def hackAffine(message):
print 'Hacking...'
# Python programs can be stopped at any time by pressing Ctrl-C (on
# Windows) or Ctrl-D (on Mac and Linux)
print '(Press Ctrl-C or Ctrl-D to quit at any time.)'
# brute-force by looping through every possible key
for key in range(len(affineCipherAbhi.SYMBOLS) ** 2):
keyA = affineCipherAbhi.getKeyParts(key)[0]
if Euclid_Algorithm.find_gcf(keyA, len(affineCipherAbhi.SYMBOLS)) != 1:
continue
decryptedText = affineCipherAbhi.decryptMessage(key, message)
if not SILENT_MODE:
print('Tried Key %s... (%s)' % (key, decryptedText[:40]))
if detectEnglish.isEnglish(decryptedText):
# Check with the user if the decrypted key has been found.
print
print 'Possible encryption hack:'
print 'Key: %s' % (key)
print 'Decrypted message: ' + decryptedText[:200]
print
print 'Enter D for done, or just press Enter to continue hacking:'
response = raw_input('> ')
if response.strip().upper().startswith('D'):
return decryptedText
return None
def getRandomKey():
while True:
keyA = random.randint(2, len(SYMBOLS))
keyB = random.randint(2, len(SYMBOLS))
if Euclid_Algorithm.find_gcf(keyA, len(SYMBOLS) -1) == 1:
return keyA * len(SYMBOLS) + keyB
def checkKeys(keyA, keyB, mode):
if keyA == 1 and mode == 'encrypt':
# this is due to the index being multiplied by keyA (1)
sys.exit('The affine cipher becomes incredibly weak when key A is \
set to 1. Choose a different key.')
if keyB == 0 and mode == 'encrypt':
# this is due to the index being added by keyB (0)
sys.exit('The affine cipher becomes incredibly weak when key B is \
set to 0. Choose a different key.')
if keyA < 0 or keyB < 0 or keyB > len(SYMBOLS) - 1:
sys.exit('Key A must be greater than 0 and Key B must be between 0 \
and %s.' % (len(SYMBOLS) - 1))
if Euclid_Algorithm.find_gcf(keyA, len(SYMBOLS)) != 1:
sys.exit('Key A (%s) and the symbol set size (%s) are not \
relatively prime. Choose a different key.' % (keyA, len(SYMBOLS)))
# Inspired by Hacking with Ciphers Al Sweigart's book
# This program proves that the keyspace of the affine cipher is limited
# to len(SYMBOLS) ^ 2. (in theory)
# len(symbols) for key A and len(symbols) for key B
# in reality, we also discard some of the sample space for its incompatibility of being relatively prime
import affineCipherAbhi, Euclid_Algorithm
message = 'Make things as simple as possible, but not simpler.'
for keyA in range(2, 100):
key = keyA * len(affineCipherAbhi.SYMBOLS) + 1# 1 represents keyB
if Euclid_Algorithm.find_gcf(keyA, len(affineCipherAbhi.SYMBOLS)) == 1:
print keyA, affineCipherAbhi.encryptMessage(key, message)