINEAR_SOLVER_TYPE == LinearSolver.SUPERLU:
self.invB = splinalg.splu(self.B)
else:
self.invB = umfpack.splu(self.B)
def get_col(self,idx):
## 对从矩阵A中获取列idx的封装
## 需要A是CSC格式的
idx_start,idx_end = self.A.indptr[idx],self.A.indptr[idx+1]
data_,row_ = self.A.data[idx_start:idx_end],self.A.indices[idx_start:idx_end]
col = np.zeros((self.n,))
col[row_] = data_
return col
def get_elem_vec(self,idx,if_transpose=False):
## 对获取单位向量e的封装
if if_transpose:
e = np.zeros((self.n,))
else:
e = np.zeros((self.m,))
e[idx] = 1
return e
def solve(self,y,if_transpose=False):
## 基于PFI的线性方程求解
if if_transpose:
## A_B^T x = y
y_ = y.copy()
for eta in self.etas[::-1]:
y_[eta[0]] += np.dot(eta[1],y_)
if LINEAR_SOLVER_TYPE == LinearSolver.SUPERLU:
x = self.invB.solve(y_,trans='T')
else:
x = self.invB.umf.solve(UMFPACK_Aat, self.invB._A, y_, autoTranspose=True)
else:
## A_B x = y
if LINEAR_SOLVER_TYPE == LinearSolver.SUPERLU:
x = self.invB.solve(y)
else:
x = self.invB.umf.solve(UMFPACK_A, self.invB._A, y, autoTranspose=True)
for eta in self.etas:
x += x[eta[0]] * eta[1]
return x
def dot(self,x,if_transpose=False):
## 矩阵与向量的相乘
if if_transpose:
## y = A^T x
return self.AT._mul_vector(x)
else:
## y = A x
return self.A._mul_vector(x)
def get_DSE_weight(self,idx):
## 计算idx行的DSE权重|A_B^{-T} e_{idx}|_2^2
e = self.get_elem_vec(idx,if_transpose=True)
return np.sum(np.square(self.solve(e,if_transpose=True)))
def init_DSE_weights(self):
self.DSE_weights = np.ones((self.n,))
def reset_DSE_weights(self):
## 重新计算DSE权重
self.DSE_weights = np.array([self.get_DSE_weight(i) for i in range(self.n)])
def update_DSE_weights(self,idxI,xB_grad0,tau,betaI0):
## 通过迭代的方式更新DSE权重
alpha_j = xB_grad0[idxI]
betaI = betaI0 / alpha_j / alpha_j
self.DSE_weights += xB_grad0 * (xB_grad0 * betaI - 2 / alpha_j * tau)
self.DSE_weights[idxI] = betaI
self.DSE_weights = np.maximum(self.DSE_weights,1e-4)
def get_DSE_weights(self):
return self.DSE_weights
class DualSimplexSolver(object):
def __init__(self):
## 保存迭代过程中的信息,用于进行控制流处理
self.global_info = {'count':0,'start_time':time.time()}
def _pricing(self,problem,sol,basis):
idxB = basis.idxB
xB = sol.x[idxB]
primal_inf = np.minimum(xB - problem.l[idxB],0) + np.maximum(xB - problem.u[idxB],0)
bool_primal_inf = (primal_inf > problem.primal_upper_bound_tol[idxB]) | \
(primal_inf < problem.primal_lower_bound_tol[idxB])
if not np.any(bool_primal_inf):
## 原始解可行,因此达到最优
return SolveStatus.OPT,-1,-1,0
## 否则,根据DSE规则选取离开下标idxBI,并保存相应信息
## DSE weight已经保存在basis中
idxI = np.argmax(np.square(primal_inf)/basis.DSE_weights)
idxBI = idxB[idxI]
primal_gap = primal_inf[idxI]
return SolveStatus.ONGOING,idxI,idxBI,primal_gap
def _ratio_test(self,problem,sol,basis,s_grad,dual_grad):
idxN,boolN = basis.idxN,basis.boolN
## 统计可能会约束对偶步长的对偶变量的下标
idxL_bounded = np.where((sol.sign == VarStatus.AT_LOWER_BOUND.value) & (s_grad < 0))[0] ## 处于下界,要求s>=0
idxU_bounded = np.where((sol.sign == VarStatus.AT_UPPER_BOUND.value) & (s_grad > 0))[0] ## 处于上界,要求s<=0
idxF = np.where((sol.sign == VarStatus.OTHER.value) & boolN)[0] ## free变量,要求s==0
idxF_bounded = idxF[(np.abs(s_grad[idxF]) > 0)]
elems_bounded = np.concatenate([idxL_bounded,idxU_bounded,idxF_bounded])
if len(elems_bounded) == 0:
## 没有变量可以约束对偶步长,因此对偶步长可以无限大,从而对偶目标无界/原始解不可行
status,idxJ,idxNJ,alpha_dual,flip_list = SolveStatus.PRIMAL_INFEAS,-1,-1,0,[]
return status,idxJ,idxNJ,alpha_dual,flip_list
## 针对可能约束对偶步长的变量,进一步判断其是否可以做bound flip;如果可行,则进行相关计算
bool_not_both_bounded = problem.bool_not_both_bounded[elems_bounded]
s_grad_bounded = s_grad[elems_bounded]
## 计算bound filp对对偶梯度的影响
s_grad_abs_bounded = np.abs(s_grad_bounded)
dual_grad_delta_flipped = problem.bounds_gap[elems_bounded] * s_grad_abs_bounded
if (np.sum(dual_grad_delta_flipped) <= dual_grad) and (not np.any(bool_not_both_bounded)):
## 如果所有约束变量都可以做bound flip,而且flip完对偶的梯度仍是正数,则对偶目标无界/原始解不可行
status,idxJ,idxNJ,delta_dual,flip_list = SolveStatus.PRIMAL_INFEAS,-1,-1,0,[]
return status,idxJ,idxNJ,delta_dual,flip_list
## 计算每个约束变量对应bound flip的临界对偶步长
alpha_dual_allowed = - sol.s[elems_bounded] / s_grad_bounded
## 通过不可flip的变量进一步筛选
if np.any(bool_not_both_bounded):
alpha_dual_ub = np.min(alpha_dual_allowed[bool_not_both_bounded])
## 找到对应最小步长的不可flip变量之前的所有变量
idxs_remain = np.where(alpha_dual_allowed <= alpha_dual_ub)[0]
else:
## 考虑全部变量
idxs_remain = np.arange(len(elems_bounded),dtype=int)
## 通过alpha_dual_allowed对各变量进行排序
idxs_remain = idxs_remain[np.argsort(alpha_dual_allowed[idxs_remain])]
## 做线搜索,寻找临界的变量
dual_grad_remain = dual_grad
for idx_pivot in idxs_remain:
dual_grad_remain -= dual_grad_delta_flipped[idx_pivot]
if dual_grad_remain < 0:
break
## 整理结果
idxNJ = elems_bounded[idx_pivot]
alpha_dual = alpha_dual_allowed[idx_pivot]
bool_flip = (alpha_dual_allowed < alpha_dual)
flip_list = elems_bounded[bool_flip]
idxJ = np.where(idxN == idxNJ)[0]
return SolveStatus.ONGOING,idxJ,idxNJ,alpha_dual,flip_list
def _step(self,problem,sol,basis):
count = self.global_info.get('count',0)
header = '{} '.format(count)
## step 1: pricing, 选出离开下标idxBI = idxB[idxI], 并计算相应对偶变量的单位变化量
status_inner,idxI,idxBI,primal_gap = self._pricing(problem,sol,basis)
if status_inner == SolveStatus.OPT:
return SolveStatus.OPT,problem,sol,basis
dual_grad = abs(primal_gap) ## 原始变量的不可行程度正是对偶问题的梯度
bool_to_lower_bound = sol.x[idxBI] <= problem.l[idxBI]
direcDualI = 1 if bool_to_lower_bound else -1 ## 原始变量的移动方向
## 计算对偶变量的单位变化量
sB_grad0 = basis.get_elem_vec(idxI,if_transpose=True) ## A_B^{-T}e_I
lam_grad0 = basis.solve(sB_grad0,if_transpose=True) ## A_B^{-T}e_I
s_grad0 = basis.dot(lam_grad0,if_transpose=True) ## A^TA_B^{-T}e_I
if direcDualI == -1:
lam_grad = lam_grad0
s_grad = -s_grad0
else:
lam_grad = -lam_grad0
s_grad = s_grad0
## step 2: ratio test, 选出进入下标idxNJ = idxN[idxJ]
status_inner,idxJ,idxNJ,alpha_dual,flip_list = self._ratio_test(problem,sol,basis,s_grad,dual_grad)
if status_inner == SolveStatus.PRIMAL_INFEAS:
return SolveStatus.PRIMAL_INFEAS,problem,sol,basis
## step 3: 更新结果
aNJ = basis.get_col(idxNJ) ## A_j
xB_grad0 = basis.solve(aNJ,if_transpose=False) ## A_B^{-1}A_j
xB_grad = - xB_grad0
betaI = np.dot(lam_grad0,lam_grad0)
tau = basis.solve(lam_grad0,if_transpose=False)
## 校核数值稳定性,在这一个notebook中只做评估而不进行处理
if True:
## 校核通过\delta s和\delta x_B计算得到的alpha = e_I^T A_B^{-1} a_{NJ}的一致性
err_pivot = s_grad0[idxNJ] + xB_grad[idxI]
if abs(err_pivot) > PRIMAL_TOL * (1 + abs(xB_grad[idxI])):
print('{} WARN err FTRAN/BTRAN pivot consistency {:.4e}.'.format(header,err_pivot))
## 校核DSE权重的准确性
err_dse = betaI - basis.DSE_weights[idxI]
if abs(err_dse) > PIVOT_TOL * 10:
print('{} WARN err DSE accuracy {:.4e}.'.format(header,err_dse))
## 校核pivot element的大小
if abs(xB_grad[idxI]) < PIVOT_TOL:
print('{} WARN err pivot size {:.4e}.'.format(header,xB_grad[idxI]))
## 更新对偶变量
sol.lam += alpha_dual * lam_grad
sol.s += alpha_dual * s_grad
## 更新原始变量
if len(flip_list) > 0:
## 对x_N进行翻转
idx_flip_to_lower = flip_list[sol.sign[flip_list] == VarStatus.AT_UPPER_BOUND.value]
idx_flip_to_upper = flip_list[sol.sign[flip_list] == VarStatus.AT_LOWER_BOUND.value]
sol.x[idx_flip_to_lower] = problem.l[idx_flip_to_lower]
sol.x[idx_flip_to_upper] = problem.u[idx_flip_to_upper]
sol.sign[idx_flip_to_lower] = VarStatus.AT_LOWER_BOUND.value
sol.sign[idx_flip_to_upper] = VarStatus.AT_UPPER_BOUND.value
## 根据翻转的x_N,更新x_B
delta_x_flipped = np.zeros((basis.m,))
delta_x_flipped[idx_flip_to_lower] = -problem.bounds_gap[idx_flip_to_lower]
delta_x_flipped[idx_flip_to_upper] = problem.bounds_gap[idx_flip_to_upper]
delta_b_flipped = basis.dot(delta_x_flipped,if_transpose=False)
delta_xB = - basis.solve(delta_b_flipped,if_transpose=False)
sol.x[basis.idxB] += delta_xB
delta_xBI = delta_xB[idxI]
else:
delta_xBI = 0
## 然后,计算原始步长,并更新x_j和x_B
alpha_primal = (-primal_gap - delta_xBI) / xB_grad[idxI]
sol.x[basis.idxB] += alpha_primal * xB_grad
sol.x[idxBI] = problem.l[idxBI] if bool_to_lower_bound else problem.u[idxBI]
sol.sign[idxBI] = VarStatus.AT_LOWER_BOUND.value if bool_to_lower_bound else VarStatus.AT_UPPER_BOUND.value
sol.x[idxNJ] += alpha_primal
sol.sign[idxNJ] = VarStatus.OTHER.value ## 进入B
## 更新基
basis.idxB[idxI] = idxNJ
basis.idxN[idxJ] = idxBI
basis.boolN[idxBI] = True
basis.boolN[idxNJ] = False
## 更新PFI和DSE信息
eta_vec = -xB_grad0 / xB_grad0[idxI]
eta_vec[idxI] += 1 / xB_grad0[idxI]
eta = (idxI,eta_vec)
basis.lu_update(eta=eta)
basis.update_DSE_weights(idxI,xB_grad0,tau,betaI)
sol.s[basis.idxB] = 0
return SolveStatus.ONGOING,problem,sol,basis
def _compute_sol_from_basis(self,problem,basis,sign=None):
'''
给定一组基,计算对应的解。如果sign没有给出,则这组基是狭义基,不在B中的元素的L/U属性将按照对偶变量s的符号给出
'''
idxB,boolN,m = basis.idxB,basis.boolN,basis.m
## A^T \lambda + s = c, s_B = 0
lam = basis.solve(problem.c[idxB],if_transpose=True)
s = problem.c - basis.dot(lam,if_transpose=True)
s[idxB] = 0
if sign is None:
sign = VarStatus.OTHER.value * np.ones((m,),dtype=int)
sign[boolN & (s < 0)] = VarStatus.AT_UPPER_BOUND.value
sign[boolN & (s >= 0)] = VarStatus.AT_LOWER_BOUND.value
## A_B x_B + A_L x_L + A_U x_U = b, x_L = l_L, x_U = u_U
x = np.zeros((m,))
x[sign == VarStatus.AT_LOWER_BOUND.value] = problem.l[sign == VarStatus.AT_LOWER_BOUND.value]
x[sign == VarStatus.AT_UPPER_BOUND.value] = problem.u[sign == VarStatus.AT_UPPER_BOUND.value]
x[idxB] = basis.solve(problem.b - basis.dot(x,if_transpose=False),if_transpose=False)
sol = Solution(x,lam,s,sign)
return sol
def _refactorize(self,problem,sol,basis):
'''
重新做LU分解并计算解,降低数值误差
'''
try:
basis.lu_factorize()
except Exception as e:
print(e)
return problem,sol,basis
if sol is not None:
sol = self._compute_sol_from_basis(problem,basis,sign=sol.sign)
else:
sol = self._compute_sol_from_basis(problem,basis)
return problem,sol,basis
def _loop(self,problem,sol,basis):
'''
进行多步迭代,直到求解状态发生变化(非ONGOING)
加入对迭代步之间的管理
'''
count = self.global_info.get('count',0)
start_time = self.global_info.get('start_time',time.time())
while True:
if count % 5000 == 0 and count > 0:
print('resetting the DSE weights!')
basis.reset_DSE_weights() ## DSE更新
if basis.eta_count % 20 == 0 and count > 0:
basis.lu_factorize() ## LU分解
status,problem,sol,basis = self._step(problem,sol,basis) ## 做一步迭代
count += 1
self.global_info['count'] = count
header = '{} '.format(count)
## 每隔一定迭代步数观察效果
if ((count % 1000 == 0 and count > 0) and (status == SolveStatus.ONGOING)):
problem.check_sol_status(sol,print_func=print,print_header=header)
## 如果最优或者无解,abort
if status != SolveStatus.ONGOING:
problem.check_sol_status(sol,print_func=print,print_header=header)
return status,problem,sol,basis
## 限制迭代时长和次数
if time.time() - start_time > 9.0e2 or count > 1e5:
print('out of time / iterations.')
problem.check_sol_status(sol,print_func=print,print_header=header)
return SolveStatus.OTHER,problem,sol,basis
def _solve(self,problem,sol,basis):
## 直接进入DS迭代
return self._loop(problem,sol,basis)
def solve(self,A_raw,b_raw,sense_raw,c_raw,l_raw,u_raw):
'''
主求解入口
'''
self.global_info = {'count':0,'start_time':time.time()}
## 读取数据
A,b,sense,c,l,u = A_raw.copy(),b_raw.copy(),sense_raw.copy(),c_raw.copy(),l_raw.copy(),u_raw.copy()
n,m = A.shape
## 加上逻辑变量,保证A是满秩的;否则会出现数值问题
c = np.concatenate([c,np.zeros((n,))])
l = np.concatenate([l,np.zeros((n,))])
u = np.concatenate([u,np.zeros((n,))])
for colidx in range(n):
## 对非等式对应的逻辑变量加上上下界
if sense[colidx] == 1: ## G
l[m+colidx] = -INF
elif sense[colidx] == -1: ## L
u[m+colidx] = INF
A = sp.hstack([A,sp.eye(n)],format='csc')
## 初始化
problem = Problem(A,b,c,l,u)
n,m = A.shape
idxB = np.arange(m-n,m,1,dtype=int)
basis = Basis(A)
basis.init_DSE_weights()
basis.reset_basis_idx(idxB)
problem,sol,basis = self._refactorize(problem,sol=None,basis=basis)
## 开始求解流程
status,problem,sol,basis = self._solve(problem,sol,basis)
## 对原始变量的后处理,去除增加的逻辑变量
sol.x = sol.x[:(m-n)]
return status,sol,basis