def lambdify(args, expr, modules=None, printer=None, use_imps=True, dummify=True): """ Returns a lambda function for fast calculation of numerical values. If not specified differently by the user, ``modules`` defaults to ``["numpy"]`` if NumPy is installed, and ``["math", "mpmath", "sympy"]`` if it isn't, that is, SymPy functions are replaced as far as possible by either ``numpy`` functions if available, and Python's standard library ``math``, or ``mpmath`` functions otherwise. To change this behavior, the "modules" argument can be used. It accepts: - the strings "math", "mpmath", "numpy", "numexpr", "sympy", "tensorflow" - any modules (e.g. math) - dictionaries that map names of sympy functions to arbitrary functions - lists that contain a mix of the arguments above, with higher priority given to entries appearing first. .. warning:: Note that this function uses ``eval``, and thus shouldn't be used on unsanitized input. The default behavior is to substitute all arguments in the provided expression with dummy symbols. This allows for applied functions (e.g. f(t)) to be supplied as arguments. Call the function with dummify=False if dummy substitution is unwanted (and `args` is not a string). If you want to view the lambdified function or provide "sympy" as the module, you should probably set dummify=False. For functions involving large array calculations, numexpr can provide a significant speedup over numpy. Please note that the available functions for numexpr are more limited than numpy but can be expanded with implemented_function and user defined subclasses of Function. If specified, numexpr may be the only option in modules. The official list of numexpr functions can be found at: https://github.com/pydata/numexpr#supported-functions In previous releases ``lambdify`` replaced ``Matrix`` with ``numpy.matrix`` by default. As of release 1.0 ``numpy.array`` is the default. To get the old default behavior you must pass in ``[{'ImmutableDenseMatrix': numpy.matrix}, 'numpy']`` to the ``modules`` kwarg. >>> from sympy import lambdify, Matrix >>> from sympy.abc import x, y >>> import numpy >>> array2mat = [{'ImmutableDenseMatrix': numpy.matrix}, 'numpy'] >>> f = lambdify((x, y), Matrix([x, y]), modules=array2mat) >>> f(1, 2) matrix([[1], [2]]) Usage ===== (1) Use one of the provided modules: >>> from sympy import sin, tan, gamma >>> from sympy.utilities.lambdify import lambdastr >>> from sympy.abc import x, y >>> f = lambdify(x, sin(x), "math") Attention: Functions that are not in the math module will throw a name error when the lambda function is evaluated! So this would be better: >>> f = lambdify(x, sin(x)*gamma(x), ("math", "mpmath", "sympy")) (2) Use some other module: >>> import numpy >>> f = lambdify((x,y), tan(x*y), numpy) Attention: There are naming differences between numpy and sympy. So if you simply take the numpy module, e.g. sympy.atan will not be translated to numpy.arctan. Use the modified module instead by passing the string "numpy": >>> f = lambdify((x,y), tan(x*y), "numpy") >>> f(1, 2) -2.18503986326 >>> from numpy import array >>> f(array([1, 2, 3]), array([2, 3, 5])) [-2.18503986 -0.29100619 -0.8559934 ] (3) Use a dictionary defining custom functions: >>> def my_cool_function(x): return 'sin(%s) is cool' % x >>> myfuncs = {"sin" : my_cool_function} >>> f = lambdify(x, sin(x), myfuncs); f(1) 'sin(1) is cool' Examples ======== >>> from sympy.utilities.lambdify import implemented_function >>> from sympy import sqrt, sin, Matrix >>> from sympy import Function >>> from sympy.abc import w, x, y, z >>> f = lambdify(x, x**2) >>> f(2) 4 >>> f = lambdify((x, y, z), [z, y, x]) >>> f(1,2,3) [3, 2, 1] >>> f = lambdify(x, sqrt(x)) >>> f(4) 2.0 >>> f = lambdify((x, y), sin(x*y)**2) >>> f(0, 5) 0.0 >>> row = lambdify((x, y), Matrix((x, x + y)).T, modules='sympy') >>> row(1, 2) Matrix([[1, 3]]) Tuple arguments are handled and the lambdified function should be called with the same type of arguments as were used to create the function.: >>> f = lambdify((x, (y, z)), x + y) >>> f(1, (2, 4)) 3 A more robust way of handling this is to always work with flattened arguments: >>> from sympy.utilities.iterables import flatten >>> args = w, (x, (y, z)) >>> vals = 1, (2, (3, 4)) >>> f = lambdify(flatten(args), w + x + y + z) >>> f(*flatten(vals)) 10 Functions present in `expr` can also carry their own numerical implementations, in a callable attached to the ``_imp_`` attribute. Usually you attach this using the ``implemented_function`` factory: >>> f = implemented_function(Function('f'), lambda x: x+1) >>> func = lambdify(x, f(x)) >>> func(4) 5 ``lambdify`` always prefers ``_imp_`` implementations to implementations in other namespaces, unless the ``use_imps`` input parameter is False. Usage with Tensorflow module: >>> import tensorflow as tf >>> f = Max(x, sin(x)) >>> func = lambdify(x, f, 'tensorflow') >>> result = func(tf.constant(1.0)) >>> result # a tf.Tensor representing the result of the calculation <tf.Tensor 'Maximum:0' shape=() dtype=float32> >>> sess = tf.Session() >>> sess.run(result) # compute result 1.0 >>> var = tf.Variable(1.0) >>> sess.run(tf.global_variables_initializer()) >>> sess.run(func(var)) # also works for tf.Variable and tf.Placeholder 1.0 >>> tensor = tf.constant([[1.0, 2.0], [3.0, 4.0]]) # works with any shape tensor >>> sess.run(func(tensor)) array([[ 1., 2.], [ 3., 4.]], dtype=float32) """ from sympy.core.symbol import Symbol from sympy.utilities.iterables import flatten # If the user hasn't specified any modules, use what is available. module_provided = True if modules is None: module_provided = False try: _import("numpy") except ImportError: # Use either numpy (if available) or python.math where possible. # XXX: This leads to different behaviour on different systems and # might be the reason for irreproducible errors. modules = ["math", "mpmath", "sympy"] else: modules = ["numpy"] # Get the needed namespaces. namespaces = [] # First find any function implementations if use_imps: namespaces.append(_imp_namespace(expr)) # Check for dict before iterating if isinstance(modules, (dict, str)) or not hasattr(modules, '__iter__'): namespaces.append(modules) else: # consistency check if _module_present('numexpr', modules) and len(modules) > 1: raise TypeError("numexpr must be the only item in 'modules'") namespaces += list(modules) # fill namespace with first having highest priority namespace = {} for m in namespaces[::-1]: buf = _get_namespace(m) namespace.update(buf) if hasattr(expr, "atoms"): #Try if you can extract symbols from the expression. #Move on if expr.atoms in not implemented. syms = expr.atoms(Symbol) for term in syms: namespace.update({str(term): term}) if printer is None: if _module_present('mpmath', namespaces): from sympy.printing.pycode import MpmathPrinter as Printer elif _module_present('numpy', namespaces): from sympy.printing.pycode import NumPyPrinter as Printer elif _module_present('numexpr', namespaces): from sympy.printing.lambdarepr import NumExprPrinter as Printer elif _module_present('tensorflow', namespaces): from sympy.printing.lambdarepr import TensorflowPrinter as Printer elif _module_present('sympy', namespaces): from sympy.printing.pycode import SymPyPrinter as Printer else: from sympy.printing.pycode import PythonCodePrinter as Printer user_functions = {} for m in namespaces[::-1]: if isinstance(m, dict): for k in m: user_functions[k] = k printer = Printer({ 'fully_qualified_modules': False, 'inline': True, 'user_functions': user_functions }) # Get the names of the args, for creating a docstring if not iterable(args): args = (args, ) names = [] # Grab the callers frame, for getting the names by inspection (if needed) callers_local_vars = inspect.currentframe().f_back.f_locals.items() for n, var in enumerate(args): if hasattr(var, 'name'): names.append(var.name) else: # It's an iterable. Try to get name by inspection of calling frame. name_list = [ var_name for var_name, var_val in callers_local_vars if var_val is var ] if len(name_list) == 1: names.append(name_list[0]) else: # Cannot infer name with certainty. arg_# will have to do. names.append('arg_' + str(n)) # Create lambda function. lstr = lambdastr(args, expr, printer=printer, dummify=dummify) flat = '__flatten_args__' imp_mod_lines = [] for mod, keys in (getattr(printer, 'module_imports', None) or {}).items(): for k in keys: if k not in namespace: imp_mod_lines.append("from %s import %s" % (mod, k)) for ln in imp_mod_lines: exec_(ln, {}, namespace) if flat in lstr: namespace.update({flat: flatten}) # Provide lambda expression with builtins, and compatible implementation of range namespace.update({'builtins': builtins, 'range': range}) func = eval(lstr, namespace) # For numpy lambdify, wrap all input arguments in arrays. # This is a fix for gh-11306. if module_provided and _module_present('numpy', namespaces): def array_wrap(funcarg): @wraps(funcarg) def wrapper(*argsx, **kwargsx): asarray = namespace['asarray'] newargs = [ asarray(i) if isinstance(i, integer_types + (float, complex)) else i for i in argsx ] return funcarg(*newargs, **kwargsx) return wrapper func = array_wrap(func) # Apply the docstring sig = "func({0})".format(", ".join(str(i) for i in names)) sig = textwrap.fill(sig, subsequent_indent=' ' * 8) expr_str = str(expr) if len(expr_str) > 78: expr_str = textwrap.wrap(expr_str, 75)[0] + '...' func.__doc__ = ("Created with lambdify. Signature:\n\n" "{sig}\n\n" "Expression:\n\n" "{expr}\n\n" "Source code:\n\n" "{src}\n\n" "Imported modules:\n\n" "{imp_mods}").format(sig=sig, expr=expr_str, src=lstr, imp_mods='\n'.join(imp_mod_lines)) return func
def lambdify(args, expr, modules=None, printer=None, use_imps=True, dummify=False): """ Translates a SymPy expression into an equivalent numeric function For example, to convert the SymPy expression ``sin(x) + cos(x)`` to an equivalent NumPy function that numerically evaluates it: >>> from sympy import sin, cos, symbols, lambdify >>> import numpy as np >>> x = symbols('x') >>> expr = sin(x) + cos(x) >>> expr sin(x) + cos(x) >>> f = lambdify(x, expr, 'numpy') >>> a = np.array([1, 2]) >>> f(a) [1.38177329 0.49315059] The primary purpose of this function is to provide a bridge from SymPy expressions to numerical libraries such as NumPy, SciPy, NumExpr, mpmath, and tensorflow. In general, SymPy functions do not work with objects from other libraries, such as NumPy arrays, and functions from numeric libraries like NumPy or mpmath do not work on SymPy expressions. ``lambdify`` bridges the two by converting a SymPy expression to an equivalent numeric function. The basic workflow with ``lambdify`` is to first create a SymPy expression representing whatever mathematical function you wish to evaluate. This should be done using only SymPy functions and expressions. Then, use ``lambdify`` to convert this to an equivalent function for numerical evaluation. For instance, above we created ``expr`` using the SymPy symbol ``x`` and SymPy functions ``sin`` and ``cos``, then converted it to an equivalent NumPy function ``f``, and called it on a NumPy array ``a``. .. warning:: This function uses ``exec``, and thus shouldn't be used on unsanitized input. Arguments ========= The first argument of ``lambdify`` is a variable or list of variables in the expression. Variable lists may be nested. Variables can be Symbols, undefined functions, or matrix symbols. The order and nesting of the variables corresponds to the order and nesting of the parameters passed to the lambdified function. For instance, >>> from sympy.abc import x, y, z >>> f = lambdify([x, (y, z)], x + y + z) >>> f(1, (2, 3)) 6 The second argument of ``lambdify`` is the expression, list of expressions, or matrix to be evaluated. Lists may be nested. If the expression is a list, the output will also be a list. >>> f = lambdify(x, [x, [x + 1, x + 2]]) >>> f(1) [1, [2, 3]] If it is a matrix, an array will be returned (for the NumPy module). >>> from sympy import Matrix >>> f = lambdify(x, Matrix([x, x + 1])) >>> f(1) [[1] [2]] Note that the argument order here, variables then expression, is used to emulate the Python ``lambda`` keyword. ``lambdify(x, expr)`` works (roughly) like ``lambda x: expr`` (see :ref:`lambdify-how-it-works` below). The third argument, ``modules`` is optional. If not specified, ``modules`` defaults to ``["scipy", "numpy"]`` if SciPy is installed, ``["numpy"]`` if only NumPy is installed, and ``["math", "mpmath", "sympy"]`` if neither is installed. That is, SymPy functions are replaced as far as possible by either ``scipy`` or ``numpy`` functions if available, and Python's standard library ``math``, or ``mpmath`` functions otherwise. ``modules`` can be one of the following types - the strings ``"math"``, ``"mpmath"``, ``"numpy"``, ``"numexpr"``, ``"scipy"``, ``"sympy"``, or ``"tensorflow"``. This uses the corresponding printer and namespace mapping for that module. - a module (e.g., ``math``). This uses the global namespace of the module. If the module is one of the above known modules, it will also use the corresponding printer and namespace mapping (i.e., ``modules=numpy`` is equivalent to ``modules="numpy"``). - a dictionary that maps names of SymPy functions to arbitrary functions (e.g., ``{'sin': custom_sin}``). - a list that contains a mix of the arguments above, with higher priority given to entries appearing first (e.g., to use the NumPy module but override the ``sin`` function with a custom version, you can use ``[{'sin': custom_sin}, 'numpy']``). The ``dummify`` keyword argument controls whether or not the variables in the provided expression that are not valid Python identifiers are substituted with dummy symbols. This allows for undefined functions like ``Function('f')(t)`` to be supplied as arguments. By default, the variables are only dummified if they are not valid Python identifiers. Set ``dummify=True`` to replace all arguments with dummy symbols (if ``args`` is not a string) - for example, to ensure that the arguments do not redefine any built-in names. .. _lambdify-how-it-works: How it works ============ When using this function, it helps a great deal to have an idea of what it is doing. At its core, lambdify is nothing more than a namespace translation, on top of a special printer that makes some corner cases work properly. To understand lambdify, first we must properly understand how Python namespaces work. Say we had two files. One called ``sin_cos_sympy.py``, with .. code:: python # sin_cos_sympy.py from sympy import sin, cos def sin_cos(x): return sin(x) + cos(x) and one called ``sin_cos_numpy.py`` with .. code:: python # sin_cos_numpy.py from numpy import sin, cos def sin_cos(x): return sin(x) + cos(x) The two files define an identical function ``sin_cos``. However, in the first file, ``sin`` and ``cos`` are defined as the SymPy ``sin`` and ``cos``. In the second, they are defined as the NumPy versions. If we were to import the first file and use the ``sin_cos`` function, we would get something like >>> from sin_cos_sympy import sin_cos # doctest: +SKIP >>> sin_cos(1) # doctest: +SKIP cos(1) + sin(1) On the other hand, if we imported ``sin_cos`` from the second file, we would get >>> from sin_cos_numpy import sin_cos # doctest: +SKIP >>> sin_cos(1) # doctest: +SKIP 1.38177329068 In the first case we got a symbolic output, because it used the symbolic ``sin`` and ``cos`` functions from SymPy. In the second, we got a numeric result, because ``sin_cos`` used the numeric ``sin`` and ``cos`` functions from NumPy. But notice that the versions of ``sin`` and ``cos`` that were used was not inherent to the ``sin_cos`` function definition. Both ``sin_cos`` definitions are exactly the same. Rather, it was based on the names defined at the module where the ``sin_cos`` function was defined. The key point here is that when function in Python references a name that is not defined in the function, that name is looked up in the "global" namespace of the module where that function is defined. Now, in Python, we can emulate this behavior without actually writing a file to disk using the ``exec`` function. ``exec`` takes a string containing a block of Python code, and a dictionary that should contain the global variables of the module. It then executes the code "in" that dictionary, as if it were the module globals. The following is equivalent to the ``sin_cos`` defined in ``sin_cos_sympy.py``: >>> import sympy >>> module_dictionary = {'sin': sympy.sin, 'cos': sympy.cos} >>> exec(''' ... def sin_cos(x): ... return sin(x) + cos(x) ... ''', module_dictionary) >>> sin_cos = module_dictionary['sin_cos'] >>> sin_cos(1) cos(1) + sin(1) and similarly with ``sin_cos_numpy``: >>> import numpy >>> module_dictionary = {'sin': numpy.sin, 'cos': numpy.cos} >>> exec(''' ... def sin_cos(x): ... return sin(x) + cos(x) ... ''', module_dictionary) >>> sin_cos = module_dictionary['sin_cos'] >>> sin_cos(1) 1.38177329068 So now we can get an idea of how ``lambdify`` works. The name "lambdify" comes from the fact that we can think of something like ``lambdify(x, sin(x) + cos(x), 'numpy')`` as ``lambda x: sin(x) + cos(x)``, where ``sin`` and ``cos`` come from the ``numpy`` namespace. This is also why the symbols argument is first in ``lambdify``, as opposed to most SymPy functions where it comes after the expression: to better mimic the ``lambda`` keyword. ``lambdify`` takes the input expression (like ``sin(x) + cos(x)``) and 1. Converts it to a string 2. Creates a module globals dictionary based on the modules that are passed in (by default, it uses the NumPy module) 3. Creates the string ``"def func({vars}): return {expr}"``, where ``{vars}`` is the list of variables separated by commas, and ``{expr}`` is the string created in step 1., then ``exec``s that string with the module globals namespace and returns ``func``. In fact, functions returned by ``lambdify`` support inspection. So you can see exactly how they are defined by using ``inspect.getsource``, or ``??`` if you are using IPython or the Jupyter notebook. >>> f = lambdify(x, sin(x) + cos(x)) >>> import inspect >>> print(inspect.getsource(f)) def _lambdifygenerated(x): return (sin(x) + cos(x)) This shows us the source code of the function, but not the namespace it was defined in. We can inspect that by looking at the ``__globals__`` attribute of ``f``: >>> f.__globals__['sin'] <ufunc 'sin'> >>> f.__globals__['cos'] <ufunc 'cos'> >>> f.__globals__['sin'] is numpy.sin True This shows us that ``sin`` and ``cos`` in the namespace of ``f`` will be ``numpy.sin`` and ``numpy.cos``. Note that there are some convenience layers in each of these steps, but at the core, this is how ``lambdify`` works. Step 1 is done using the ``LambdaPrinter`` printers defined in the printing module (see :mod:`sympy.printing.lambdarepr`). This allows different SymPy expressions to define how they should be converted to a string for different modules. You can change which printer ``lambdify`` uses by passing a custom printer in to the ``printer`` argument. Step 2 is augmented by certain translations. There are default translations for each module, but you can provide your own by passing a list to the ``modules`` argument. For instance, >>> def mysin(x): ... print('taking the sin of', x) ... return numpy.sin(x) ... >>> f = lambdify(x, sin(x), [{'sin': mysin}, 'numpy']) >>> f(1) taking the sin of 1 0.8414709848078965 The globals dictionary is generated from the list by merging the dictionary ``{'sin': mysin}`` and the module dictionary for NumPy. The merging is done so that earlier items take precedence, which is why ``mysin`` is used above instead of ``numpy.sin``. If you want to modify the way ``lambdify`` works for a given function, it is usually easiest to do so by modifying the globals dictionary as such. In more complicated cases, it may be necessary to create and pass in a custom printer. Finally, step 3 is augmented with certain convenience operations, such as the addition of a docstring. Understanding how ``lambdify`` works can make it easier to avoid certain gotchas when using it. For instance, a common mistake is to create a lambdified function for one module (say, NumPy), and pass it objects from another (say, a SymPy expression). For instance, say we create >>> from sympy.abc import x >>> f = lambdify(x, x + 1, 'numpy') Now if we pass in a NumPy array, we get that array plus 1 >>> import numpy >>> a = numpy.array([1, 2]) >>> f(a) [2 3] But what happens if you make the mistake of passing in a SymPy expression instead of a NumPy array: >>> f(x + 1) x + 2 This worked, but it was only by accident. Now take a different lambdified function: >>> from sympy import sin >>> g = lambdify(x, x + sin(x), 'numpy') This works as expected on NumPy arrays: >>> g(a) [1.84147098 2.90929743] But if we try to pass in a SymPy expression, it fails >>> try: ... g(x + 1) ... # NumPy release after 1.17 raises TypeError instead of ... # AttributeError ... except (AttributeError, TypeError): ... raise AttributeError() # doctest: +IGNORE_EXCEPTION_DETAIL Traceback (most recent call last): ... AttributeError: Now, let's look at what happened. The reason this fails is that ``g`` calls ``numpy.sin`` on the input expression, and ``numpy.sin`` does not know how to operate on a SymPy object. **As a general rule, NumPy functions do not know how to operate on SymPy expressions, and SymPy functions do not know how to operate on NumPy arrays. This is why lambdify exists: to provide a bridge between SymPy and NumPy.** However, why is it that ``f`` did work? That's because ``f`` doesn't call any functions, it only adds 1. So the resulting function that is created, ``def _lambdifygenerated(x): return x + 1`` does not depend on the globals namespace it is defined in. Thus it works, but only by accident. A future version of ``lambdify`` may remove this behavior. Be aware that certain implementation details described here may change in future versions of SymPy. The API of passing in custom modules and printers will not change, but the details of how a lambda function is created may change. However, the basic idea will remain the same, and understanding it will be helpful to understanding the behavior of lambdify. **In general: you should create lambdified functions for one module (say, NumPy), and only pass it input types that are compatible with that module (say, NumPy arrays).** Remember that by default, if the ``module`` argument is not provided, ``lambdify`` creates functions using the NumPy and SciPy namespaces. Examples ======== >>> from sympy.utilities.lambdify import implemented_function >>> from sympy import sqrt, sin, Matrix >>> from sympy import Function >>> from sympy.abc import w, x, y, z >>> f = lambdify(x, x**2) >>> f(2) 4 >>> f = lambdify((x, y, z), [z, y, x]) >>> f(1,2,3) [3, 2, 1] >>> f = lambdify(x, sqrt(x)) >>> f(4) 2.0 >>> f = lambdify((x, y), sin(x*y)**2) >>> f(0, 5) 0.0 >>> row = lambdify((x, y), Matrix((x, x + y)).T, modules='sympy') >>> row(1, 2) Matrix([[1, 3]]) ``lambdify`` can be used to translate SymPy expressions into mpmath functions. This may be preferable to using ``evalf`` (which uses mpmath on the backend) in some cases. >>> import mpmath >>> f = lambdify(x, sin(x), 'mpmath') >>> f(1) 0.8414709848078965 Tuple arguments are handled and the lambdified function should be called with the same type of arguments as were used to create the function: >>> f = lambdify((x, (y, z)), x + y) >>> f(1, (2, 4)) 3 The ``flatten`` function can be used to always work with flattened arguments: >>> from sympy.utilities.iterables import flatten >>> args = w, (x, (y, z)) >>> vals = 1, (2, (3, 4)) >>> f = lambdify(flatten(args), w + x + y + z) >>> f(*flatten(vals)) 10 Functions present in ``expr`` can also carry their own numerical implementations, in a callable attached to the ``_imp_`` attribute. This can be used with undefined functions using the ``implemented_function`` factory: >>> f = implemented_function(Function('f'), lambda x: x+1) >>> func = lambdify(x, f(x)) >>> func(4) 5 ``lambdify`` always prefers ``_imp_`` implementations to implementations in other namespaces, unless the ``use_imps`` input parameter is False. Usage with Tensorflow: >>> import tensorflow as tf >>> from sympy import Max, sin, lambdify >>> from sympy.abc import x >>> f = Max(x, sin(x)) >>> func = lambdify(x, f, 'tensorflow') After tensorflow v2, eager execution is enabled by default. If you want to get the compatible result across tensorflow v1 and v2 as same as this tutorial, run this line. >>> tf.compat.v1.enable_eager_execution() If you have eager execution enabled, you can get the result out immediately as you can use numpy. If you pass tensorflow objects, you may get an ``EagerTensor`` object instead of value. >>> result = func(tf.constant(1.0)) >>> print(result) tf.Tensor(1.0, shape=(), dtype=float32) >>> print(result.__class__) <class 'tensorflow.python.framework.ops.EagerTensor'> You can use ``.numpy()`` to get the numpy value of the tensor. >>> result.numpy() 1.0 >>> var = tf.Variable(2.0) >>> result = func(var) # also works for tf.Variable and tf.Placeholder >>> result.numpy() 2.0 And it works with any shape array. >>> tensor = tf.constant([[1.0, 2.0], [3.0, 4.0]]) >>> result = func(tensor) >>> result.numpy() [[1. 2.] [3. 4.]] Notes ===== - For functions involving large array calculations, numexpr can provide a significant speedup over numpy. Please note that the available functions for numexpr are more limited than numpy but can be expanded with ``implemented_function`` and user defined subclasses of Function. If specified, numexpr may be the only option in modules. The official list of numexpr functions can be found at: https://numexpr.readthedocs.io/en/latest/user_guide.html#supported-functions - In previous versions of SymPy, ``lambdify`` replaced ``Matrix`` with ``numpy.matrix`` by default. As of SymPy 1.0 ``numpy.array`` is the default. To get the old default behavior you must pass in ``[{'ImmutableDenseMatrix': numpy.matrix}, 'numpy']`` to the ``modules`` kwarg. >>> from sympy import lambdify, Matrix >>> from sympy.abc import x, y >>> import numpy >>> array2mat = [{'ImmutableDenseMatrix': numpy.matrix}, 'numpy'] >>> f = lambdify((x, y), Matrix([x, y]), modules=array2mat) >>> f(1, 2) [[1] [2]] - In the above examples, the generated functions can accept scalar values or numpy arrays as arguments. However, in some cases the generated function relies on the input being a numpy array: >>> from sympy import Piecewise >>> from sympy.utilities.pytest import ignore_warnings >>> f = lambdify(x, Piecewise((x, x <= 1), (1/x, x > 1)), "numpy") >>> with ignore_warnings(RuntimeWarning): ... f(numpy.array([-1, 0, 1, 2])) [-1. 0. 1. 0.5] >>> f(0) Traceback (most recent call last): ... ZeroDivisionError: division by zero In such cases, the input should be wrapped in a numpy array: >>> with ignore_warnings(RuntimeWarning): ... float(f(numpy.array([0]))) 0.0 Or if numpy functionality is not required another module can be used: >>> f = lambdify(x, Piecewise((x, x <= 1), (1/x, x > 1)), "math") >>> f(0) 0 """ from sympy.core.symbol import Symbol # If the user hasn't specified any modules, use what is available. if modules is None: try: _import("scipy") except ImportError: try: _import("numpy") except ImportError: # Use either numpy (if available) or python.math where possible. # XXX: This leads to different behaviour on different systems and # might be the reason for irreproducible errors. modules = ["math", "mpmath", "sympy"] else: modules = ["numpy"] else: modules = ["numpy", "scipy"] # Get the needed namespaces. namespaces = [] # First find any function implementations if use_imps: namespaces.append(_imp_namespace(expr)) # Check for dict before iterating if isinstance(modules, (dict, string_types)) or not hasattr(modules, '__iter__'): namespaces.append(modules) else: # consistency check if _module_present('numexpr', modules) and len(modules) > 1: raise TypeError("numexpr must be the only item in 'modules'") namespaces += list(modules) # fill namespace with first having highest priority namespace = {} for m in namespaces[::-1]: buf = _get_namespace(m) namespace.update(buf) if hasattr(expr, "atoms"): #Try if you can extract symbols from the expression. #Move on if expr.atoms in not implemented. syms = expr.atoms(Symbol) for term in syms: namespace.update({str(term): term}) if printer is None: if _module_present('mpmath', namespaces): from sympy.printing.pycode import MpmathPrinter as Printer elif _module_present('scipy', namespaces): from sympy.printing.pycode import SciPyPrinter as Printer elif _module_present('numpy', namespaces): from sympy.printing.pycode import NumPyPrinter as Printer elif _module_present('numexpr', namespaces): from sympy.printing.lambdarepr import NumExprPrinter as Printer elif _module_present('tensorflow', namespaces): from sympy.printing.tensorflow import TensorflowPrinter as Printer elif _module_present('sympy', namespaces): from sympy.printing.pycode import SymPyPrinter as Printer else: from sympy.printing.pycode import PythonCodePrinter as Printer user_functions = {} for m in namespaces[::-1]: if isinstance(m, dict): for k in m: user_functions[k] = k printer = Printer({ 'fully_qualified_modules': False, 'inline': True, 'allow_unknown_functions': True, 'user_functions': user_functions }) # Get the names of the args, for creating a docstring if not iterable(args): args = (args, ) names = [] # Grab the callers frame, for getting the names by inspection (if needed) callers_local_vars = inspect.currentframe().f_back.f_locals.items() for n, var in enumerate(args): if hasattr(var, 'name'): names.append(var.name) else: # It's an iterable. Try to get name by inspection of calling frame. name_list = [ var_name for var_name, var_val in callers_local_vars if var_val is var ] if len(name_list) == 1: names.append(name_list[0]) else: # Cannot infer name with certainty. arg_# will have to do. names.append('arg_' + str(n)) # Create the function definition code and execute it funcname = '_lambdifygenerated' if _module_present('tensorflow', namespaces): funcprinter = _TensorflowEvaluatorPrinter(printer, dummify) else: funcprinter = _EvaluatorPrinter(printer, dummify) funcstr = funcprinter.doprint(funcname, args, expr) # Collect the module imports from the code printers. imp_mod_lines = [] for mod, keys in (getattr(printer, 'module_imports', None) or {}).items(): for k in keys: if k not in namespace: ln = "from %s import %s" % (mod, k) try: exec_(ln, {}, namespace) except ImportError: # Tensorflow 2.0 has issues with importing a specific # function from its submodule. # https://github.com/tensorflow/tensorflow/issues/33022 ln = "%s = %s.%s" % (k, mod, k) exec_(ln, {}, namespace) imp_mod_lines.append(ln) # Provide lambda expression with builtins, and compatible implementation of range namespace.update({'builtins': builtins, 'range': range}) funclocals = {} global _lambdify_generated_counter filename = '<lambdifygenerated-%s>' % _lambdify_generated_counter _lambdify_generated_counter += 1 c = compile(funcstr, filename, 'exec') exec_(c, namespace, funclocals) # mtime has to be None or else linecache.checkcache will remove it linecache.cache[filename] = (len(funcstr), None, funcstr.splitlines(True), filename) func = funclocals[funcname] # Apply the docstring sig = "func({0})".format(", ".join(str(i) for i in names)) sig = textwrap.fill(sig, subsequent_indent=' ' * 8) expr_str = str(expr) if len(expr_str) > 78: expr_str = textwrap.wrap(expr_str, 75)[0] + '...' func.__doc__ = ("Created with lambdify. Signature:\n\n" "{sig}\n\n" "Expression:\n\n" "{expr}\n\n" "Source code:\n\n" "{src}\n\n" "Imported modules:\n\n" "{imp_mods}").format(sig=sig, expr=expr_str, src=funcstr, imp_mods='\n'.join(imp_mod_lines)) return func