def list_menu(context, position_id):
"""
Simple and generic menu tags to print menu items as a html list.
example:
{% list_menu 'top_menu' %}
"""
request = context.get('request')
title, items = get_menu_by_position(position_id)
menu_tag, menu_class, before_link, after_link = get_menu_components(
position_id)
output = []
output.append('<%s class="ul_toplevel %s">' % (menu_tag, menu_class))
top_menu_count = count_menu_children(items, 0)
counter = 0
for menu in items:
if menu['parent_id'] == 0:
current_class = ''
if request.path == menu.get('url'):
current_class = 'current'
if counter == 0:
output.append('<li class="li_toplevel first menu_%s %s">' %
(menu['id'], current_class))
elif counter == top_menu_count - 1:
output.append('<li class="li_toplevel last menu_%s %s">' %
(menu['id'], current_class))
else:
output.append('<li class="li_toplevel menu_%s %s">' %
(menu['id'], current_class))
output.append('%s<a href="%s" title="%s">%s</a>%s' %
(before_link, menu['url'], menu['title'],
menu['title'], after_link))
output.append(render_menu_children(request, menu, items, menu_tag))
output.append('</li>')
counter += 1
output.append('</%s>' % menu_tag)
return u'\n'.join(output)
def render(self, context):
title, items = get_menu_by_position(self.position_id)
context[self.varname + '_title'] = title
context[self.varname] = items
return ''