Python is_linkedの例

コード例 #1

ファイル: conda_interface.py プロジェクト: tjd2002/conda-build

def which_package(path):
    """
    given the path (of a (presumably) conda installed file) iterate over
    the conda packages the file came from.  Usually the iteration yields
    only one package.
    """
    from os.path import abspath, join
    path = abspath(path)
    prefix = which_prefix(path)
    if prefix is None:
        raise RuntimeError("could not determine conda prefix from: %s" % path)
    for dist in linked(prefix):
        meta = is_linked(prefix, dist)
        if any(abspath(join(prefix, f)) == path for f in meta['files']):
            yield dist

コード例 #2

ファイル: conda_interface.py プロジェクト: mingwandroid/conda-build

def which_package(path):
    """
    given the path (of a (presumably) conda installed file) iterate over
    the conda packages the file came from.  Usually the iteration yields
    only one package.
    """
    from os.path import abspath, join
    path = abspath(path)
    prefix = which_prefix(path)
    if prefix is None:
        raise RuntimeError("could not determine conda prefix from: %s" % path)
    for dist in linked(prefix):
        meta = is_linked(prefix, dist)
        if any(abspath(join(prefix, f)) == path for f in meta['files']):
            yield dist