def test_decode():
assert bytearray(leviathan_plain,
'utf-8') == ascii85.decode(leviathan_encoded)
for (plain, encoded) in tuples:
assert bytearray(plain,
'utf-8') == ascii85.decode('<~' + encoded + '~>')
assert False == ascii85.decode(encoded)
assert False == ascii85.decode('<~' + encoded)
assert False == ascii85.decode(encoded + '~>')
def test_decode(self):
for phrase in self.phrases_to_decode:
phrase = phrase.encode("utf-8")
actual = ascii85.decode(phrase)
expected = base64.a85decode(phrase, adobe=True)
self.assertEqual(actual, expected)
xor.append(x)
# a) 15 * '=' must be in the encrypted text, because the line "==[ Payload ]==" contains 47 * '='.
# b) Multiple occurences are possible, but hopefully in at least one case 17 more '=' will follow.
# c) The last occurence is tried first, because that should be the "Payload"-line.
tattletale = bytearray()
for x in xor:
tattletale.append(x ^ ord('='))
xorfullstart = decoded.rfind(tattletale)
# assumption/hope: the next 32 bytes are all encoded '='
xorfull = bytearray()
for d in decoded[xorfullstart:xorfullstart + 32]:
xorfull.append(d ^ ord('='))
# decrypt the bytes with the assumed key
decrypted = bytearray()
for i in range(len(decoded)):
decrypted.append(decoded[i] ^ xorfull[i % 32])
return decrypted
if __name__ == '__main__':
import ascii85
payload = ascii85.loadpayload('layers/layer3.txt')
decoded = ascii85.decode(payload)
decoded = decrypt(decoded)
print(decoded.decode()[0:500])