def find_sn_pos(phrase, begin_pos):
"""
We will find the nominal group which is in a known position
We have to use adjective_pos to return the end position of nominal group
Input=the sentence (list of strings) and the position of the nominal group
Output=the nominal group
"""
if begin_pos >= len(phrase):
return []
end_pos = 1
#If it is a pronoun
if phrase[begin_pos] in ResourcePool().pronouns:
return [phrase[begin_pos]]
#If there is a nominal group with determinant
if phrase[begin_pos] in ResourcePool().determinants:
end_pos += adjective_pos(phrase, begin_pos + 1)
return phrase[begin_pos:end_pos + begin_pos]
#If we have 'something'
for k in ResourcePool().composed_nouns:
if phrase[begin_pos].startswith(k):
if phrase[begin_pos] in ResourcePool().noun_not_composed:
return []
return [phrase[begin_pos]]
#If there is a number, it will be the same with determinant
if other_functions.number(phrase[begin_pos]) == 1:
end_pos += adjective_pos(phrase, begin_pos + 1)
return phrase[begin_pos:end_pos + begin_pos]
#If it is a proper name
counter = begin_pos
while counter < len(phrase) and other_functions.find_cap_lettre(
phrase[counter]) == 1:
counter += 1
#Default case return [] => ok if counter=begin_pos
return phrase[begin_pos:counter]
def find_sn_pos(phrase, begin_pos):
"""
We will find the nominal group which is in a known position
We have to use adjective_pos to return the end position of nominal group
Input=the sentence (list of strings) and the position of the nominal group
Output=the nominal group
"""
if begin_pos >= len(phrase):
return []
end_pos = 1
#If it is a pronoun
if phrase[begin_pos] in ResourcePool().pronouns:
return [phrase[begin_pos]]
#If there is a nominal group with determinant
if phrase[begin_pos] in ResourcePool().determinants:
end_pos += adjective_pos(phrase, begin_pos + 1)
return phrase[begin_pos: end_pos + begin_pos]
#If we have 'something'
for k in ResourcePool().composed_nouns:
if phrase[begin_pos].startswith(k):
if phrase[begin_pos] in ResourcePool().noun_not_composed:
return []
return [phrase[begin_pos]]
#If there is a number, it will be the same with determinant
if other_functions.number(phrase[begin_pos]) == 1:
end_pos += adjective_pos(phrase, begin_pos + 1)
return phrase[begin_pos: end_pos + begin_pos]
#If it is a proper name
counter = begin_pos
while counter < len(phrase) and other_functions.find_cap_lettre(phrase[counter]) == 1:
counter += 1
#Default case return [] => ok if counter=begin_pos
return phrase[begin_pos: counter]
def adjective_pos(phrase, word_pos):
"""
returns the position of the end of the nominal group
We have to use the list of irregular adjectives
Input=the sentence (list of strings) and the position of the first adjective
Output=the position of the last word of the nominal group
"""
#If it is the end of the phrase
if len(phrase) - 1 <= word_pos:
return 1
#The case of '2 of them'
if phrase[word_pos] == 'of':
return 0
#It is a noun so we have to return 1
if phrase[word_pos] in ResourcePool().special_nouns:
return 1
#For the regular adjectives
for k in ResourcePool().adjective_rules:
if phrase[word_pos].endswith(k):
return 1 + adjective_pos(phrase, word_pos + 1)
#For adjectives created from numbers
if phrase[word_pos].endswith('th') and other_functions.number(
phrase[word_pos]) == 2:
return 1 + adjective_pos(phrase, word_pos + 1)
#We use the irregular adjectives list to find it
if phrase[word_pos] in list(ResourcePool().adjectives.keys(
)) + ResourcePool().adjective_numbers + ResourcePool().adj_quantifiers:
return 1 + adjective_pos(phrase, word_pos + 1)
#Default case
return 1
def adjective_pos(phrase, word_pos):
"""
returns the position of the end of the nominal group
We have to use the list of irregular adjectives
Input=the sentence (list of strings) and the position of the first adjective
Output=the position of the last word of the nominal group
"""
#If it is the end of the phrase
if len(phrase) - 1 <= word_pos:
return 1
#The case of '2 of them'
if phrase[word_pos] == 'of':
return 0
#It is a noun so we have to return 1
if phrase[word_pos] in ResourcePool().special_nouns:
return 1
#For the regular adjectives
for k in ResourcePool().adjective_rules:
if phrase[word_pos].endswith(k):
return 1 + adjective_pos(phrase, word_pos + 1)
#For adjectives created from numbers
if phrase[word_pos].endswith('th') and other_functions.number(phrase[word_pos]) == 2:
return 1 + adjective_pos(phrase, word_pos + 1)
#We use the irregular adjectives list to find it
if phrase[word_pos] in list(
ResourcePool().adjectives.keys()) + ResourcePool().adjective_numbers + ResourcePool().adj_quantifiers:
return 1 + adjective_pos(phrase, word_pos + 1)
#Default case
return 1
