def issuecred(self, usk, uvk, m, ask, avk):
n = len(m)
# 得到s
s = p.random()
print("s为", s)
# 得到{Qi},i=[1,n],其中Qi都是G2上的元素
G = bp.BpGroup()
g2 = G.gen2()
Q = []
for _ in range(n):
rand = p.random()
Q.append(rand * g2)
# (user) ObtainCommit
# 得到pi_1和pi_2
pi_1 = self.nizk.proveK(m, s, uvk, Q)
# 由于proveDL的接口,只能传入list形式的参数,这里需要用[usk],[self.g2],而不能用usk,self.g2
pi_2 = self.nizk.proveDL([usk], [self.g2])
# (auth)sigma_cred_ <-Issue(uvk,ask,pi)
# 同样DL的接口,只能传入list形式的参数,这里需要用pi_2(pi_2本身就是三个元素的list),[self.g2]
if (self.nizk.verifyK(pi_1, uvk, Q) == 1
and self.nizk.verifyDL(pi_2, [self.g2]) == 1):
w = p.random()
sigma_cred_ = (w * uvk, w * (avk[1] + pi_1[0]))
else:
print("auth验证失败")
#(user)delta_cred<-Unblind(delta_cred_,s)
sigma_cred = (self.g1, self.g1, sigma_cred_[0],
sigma_cred_[1] - s * sigma_cred_[0])
return sigma_cred
def mk_gk():
G = bp.BpGroup()
q = G.order()
g1 = G.gen1()
g2 = G.gen2()
gt = G.pair(g1, g2)
return gk_T(G, q, g1, g2, gt, G.pair)
def H(otsvk):
# 这里要确保这里生成的G和BLCred的self.G是一样的才行
G = bp.BpGroup()
X_ = otsvk[0].export()
Y_ = otsvk[1].export()
bytestr = X_ + Y_
str0 = str(bytestr)
return G.hashG1(str0.encode("utf8"))
def __init__(self, p):
self.G = bp.BpGroup()
# g1, g2 is the generator of G1, G2
self.g1, self.g2 = self.G.gen1(), self.G.gen2()
self.x = 0
self.X = 0
self.p = p
self.h = 0
print("G的order为", self.G.order())
def __init__(self, p, m):
self.G = bp.BpGroup()
# g1, g2 分别是G1，G2的生成元
self.g1, self.g2 = self.G.gen1(), self.G.gen2()
# x,X 分别是私钥和公钥
self.x = 0
self.X = 0
# p,m是传入的参数，p为传入的大质数，G1，G2，GT的阶为另一个给定的大质数，m是传入的消息，属于Zp
self.p = p
self.m = m
def __init__(self, p):
self.G = bp.BpGroup()
# g1, g2 分别是G1，G2的生成元
self.g1, self.g2 = self.G.gen1(), self.G.gen2()
# x,y,X,Y 分别是私钥和公钥中的元素
self.x = 0
self.y = 0
self.X = 0
self.Y = 0
# p,m是传入的参数，p为传入的大质数，使得G1，G2，GT的阶为质数p，m是传入的消息，属于Zp
self.p = p
# r是theta中的一个元素，从消息空间Zp中随机获得（这里暂且先生成一个candidate，之后在sign函数中会进行筛选
self.r = Bn().from_decimal(str(self.p)).random()
self.theta_prime = 0
print("G的order为", self.G.order())
def setup(self):
# Choose a bilinear group
self.G = bp.BpGroup()
self.g1, self.g2 = self.G.gen1(), self.G.gen2()
import random from petlib.bn import Bn from petlib.ec import EcGroup, EcPt from bplib import bp # 在FBB和WBB中遇到的一个Bug G = bp.BpGroup() p = 19 m = 16 x = Bn(p).random() print(x) # 这种情况会报错:TypeError: bad operand type for abs(): 'Bn' num = Bn(x + m).mod_inverse(G.order()) print(num) # 解决方案:改为如下写法 num = Bn(int(x + m)).mod_inverse(G.order()) print(num) # 在BLS，FBB，WBB中会遇到另外一个Bug # 无法使用大整数问题：如果是Bn(x)，x不能超过2^32，而且必须是int类型，即最好写成Bn(int(x))，否则可能报错（上述 # 因此我们可以用别的方法来避免这种调用 Bn.from_decimal(str(x + m))
def __init__(self):
self.G = bp.BpGroup()
self.p = int(self.G.order())
self.n = -1