def find_the_most_suitable_answer(keywords):
    dao = Dao()
    answers = dao.get_dictionary()
    # print(answers)
    value_list = {}
    i = 0
    while i < 500:
        value_list[i] = 0.0
        i += 1

    '''for keyword in keywords:
        #print(keyword)
        for answer in answers:
            #print(answer)
            if answers[answer].count(keyword) == 1:
                value_list[answer] += 1'''

    # print(keyword)
    for answer in answers:
        for keyword in keywords:
            # print(answer)
            if answers[answer].count(keyword) == 1:
                value_list[answer] += 1
        if len(answers[answer]) != 0:
            # print("Sss" + str(value_list[answer]) + str(len(answers[answer]) * 1.0))
            value_list[answer] = value_list[answer] / (len(answers[answer]) * 1.0)
            # print(value_list[answer])
        # print(dao.execute("select `text` from hack.`key` where `answer_id` = " + str(answer)))

    return sorted(value_list.items(), key=operator.itemgetter(1))[len(value_list) - 1][0]
Beispiel #2
0
from db.dao import Dao

dao = Dao()
print(dao.get_dictionary())