#!/usr/bin/python3

# -*- coding: utf-8 -*-

# Take the number 192 and multiply it by each of 1, 2, and 3:

# 192 × 1 = 192

# 192 × 2 = 384

# 192 × 3 = 576

# By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

# The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

# What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?

from functions import ispandigital

largest = 1

for p in range(1,10000):

n=''

q=1

while(len(n)<9):

n=n+''.join(str(p*q))

q += 1

if(len(n)==9 and ispandigital(int(n))==1):

largest=max(largest,int(n))

print(largest)