Beispiel #1
0
    def rotate_in_place(a: np.array):
        """  Rotate for N*N array, the result is equivalent to numpy.rot90(a, 3)
        :array: N*N numpy array
        :return: rotated numpy array

        Complexity:
        Time  : O(rc)
        Space : O(rc)
        """

        # 4-way edge swap
        if not a.all():
            raise ArgError()

        row_num, col_num = a.shape

        if row_num != col_num:
            raise ArgError("only support N*N array")

        dim = row_num

        layers = dim // 2

        for layer in range(layers):
            start = layer
            end = dim - 1 - layer

            for offset in range(end - start):
                tmp = a[start, start + offset]
                a[start, start + offset] = a[end - offset, start]
                a[end - offset, start] = a[end, end - offset]
                a[end, end - offset] = a[start + offset, end]
                a[start + offset, end] = tmp

        return a
Beispiel #2
0
    def is_permutation(s1, s2, *, case_sensitive=False):
        """ Determine if str1 is the permutation of str2

        Complexity:
        Time  : O(n)
        Space : O(c)
        """

        if not s1 or not s2:
            raise ArgError()

        if len(s1) != len(s2):
            return False

        if not case_sensitive:
            s1, s2 = s1.lower(), s2.lower()

        m = collections.defaultdict(int)

        for c in s1:
            m[c] += 1

        for c in s2:
            m[c] -= 1
            if m[c] < 0:
                return False

        return True
Beispiel #3
0
    def rotate_in_place_v2(a):
        """  Rotate for N*N array, the result is equivalent to numpy.rot90(a, 3)
        :array: non np array
        :return: rotated  array

        Complexity:
        Time  : O(rc)
        Space : O(rc)
        """
        row_num = len(a)
        col_num = len(a[0])

        if row_num != col_num:
            raise ArgError()

        dim = row_num

        layers = row_num // 2

        for layer in range(layers):
            start = layer
            end = dim - 1 - layer

            for offset in range(end - start):
                tmp = a[start][start + offset]
                a[start][start + offset] = a[end - offset][start]
                a[end - offset][start] = a[end][end - offset]
                a[end][end - offset] = a[start + offset][end]
                a[start + offset][end] = tmp

        return a
Beispiel #4
0
    def replace_spaces(s, *, pattern="%20"):
        """ In fact, s.replace(" ", %20) can solve this issue

        Complexity:
            Time  : O(n)
            Space : O(n)
        """

        if not s:
            raise ArgError()

        buf = list()

        for c in s:
            if c == " ":
                buf.append(pattern)
            else:
                buf.append(c)

        return "".join(buf)
Beispiel #5
0
    def rotate(a: np.array, *, dtype=int):
        """  Rotate for M*N array, this is equivalent to numpy.rot90(a, 3)
        :array: M*N numpy array
        :return: rotated numpy array

        Complexity:
        Time  : O(rc)
        Space : O(rc)
        """

        if not a.all():
            raise ArgError()

        row_num, col_num = a.shape[::-1]

        rotated_array = np.empty(shape=[row_num, col_num], dtype=dtype)

        for index, v in np.ndenumerate(a):
            r, c = index
            rotated_array[c, col_num - 1 - r] = v

        return rotated_array
Beispiel #6
0
    def is_palindrome_permutation(s):
        """ Determine if s is a palindrome permutation

        Complexity:
            Time  : O(n)
            Space : O(n)
        """
        if not s:
            raise ArgError()

        if len(s) == 1:
            return True

        odd_cnt = 0
        m = collections.defaultdict(int)
        for c in s:
            m[c] += 1
            if m[c] % 2 == 0:
                odd_cnt -= 1
            else:
                odd_cnt += 1

        return odd_cnt <= 1
Beispiel #7
0
    def is_palindrome(s):
        """ Determine if s is a palindrome

        Complexity:
            Time  : O(n)
            Space : O(n)
        """
        if not s:
            raise ArgError()

        if len(s) == 1:
            return True

        start, end = 0, len(s) - 1

        while start < end:
            if s[start] == s[end]:
                start += 1
                end -= 1
            else:
                return False

        return True
Beispiel #8
0
    def is_unique_char(s, *, case_sensitive=False):
        """ Determine if str has all unique characters

        Complexity:
        Time  : O(n)
        Space : O(C)
        """

        if not s:
            raise ArgError()

        if not case_sensitive:
            s = s.lower()

        m = dict()
        for c in s:
            if not m.get(c, None):
                m[c] = True
                continue
            else:
                # duplicated
                return False

        return True