Beispiel #1
0
def ispalindrome(linked_list):
    if not linked_list.head:
        return False

    aux = linked_list.head
    size = 0
    while aux:
        size += 1
        aux = aux.next

    if size == 1:  # maybe removed
        return True

    i = 1
    ll = None
    while i <= round(size / 2):
        if not ll:
            ll = LinkedList(linked_list.head.value)
        else:
            new_head = Node(linked_list.head.value)
            new_head.next = ll.head
            ll.head = new_head
        if size % 2 == 0 or i != round(size / 2):
            linked_list.head = linked_list.head.next
        i += 1

    return equals(ll, linked_list)
Beispiel #2
0
        aux = aux.next
        size += 1

    if kth >= size:
        return
    complement = size - kth

    aux = linked_list.head
    i = 1
    while i != complement:
        aux = aux.next
        i += 1
    return aux.value


ll = LinkedList(5)
ll.add(4)
ll.add(3)
ll.add(2)
ll.add(1)

ll_one_elem = LinkedList(1)

print(return_kth_to_last(ll, 1))
print(return_kth_to_last(ll, 2))
print(return_kth_to_last(ll, 3))
print(return_kth_to_last(ll, 4))
print(return_kth_to_last(ll, 5))
print(return_kth_to_last(ll, 6))

print(return_kth_to_last(ll_one_elem, 0))
Beispiel #3
0
from linked_list.likedlist import LinkedList


# Remove duplications from a linked list
# Space O(1). Time O(n²)
def remove_dup(linked_list):
    first = linked_list.head

    while first and first.next:
        second = first
        while second.next:
            if first.value == second.next.value:
                second.next = second.next.next
            else:
                second = second.next
        first = first.next


ll = LinkedList(5)
ll.add(4)
ll.add(3)
ll.add(5)
ll.add(4)
ll.add(3)

print(ll)
remove_dup(ll)
print(ll)
Beispiel #4
0
    if first_size > second_size:
        while first_size != second_size:
            aux1 = aux1.next
            first_size -= 1
    elif second_size > first_size:
        while second_size != first_size:
            aux2 = aux2.next
            second_size -= 1

    while aux1 and aux2:
        if aux1 == aux2:
            return aux1
        aux1 = aux1.next
        aux2 = aux2.next

    return


first_ll = LinkedList('1')
first_ll.add('2')
first_ll.add('3')
first_ll.add('4')
first_ll.add('5')

second_ll = copy.copy(first_ll)
second_ll.head = second_ll.head.next
new_head = Node(9)
new_head.next = second_ll.head.next
second_ll.head = new_head
print(intersection(first_ll, second_ll))
Beispiel #5
0
        val2 = aux2.value if aux2 else 0
        if not aux1:
            aux1_prev.next = Node((val1 + val2 + carry) % 10)
        else:
            aux1.value = (val1 + val2 + carry) % 10
        carry = 1 if val1 + val2 + carry >= 10 else 0
        aux1_prev = aux1 if aux1 else aux1_prev.next
        if aux1:
            aux1 = aux1.next
        if aux2:
            aux2 = aux2.next

    return list_one


first_ll = LinkedList(1)
first_ll.add(3)
first_ll.add(5)

second_ll = LinkedList(2)
second_ll.add(4)
second_ll.add(1)

# first_ll = LinkedList(9)
# first_ll.add(5)
# first_ll.add(1)
#
# second_ll = LinkedList(7)
# second_ll.add(4)
# second_ll.add(1)
Beispiel #6
0
    ll = None
    while i <= round(size / 2):
        if not ll:
            ll = LinkedList(linked_list.head.value)
        else:
            new_head = Node(linked_list.head.value)
            new_head.next = ll.head
            ll.head = new_head
        if size % 2 == 0 or i != round(size / 2):
            linked_list.head = linked_list.head.next
        i += 1

    return equals(ll, linked_list)


ll = LinkedList('a')
print(ispalindrome(ll))

ll = LinkedList('a')
ll.add('a')
print(ispalindrome(ll))

ll = LinkedList('t')
ll.add('a')
ll.add('c')
ll.add('c')
ll.add('a')
ll.add('t')
print(ispalindrome(ll))

ll = LinkedList('t')
Beispiel #7
0
# Check is a linked lists contains a loop. Return the node at beginning of loop.
# Space O(n). Time O(n)
def loop_detect(linked_list):
    if not linked_list.head:
        return

    dict = {}
    aux = linked_list.head
    while aux:
        if dict.get(aux):
            return aux
        dict[aux] = 1
        aux = aux.next


circular_ll = LinkedList('A')
circular_ll.add('B')
circular_ll.add('C')
circular_ll.add('D')
circular_ll.add('E')
tail = circular_ll.head.next.next.next.next
node_c = circular_ll.head.next.next
tail.next = node_c
print(loop_detect(circular_ll))

not_circular_ll = LinkedList('A')
not_circular_ll.add('B')
not_circular_ll.add('C')
not_circular_ll.add('D')
not_circular_ll.add('E')
print(loop_detect(not_circular_ll))