Beispiel #1
0
class Solution:
    def subtreeWithAllDeepest(self, root: TreeNode) -> TreeNode:
        def dfs(root: TreeNode) -> (TreeNode, int):
            if root is None:
                return root, 0
            L = dfs(root.left)
            R = dfs(root.right)
            if L[1] > R[1]:
                return L[0], L[1] + 1
            if R[1] > L[1]:
                return R[0], R[1] + 1
            return root, L[1] + 1

        return dfs(root)[0]


root = TreeNode(3)
root.left = TreeNode(5)
root.left.left = TreeNode(6)
root.left.right = TreeNode(2)
root.left.right.left = TreeNode(7)
root.left.right.right = TreeNode(4)
root.right = TreeNode(1)
root.right.left = TreeNode(0)
root.right.right = TreeNode(8)

tests = [(root, TreeNode(2, TreeNode(7), TreeNode(4)))]

run_functional_tests(Solution().subtreeWithAllDeepest, tests)
Beispiel #2
0
"""
class Solution:
    def hasPathSum(self, root: TreeNode, sum: int) -> bool:
        if root is None:
            return False
        if root.left is None and root.right is None:
            return sum == root.val
        if self.hasPathSum(root.left, sum - root.val):
            return True
        return self.hasPathSum(root.right, sum - root.val)


t1 = TreeNode(5)
t1.left = TreeNode(4)
t1.right = TreeNode(8)

t1.left.left = TreeNode(11)
t1.left.left.left = TreeNode(7)
t1.left.left.right = TreeNode(2)

t1.right.left = TreeNode(13)
t1.right.right = TreeNode(4)

t1.right.right.right = TreeNode(1)

tests = [
    (t1, 22, True)
]

run_functional_tests(Solution().hasPathSum, tests)
Beispiel #3
0
from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 3688 ms, faster than 44.27% of Python3 online submissions for Ones and Zeroes.
# Memory Usage: 14.3 MB, less than 95.49% of Python3 online submissions for Ones and Zeroes.
class Solution:
    def findMaxForm(self, strs: List[str], m: int, n: int) -> int:
        c = len(strs)
        dp = [[0] * (n + 1) for _ in range(m + 1)]

        def count(si: str) -> List[int]:
            res = [0, 0]
            for t in si:
                res[ord(t) - ord('0')] += 1
            return res

        for si in strs:
            ci = count(si)
            for i in range(m, ci[0] - 1, -1):
                for j in range(n, ci[1] - 1, -1):
                    dp[i][j] = max(dp[i][j], dp[i - ci[0]][j - ci[1]] + 1)

        return dp[m][n]


tests = [(["10", "0001", "111001", "1", "0"], 5, 3, 4),
         (["10", "0", "1"], 1, 1, 2)]

run_functional_tests(Solution().findMaxForm, tests)
        prev, first, second = None, None, None

        def inorder(node: TreeNode):
            nonlocal prev, first, second
            if node.left:
                inorder(node.left)

            if not first and (not prev or node.val < prev.val):
                first = prev
            if first and (not prev or node.val < prev.val):
                second = node

            prev = node
            if node.right:
                inorder(node.right)

        inorder(root)
        first.val, second.val = second.val, first.val


tests = [[
    TreeNode(1, TreeNode(3, null, TreeNode(2))),
    TreeNode(3, TreeNode(1, null, TreeNode(2)))
],
         [
             TreeNode(3, TreeNode(1), TreeNode(4, TreeNode(2))),
             TreeNode(2, TreeNode(1), TreeNode(4, TreeNode(3)))
         ]]

run_functional_tests(in_place_to_function(Solution().recoverTree), tests)
Beispiel #5
0
Memory Usage: 14.8 MB, less than 56.27% of Python3 online submissions for Burst Balloons.
"""
from typing import List

from Common.ObjectTestingUtils import run_functional_tests


class Solution:
    def maxCoins(self, nums: List[int]) -> int:
        A = [1] + nums + [1]
        n = len(A)
        dp: List[List[int]] = [[0] * n for i in range(n)]

        for l in range(n+1):
            for i in range(n-l):
                mx = 0
                j = i + l
                for k in range(i+1, j):
                    v = A[i] * A[k] * A[j] + dp[i][k] + dp[k][j]
                    mx = max(mx, v)
                dp[i][j] = mx

        return dp[0][n-1]


tests = [
    ([3,1,5,8], 167)
]

run_functional_tests(Solution().maxCoins, tests)
Beispiel #6
0
path[i] is either 'N', 'S', 'E', or 'W'.
"""
from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 60 ms, faster than 5.75% of Python3 online submissions for Path Crossing.
# Memory Usage: 14.2 MB, less than 93.66% of Python3 online submissions for Path Crossing.
class Solution:
    def isPathCrossing(self, path: str) -> bool:
        visited = set()
        x, y = 0, 0
        visited.add((x, y))
        for p in path:
            if p == 'N':
                y -= 1
            elif p == 'S':
                y += 1
            elif p == 'E':
                x += 1
            elif p == 'W':
                x -= 1
            if (x, y) in visited:
                return True
            visited.add((x, y))
        return False


tests = [["NESWW", True]]

run_functional_tests(Solution().isPathCrossing, tests)
Beispiel #7
0
# Memory Usage: 16.1 MB, less than 63.08% of Python3 online submissions for N-ary Tree Preorder Traversal.
class Solution:
    def preorder(self, root: 'Node') -> List[int]:
        result = []
        st = []
        if root:
            st.append(root)
        while st:
            node = st.pop()
            result.append(node.val)
            if node.children:
                for child in node.children[::-1]:
                    st.append(child)
        return result


tests = [[
    Node(1, [Node(3, [Node(5), Node(6)]),
             Node(2), Node(4)]), [1, 3, 5, 6, 2, 4]
],
         [
             Node(1, [
                 Node(2),
                 Node(3, [Node(6), Node(7, [Node(11, [Node(14)])])]),
                 Node(4, [Node(8, [Node(12)])]),
                 Node(5, [Node(9, [Node(13)]), Node(10)])
             ]), [1, 2, 3, 6, 7, 11, 14, 4, 8, 12, 5, 9, 13, 10]
         ]]

run_functional_tests(Solution().preorder, tests)
1 <= c <= 100
a != b, b != c, c != a
"""
from typing import List

# Runtime: 28 ms, faster than 83.08% of Python3 online submissions for Moving Stones Until Consecutive.
# Memory Usage: 14.1 MB, less than 94.03% of Python3 online submissions for Moving Stones Until Consecutive.
from Common.ObjectTestingUtils import run_functional_tests


class Solution:
    def numMovesStones(self, a: int, b: int, c: int) -> List[int]:
        a, b, c = sorted([a, b, c])
        # print(a, b, c)

        mn = 2
        if b - a == 1 and c - b == 1:
            mn = 0
        elif b - a <= 2 or c - b <= 2:
            mn = 1

        # mx = c - b - 1 + b - a - 1
        mx = c - a - 2

        return [mn, mx]


tests = [(1, 2, 5, [1, 2]), (4, 3, 2, [0, 0]), (3, 5, 1, [1, 2])]

run_functional_tests(Solution().numMovesStones, tests)
Beispiel #9
0
# class Solution:
#     def minCostClimbingStairs(self, cost: List[int]) -> int:
#         n = len(cost)
#         cost += [0]
#         dp = [0] * (n+1)
#         dp[0], dp[1] = cost[0], cost[1]
#         for i in range(2, n+1):
#             dp[i] = cost[i] + min(dp[i-1], dp[i-2])
#         return dp[n]


# Runtime: 92 ms, faster than 5.57% of Python3 online submissions for Min Cost Climbing Stairs.
# Memory Usage: 14.4 MB, less than 44.78% of Python3 online submissions for Min Cost Climbing Stairs.
class Solution:
    def minCostClimbingStairs(self, cost: List[int]) -> int:
        n = len(cost)
        cost += [0]
        dp0, dp1, dp2 = cost[0], cost[1], 0
        for i in range(2, n+1):
            dp2 = cost[i] + min(dp0, dp1)
            dp0, dp1 = dp1, dp2
        return dp2


tests = [
    [[10,15,20], 15],
    [[1,100,1,1,1,100,1,1,100,1], 6]
]

run_functional_tests(Solution().minCostClimbingStairs, tests)
Beispiel #10
0
#             return "".join('*' if c in 'aeiou' else c for c in w)
#
#         words_base = set(wordlist)
#         words1 = {}
#         words2 = {}
#
#         for w in wordlist:
#             wl = w.lower()
#             words1.setdefault(wl, w)
#             words2.setdefault(devowel(wl), w)
#
#         def solve(q):
#             if q in words_base:
#                 return q
#             ql = q.lower()
#             if ql in words1:
#                 return words1[ql]
#             qlv = devowel(ql)
#             if qlv in words2:
#                 return words2[qlv]
#             return ""
#
#         return map(solve, queries)

tests = [(["KiTe", "kite", "hare", "Hare"], [
    "kite", "Kite", "KiTe", "Hare", "HARE", "Hear", "hear", "keti", "keet",
    "keto"
], ["kite", "KiTe", "KiTe", "Hare", "hare", "", "", "KiTe", "", "KiTe"])]

run_functional_tests(Solution().spellchecker, tests)
Beispiel #11
0
#         for i in range(1, n):
#             for j in range(i):
#                 if envelopes[j][0] < envelopes[i][0] and envelopes[j][1] < envelopes[i][1]:
#                     dp[i] = max(dp[i], dp[j] + 1)
#                     result = max(result, dp[i])
#         return result


# Runtime: 148 ms, faster than 82.41% of Python3 online submissions for Russian Doll Envelopes.
# Memory Usage: 16.5 MB, less than 57.77% of Python3 online submissions for Russian Doll Envelopes.
class Solution:
    def maxEnvelopes(self, envelopes: List[List[int]]) -> int:
        n = len(envelopes)
        envelopes.sort(key=lambda x: (x[0], -x[1]))
        dp = []
        for (w, h) in envelopes:
            l = bisect_left(dp, h)
            if l == len(dp):
                dp.append(h)
            else:
                dp[l] = h
        return len(dp)


tests = [([[8, 3], [3, 20], [15, 5], [11, 2], [19, 6], [9, 18], [1,
                                                                 19], [13, 3],
           [14, 20], [6, 7]], 4), ([[5, 4], [6, 4], [6, 7], [2, 3]], 3),
         ([[1, 1], [1, 1], [1, 1]], 1)]

run_functional_tests(Solution().maxEnvelopes, tests)
            return 0

        dl = dr = 0

        if root.left:
            dl = self.minDepth(root.left)

        if root.right:
            dr = self.minDepth(root.right)

        if dl > 0 and dr > 0:
            return 1 + min(dl, dr)

        if dl > 0:
            return dl + 1
        return dr + 1


tree1 = TreeNode(3)
tree1.left = TreeNode(9)
tree1.right = TreeNode(20)
tree1.right.left = TreeNode(15)
tree1.right.right = TreeNode(7)

tree2 = TreeNode(1)
tree2.left = TreeNode(2)

tests = [(tree1, 2), (tree2, 2)]

run_functional_tests(Solution().minDepth, tests)
        def get_order(order: str) -> Dict[str, int]:
            result = {}
            for i, c in enumerate(order):
                result[c] = i
            return result

        def is_less(s1: str, s2: str, ordd: Dict[str, int]) -> bool:
            n1 = len(s1)
            n2 = len(s2)
            n = min(n1, n2)
            for i in range(n):
                if ordd.get(s1[i]) > ordd.get(s2[i]):
                    return False
                if ordd.get(s1[i]) < ordd.get(s2[i]):
                    return True
            return n1 <= n2

        ordd = get_order(order)
        n = len(words)
        for i in range(1, n):
            if not is_less(words[i - 1], words[i], ordd):
                return False

        return True


tests = [(["hello", "leetcode"], "hlabcdefgijkmnopqrstuvwxyz", True),
         (["word", "world", "row"], "worldabcefghijkmnpqstuvxyz", False)]

run_functional_tests(Solution().isAlienSorted, tests)
# Runtime: 68 ms, faster than 48.89% of Python3 online submissions for Evaluate Reverse Polish Notation.
# Memory Usage: 14.3 MB, less than 96.45% of Python3 online submissions for Evaluate Reverse Polish Notation.
class Solution:
    def evalRPN(self, tokens: List[str]) -> int:
        st = []
        for token in tokens:
            if token in ['+', '-', '*', '/']:
                v2 = st.pop()
                v1 = st.pop()
                if token == '+':
                    st.append(v1 + v2)
                elif token == '-':
                    st.append(v1 - v2)
                elif token == '*':
                    st.append(v1 * v2)
                elif token == '/':
                    st.append(int(v1 / v2))
            else:
                st.append(int(token))

        return st[0] if st else 0


tests = [
    # [["2","1","+","3","*"], 9],
    # [["4","13","5","/","+"], 6],
    [["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"], 22]
]

run_functional_tests(Solution().evalRPN, tests)
                A_used[i] = True
                j += 1

        for i in range(n):
            if A_used[i]:
                continue
            result[Bt[j][1]] = A[i]
            A_used[i] = True
            j += 1

        return result


def checkAdvantage(A: List[int], B: List[int]):
    return sum([1 if ai > bi else 0 for (ai, bi) in zip(A, B)])


def customCheck(test, result) -> bool:
    B = test[1]
    expected = test[2]
    return checkAdvantage(expected, B) == checkAdvantage(result, B)


tests = [([2, 0, 4, 1, 2], [1, 3, 0, 0, 2], [2, 0, 2, 1, 4]),
         ([2, 7, 11, 15], [1, 10, 4, 11], [2, 11, 7, 15]),
         ([12, 24, 8, 32], [13, 25, 32, 11], [24, 32, 8, 12])]

run_functional_tests(Solution().advantageCount,
                     tests,
                     custom_check=customCheck)
Beispiel #16
0
#                     min_cost_i = min(min_cost_i, prevLevel[i])
#                 current_level[i] = triangle[level][i] + min_cost_i
#                 min_cost = min(current_level[i], min_cost)
#             prevLevel = current_level
#         return min_cost

# Runtime: 52 ms, faster than 94.36% of Python3 online submissions for Triangle.
# Memory Usage: 15.2 MB, less than 26.73% of Python3 online submissions for Triangle
class Solution:
    def minimumTotal(self, triangle: List[List[int]]) -> int:
        n_levels = len(triangle)
        for level in range(n_levels-2, -1, -1):
            for i in range(level+1):
                best_below = min(triangle[level+1][i], triangle[level+1][i+1])
                triangle[level][i] += best_below
        return triangle[0][0]


tests = [
    [
        [[2],[3,4],[6,5,7],[4,1,8,3]],
        11
    ],
    [
        [[-10]],
        -10
    ]
]

run_functional_tests(Solution().minimumTotal, tests)
Beispiel #17
0
0 <= indices[i] < n
All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n - 1).
"""
from typing import List

from Common.ObjectTestingUtils import run_functional_tests

# Runtime: 64 ms, faster than 12.45% of Python3 online submissions for Shuffle String.
# Memory Usage: 14.4 MB, less than 18.54% of Python3 online submissions for Shuffle String.
# class Solution:
#     def restoreString(self, s: str, indices: List[int]) -> str:
#         return "".join(c for i, c in sorted([i, c] for i, c in zip(indices, s)))


# Runtime: 96 ms, faster than 5.05% of Python3 online submissions for Shuffle String.
# Memory Usage: 14.1 MB, less than 92.21% of Python3 online submissions for Shuffle String.
class Solution:
    def restoreString(self, s: str, indices: List[int]) -> str:
        result = [' '] * len(s)
        for i in indices:
            result[indices[i]] = s[i]
        return "".join(result)


tests = [["codeleet", [4, 5, 6, 7, 0, 2, 1, 3], "leetcode"],
         ["abc", [0, 1, 2], "abc"], ["aiohn", [3, 1, 4, 2, 0], "nihao"],
         ["aaiougrt", [4, 0, 2, 6, 7, 3, 1, 5], "arigatou"],
         ["art", [1, 0, 2], "rat"]]

run_functional_tests(Solution().restoreString, tests)
Beispiel #18
0
    def averageOfLevels(self, root: TreeNode) -> List[float]:

        levels = []

        def walkLevels(root: TreeNode, level: int):
            if not root:
                return
            nonlocal levels
            if len(levels) <= level:
                levels.append([root.val, 1])
            else:
                levels[level][0] += root.val
                levels[level][1] += 1
            walkLevels(root.left, level + 1)
            walkLevels(root.right, level + 1)

        walkLevels(root, 0)

        return [s / c for s, c in levels]


root1 = TreeNode(3)
root1.left = TreeNode(9)
root1.right = TreeNode(20)
root1.right.left = TreeNode(15)
root1.right.right = TreeNode(7)

tests = [(root1, [3, 14.5, 11])]

run_functional_tests(Solution().averageOfLevels, tests)
Beispiel #19
0
Output: [1, 2, 3]
Explanation: The [1, 2, 3] has three different positive integers ranging from 1 to 3, and the [1, 1] has exactly 1 distinct integer: 1.
Example 2:
Input: n = 3, k = 2
Output: [1, 3, 2]
Explanation: The [1, 3, 2] has three different positive integers ranging from 1 to 3, and the [2, 1] has exactly 2 distinct integers: 1 and 2.
Note:
The n and k are in the range 1 <= k < n <= 104.
"""
from typing import List

from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 48 ms, faster than 60.67% of Python3 online submissions for Beautiful Arrangement II.
# Memory Usage: 15.2 MB, less than 51.33% of Python3 online submissions for Beautiful Arrangement II.
class Solution:
    def constructArray(self, n: int, k: int) -> List[int]:
        result = list(range(1, n - k))
        for i in range(k + 1):
            if i % 2 == 0:
                result.append(n - k + i // 2)
            else:
                result.append(n - i // 2)
        return result


tests = [(3, 1, [1, 2, 3]), (3, 2, [1, 3, 2]), (6, 3, [1, 2, 3, 6, 4, 5])]

run_functional_tests(Solution().constructArray, tests)
Beispiel #20
0
class Solution:
    def wiggleMaxLength(self, nums: List[int]) -> int:
        n = len(nums)
        if n < 2:
            return n
        prevdiff = nums[1] - nums[0]
        result = 1 if prevdiff == 0 else 2
        for i in range(2, n):
            diff = nums[i] - nums[i-1]
            if diff > 0 and prevdiff <= 0 or diff < 0 and prevdiff >= 0:
                result += 1
                prevdiff = diff

        return result


tests = [
    ([3,3,3,2,5], 3),

    ([1, 4, 5, 7, 5, 5, 7, 2, 3], 6),

    ([0, 0], 1),
    ([0,0,0], 1),

    ([1,7,4,9,2,5], 6),
    ([1,17,5,10,13,15,10,5,16,8], 7),
    ([1,2,3,4,5,6,7,8,9], 2)
]

run_functional_tests(Solution().wiggleMaxLength, tests)
Beispiel #21
0
            for j in range(i+1, n):
                p = nums[i] * nums[j]
                products[p] = products.get(p, 0) + 1
        cnt = 0
        for k in products.keys():
            v = products[k]
            cnt += 4 * v * (v - 1)
        return cnt


tests = [
    [
        [2,3,4,6],
        8
    ],
    [
        [1,2,4,5,10],
        16
    ],
    [
        [2,3,4,6,8,12],
        40
    ],
    [
        [2,3,5,7],
        0
    ]
]

run_functional_tests(Solution().tupleSameProduct, tests)
#         dic = defaultdict(lambda: set())
#         for i in range(n):
#             for c in words[i]:
#                 dic[c].add(i)
#         for i in range(n):
#             for j in range(i+1, n):
#                 if not any(j in dic[c] for c in words[i]):
#                     max_p = max(max_p, len(words[i]) * len(words[j]))
#         return max_p


# Runtime: 488 ms, faster than 67.49% of Python3 online submissions for Maximum Product of Word Lengths.
# Memory Usage: 14.4 MB, less than 96.88% of Python3 online submissions for Maximum Product of Word Lengths.
class Solution:
    def maxProduct(self, words: List[str]) -> int:
        res, dic = 0, defaultdict(int)
        for w in words:
            for c in w:
                dic[w] |= 1 << (ord(c) - ord('a'))
        for w1, w2 in combinations(dic.keys(), 2):
            if dic[w1] & dic[w2] == 0:
                res = max(res, len(w1) * len(w2))
        return res


tests = [[["abcw", "baz", "foo", "bar", "xtfn", "abcdef"], 16],
         [["a", "ab", "abc", "d", "cd", "bcd", "abcd"], 4],
         [["a", "aa", "aaa", "aaaa"], 0]]

run_functional_tests(Solution().maxProduct, tests)
Beispiel #23
0
# Runtime: 664 ms, faster than 97.10% of Python3 online submissions for Course Schedule III.
# Memory Usage: 19.4 MB, less than 50.65% of Python3 online submissions for Course Schedule III.
class Solution:
    def scheduleCourse(self, courses: List[List[int]]) -> int:
        courses.sort(key=lambda x: x[1])
        n = len(courses)

        time, count = 0, 0

        prev_courses = []

        for i in range(n):
            duration, end = courses[i]
            if time + duration <= end:
                time += duration
                count += 1
                heapq.heappush(prev_courses, -duration)
            else:
                if prev_courses and -prev_courses[0] > duration:
                    prev_duration = -heapq.heappop(prev_courses)
                    time += duration - prev_duration
                    heapq.heappush(prev_courses, -duration)
        return count


tests = [[[[1, 2], [2, 3]], 2],
         [[[100, 200], [200, 1300], [1000, 1250], [2000, 3200]], 3],
         [[[1, 2]], 1], [[[3, 2], [4, 3]], 0]]

run_functional_tests(Solution().scheduleCourse, tests)
Beispiel #24
0
#             tvisit[curr] = fup[curr] = self.timer
#             for child in graph[curr]:
#                 if child == par:
#                     continue
#                 if marked[child]:
#                     fup[curr] = min(fup[curr], tvisit[child])
#                 else:
#                     dfs(child, curr)
#                     fup[curr] = min(fup[curr], fup[child])
#                     if fup[child] > tvisit[curr]:
#                         result.append([curr, child])
#
#         for i, j in connections:
#             graph[i].append(j)
#             graph[j].append(i)
#
#         for i in range(n):
#             if not marked[i]:
#                 dfs(i)
#
#         return result




tests = [
    [4, [[0,1],[1,2],[2,0],[1,3]], [[1,3]]]
]

run_functional_tests(Solution().criticalConnections, tests)
    def letterCombinations(self, digits: str) -> List[str]:
        if not digits:
            return []
        tr = {
            "2": "abc",
            "3": "def",
            "4": "ghi",
            "5": "jkl",
            "6": "mno",
            "7": "pqrs",
            "8": "tuv",
            "9": "wxyz"
        }
        result = [""]
        for d in digits:
            current = result
            result = []
            for s in current:
                for dd in tr.get(d):
                    result.append(s + dd)
        return result


tests = [
    ("23", ["ad","ae","af","bd","be","bf","cd","ce","cf"]),
    ("", []),
    ("2", ["a","b","c"])
]

run_functional_tests(Solution().letterCombinations, tests)
Beispiel #26
0
Note:

1 <= rooms.length <= 1000
0 <= rooms[i].length <= 1000
The number of keys in all rooms combined is at most 3000.
"""
from typing import List

from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 68 ms, faster than 52.75% of Python3 online submissions for Keys and Rooms.
# Memory Usage: 15 MB, less than 38.28% of Python3 online submissions for Keys and Rooms.
class Solution:
    def canVisitAllRooms(self, rooms: List[List[int]]) -> bool:
        n = len(rooms)
        visited = set()
        toVisit = [0]
        while toVisit:
            i = toVisit.pop()
            visited.add(i)
            for j in rooms[i]:
                if j not in visited:
                    toVisit.append(j)
        return len(visited) == n


tests = [([[1], [2], [3], []], True), ([[1, 3], [3, 0, 1], [2], [0]], False)]

run_functional_tests(Solution().canVisitAllRooms, tests)
Beispiel #27
0
2 <= s.length <= 500
The string s consists of characters '0' and '1' only.
"""
from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 32 ms, faster than 82.95% of Python3 online submissions for Maximum Score After Splitting a String.
# Memory Usage: 14.1 MB, less than 73.40% of Python3 online submissions for Maximum Score After Splitting a String.
class Solution:
    def maxScore(self, s: str) -> int:
        max_score = 0
        s0 = 0
        s1 = sum(1 for c in s if c == '1')
        n = len(s)
        for i in range(n-1):
            if s[i] == '0':
                s0 += 1
            else:
                s1 -= 1
            max_score = max(max_score, s0 + s1)
        return max_score


tests = [
    ["011101", 5],
    ["00111", 5],
    ["1111", 3]
]

run_functional_tests(Solution().maxScore, tests)
Beispiel #28
0
            if str.isdigit(s[i]):
                current = 10 * current + (ord(s[i]) - ord('0'))
            if i == n-1 or not str.isdigit(s[i]) and not str.isspace(s[i]):
                op = s[i]
                if operation == '-':
                    result += last
                    last = -current
                elif operation == '+':
                    result += last
                    last = current
                elif operation == '*':
                    last = last * current
                else:
                    last = int(last / current)
                operation = op
                current = 0
            i += 1
        result += last
        return result


tests = [
    ("14-3/2", 13),

    ("3+2*2", 7),
    (" 3/2 ", 1),
    (" 3+5 / 2 ", 5)
]

run_functional_tests(Solution().calculate, tests)
Beispiel #29
0
#
#         for x in numbers:
#             for y in [x-1, x+1]:
#                 if y in numbers:
#                     union(find_set(numbers[x]), find_set(numbers[y]))
#
#         return max(w)


# Runtime: 180 ms, faster than 41.47% of Python3 online submissions for Longest Consecutive Sequence.
# Memory Usage: 25.7 MB, less than 24.14% of Python3 online submissions for Longest Consecutive Sequence.
class Solution:
    def longestConsecutive(self, nums: List[int]) -> int:
        result = 0
        numbers = set(nums)
        for x in numbers:
            if x - 1 not in numbers:
                current = x
                current_streak = 1
                while current + 1 in numbers:
                    current += 1
                    current_streak += 1
                result = max(result, current_streak)
        return result


tests = [[[1, 3, 5, 2, 4], 5], [[], 0], [[100, 4, 200, 1, 3, 2], 4],
         [[0, 3, 7, 2, 5, 8, 4, 6, 0, 1], 9]]

run_functional_tests(Solution().longestConsecutive, tests)
Beispiel #30
0
from Common.ObjectTestingUtils import run_functional_tests


# Runtime: 244 ms, faster than 49.40% of Python3 online submissions for Palindromic Substrings.
# Memory Usage: 21.8 MB, less than 39.18% of Python3 online submissions for Palindromic Substrings.
class Solution:
    def countSubstrings(self, s: str) -> int:
        cnt = 0
        n = len(s)
        dp = [[False] * n for _ in range(n)]
        for i in range(n):
            dp[i][i] = True
            cnt += 1
            if i > 0 and s[i - 1] == s[i]:
                dp[i - 1][i] = True
                cnt += 1

        for l in range(3, n + 1):
            for i in range(0, n - l + 1):
                j = i + l - 1
                if s[i] == s[j] and dp[i + 1][j - 1]:
                    dp[i][j] = True
                    cnt += 1

        return cnt


tests = [("abc", 3), ("aaa", 6)]

run_functional_tests(Solution().countSubstrings, tests)