Beispiel #1
0
def makeorder(client, address, currency, amount, tokenprice, key):
    utxos = client_call(client.get_utxos, [address, currency])

    amount = int(amount * 1e18)
    # Find a utxos with enough tokens
    for utxo in utxos:
        if utxo[3] >= amount:
            # generate the transaction object

            change_amount = utxo[3] - amount

            if change_amount:
                tx = Transaction(Transaction.TxnType.make_order,
                                 utxo[0], utxo[1], utxo[2],
                                 0, 0, 0,
                                 Transaction.UTXOType.make_order, utils.normalize_address(address), amount, tokenprice, utils.normalize_address(currency),
                                 Transaction.UTXOType.transfer, utils.normalize_address(address), change_amount, 0, utils.normalize_address(currency),
                                 0, NULL_ADDRESS, 0, 0, NULL_ADDRESS,
                                 0, NULL_ADDRESS, 0, 0, NULL_ADDRESS)
            else:
                tx = Transaction(Transaction.TxnType.make_order,
                                 utxo[0], utxo[1], utxo[2],
                                 0, 0, 0,
                                 Transaction.UTXOType.make_order, utils.normalize_address(address), amount, tokenprice, utils.normalize_address(currency),
                                 0, NULL_ADDRESS, 0, 0, NULL_ADDRESS,
                                 0, NULL_ADDRESS, 0, 0, NULL_ADDRESS,
                                 0, NULL_ADDRESS, 0, 0, NULL_ADDRESS)                

            tx.sign1(utils.normalize_key(key))

            client_call(client.apply_transaction, [tx], "Sent transaction")
            break
Beispiel #2
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def sendtx(client, blknum1, txindex1, oindex1, blknum2, txindex2, oindex2,
           newowner1, contractaddress1, amount1, tokenid1, newowner2,
           contractaddress2, amount2, tokenid2, key1, key2):
    if newowner1 == "0x0":
        newowner1 = NULL_ADDRESS
    if newowner2 == "0x0":
        newowner2 = NULL_ADDRESS
    if contractaddress1 == "0x0":
        contractaddress1 = NULL_ADDRESS
    if contractaddress2 == "0x0":
        contractaddress2 = NULL_ADDRESS
    if key2 is None:
        key2 = key1

    # Form a transaction
    tx = Transaction(blknum1, txindex1, oindex1, blknum2, txindex2, oindex2,
                     utils.normalize_address(newowner1),
                     utils.normalize_address(contractaddress1), amount1,
                     tokenid1, utils.normalize_address(newowner2),
                     utils.normalize_address(contractaddress2), amount2,
                     tokenid2)

    # Sign it
    tx.sign1(utils.normalize_key(key1))
    tx.sign2(utils.normalize_key(key2))

    client.apply_transaction(tx)
    print("Sent transaction")
Beispiel #3
0
def test_challenge_exit(t, u, root_chain):
    owner, value_1, key = t.a1, 100, t.k1
    null_address = b'\x00' * 20
    tx1 = Transaction(0, 0, 0, 0, 0, 0, owner, value_1, null_address, 0, 0)
    tx_bytes1 = rlp.encode(tx1, UnsignedTransaction)
    dep1_blknum = root_chain.getDepositBlock()
    root_chain.deposit(tx_bytes1, value=value_1)
    merkle = FixedMerkle(16, [tx1.merkle_hash], True)
    proof = merkle.create_membership_proof(tx1.merkle_hash)
    confirmSig1 = confirm_tx(tx1,
                             root_chain.getChildChain(dep1_blknum)[0], key)
    sigs = tx1.sig1 + tx1.sig2 + confirmSig1
    exitId1 = dep1_blknum * 1000000000 + 10000 * 0 + 0
    root_chain.startExit(exitId1, tx_bytes1, proof, sigs, sender=key)
    tx2 = Transaction(dep1_blknum, 0, 0, 0, 0, 0, owner, value_1, null_address,
                      0, 0)
    tx2.sign1(key)
    tx_bytes2 = rlp.encode(tx2, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx2.merkle_hash], True)
    proof = merkle.create_membership_proof(tx2.merkle_hash)
    child_blknum = root_chain.currentChildBlock()
    root_chain.submitBlock(merkle.root)
    confirmSig = confirm_tx(tx2,
                            root_chain.getChildChain(child_blknum)[0], key)
    sigs = tx2.sig1 + tx2.sig2
    exitId2 = child_blknum * 1000000000 + 10000 * 0 + 0
    assert root_chain.exits(exitId1) == ['0x' + owner.hex(), 100, exitId1]
    assert root_chain.exitIds(exitId1) == exitId1
    root_chain.challengeExit(exitId2, exitId1, tx_bytes2, proof, sigs,
                             confirmSig)
    assert root_chain.exits(exitId1) == [
        '0x0000000000000000000000000000000000000000', 0, 0
    ]
    assert root_chain.exitIds(exitId1) == 0
def test_start_exit(t, root_chain, assert_tx_failed):
    week_and_a_half = 60 * 60 * 24 * 13
    owner, value_1, key = t.a1, 100, t.k1
    null_address = b'\x00' * 20
    tx1 = Transaction(0, 0, 0, 0, 0, 0, owner, value_1, null_address, 0, 0)
    tx_bytes1 = rlp.encode(tx1, UnsignedTransaction)
    root_chain.deposit(tx_bytes1, value=value_1)
    merkle = FixedMerkle(16, [tx1.merkle_hash], True)
    proof = merkle.create_membership_proof(tx1.merkle_hash)
    confirmSig1 = confirm_tx(tx1, root_chain.getChildChain(1)[0], key)
    priority1 = 1 * 1000000000 + 10000 * 0 + 0
    snapshot = t.chain.snapshot()
    sigs = tx1.sig1 + tx1.sig2 + confirmSig1
    # Deposit exit
    root_chain.startExit([1, 0, 0], tx_bytes1, proof, sigs, sender=key)
    t.chain.head_state.timestamp += week_and_a_half
    # Cannot exit twice off of the same utxo
    assert_tx_failed(lambda: root_chain.startExit(
        [1, 0, 0], tx_bytes1, proof, sigs, sender=key))
    assert root_chain.getExit(priority1) == [
        '0x' + owner.hex(), 100, [1, 0, 0]
    ]
    t.chain.revert(snapshot)

    tx2 = Transaction(1, 0, 0, 0, 0, 0, owner, value_1, null_address, 0, 0)
    tx2.sign1(key)
    tx_bytes2 = rlp.encode(tx2, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx2.merkle_hash], True)
    proof = merkle.create_membership_proof(tx2.merkle_hash)
    t.chain.head_state.block_number += 7
    root_chain.submitBlock(merkle.root)
    confirmSig1 = confirm_tx(tx2, root_chain.getChildChain(2)[0], key)
    priority2 = 2 * 1000000000 + 10000 * 0 + 0
    sigs = tx2.sig1 + tx2.sig2 + confirmSig1
    snapshot = t.chain.snapshot()
    # Single input exit
    root_chain.startExit([2, 0, 0], tx_bytes2, proof, sigs, sender=key)
    assert root_chain.getExit(priority2) == [
        '0x' + owner.hex(), 100, [2, 0, 0]
    ]
    t.chain.revert(snapshot)

    root_chain.deposit(tx_bytes1, value=value_1)
    tx3 = Transaction(2, 0, 0, 3, 0, 0, owner, value_1, null_address, 0, 0)
    tx3.sign1(key)
    tx3.sign2(key)
    tx_bytes3 = rlp.encode(tx3, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx3.merkle_hash], True)
    proof = merkle.create_membership_proof(tx3.merkle_hash)
    t.chain.head_state.block_number += 7
    root_chain.submitBlock(merkle.root)
    confirmSig1 = confirm_tx(tx3, root_chain.getChildChain(4)[0], key)
    confirmSig2 = confirm_tx(tx3, root_chain.getChildChain(4)[0], key)
    priority3 = 4 * 1000000000 + 10000 * 0 + 0
    sigs = tx3.sig1 + tx3.sig2 + confirmSig1 + confirmSig2
    # Double input exit
    root_chain.startExit([4, 0, 0], tx_bytes3, proof, sigs, sender=key)
    assert root_chain.getExit(priority3) == [
        '0x' + owner.hex(), 100, [4, 0, 0]
    ]
Beispiel #5
0
def test_challenge_exit(t, u, root_chain):
    owner, value_1, key = t.a1, 100, t.k1
    null_address = b'\x00' * 20
    tx1 = Transaction(0, 0, 0, 0, 0, 0,
                      owner, value_1, null_address, 0, 0)
    tx_bytes1 = rlp.encode(tx1, UnsignedTransaction)
    root_chain.deposit(tx_bytes1, value=value_1)
    merkle = FixedMerkle(16, [tx1.merkle_hash], True)
    proof = merkle.create_membership_proof(tx1.merkle_hash)
    confirmSig1 = confirm_tx(tx1, root_chain.getChildChain(1)[0], key)
    sigs = tx1.sig1 + tx1.sig2 + confirmSig1
    root_chain.startExit([1, 0, 0], tx_bytes1, proof, sigs, sender=key)
    tx2 = Transaction(1, 0, 0, 0, 0, 0,
                      owner, value_1, null_address, 0, 0)
    tx2.sign1(key)
    tx_bytes2 = rlp.encode(tx2, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx2.merkle_hash], True)
    proof = merkle.create_membership_proof(tx2.merkle_hash)
    t.chain.head_state.block_number += 7
    root_chain.submitBlock(merkle.root)
    confirmSig = confirm_tx(tx2, root_chain.getChildChain(2)[0], key)
    sigs = tx2.sig1 + tx2.sig2
    exit_id = 1 * 1000000000 + 10000 * 0 + 0
    assert root_chain.exits(exit_id) == ['0x' + owner.hex(), 100]
    assert root_chain.exitIds(exit_id) == exit_id
    root_chain.challengeExit(exit_id, [2, 0, 0], tx_bytes2, proof, sigs, confirmSig)
    assert root_chain.exits(exit_id) == ['0x0000000000000000000000000000000000000000', 0]
    assert root_chain.exitIds(exit_id) == 0
    def create_utxo(self, to_contractaddress, provide_amount):
        utxos = self.get_utxos()
        for blknum, txindex, oindex, contractaddress, amount, tokenid in utxos:
            if contractaddress.lower() == to_contractaddress[2:].lower():
                if amount == provide_amount:
                    return blknum, txindex, oindex, contractaddress, amount, tokenid

        for blknum, txindex, oindex, contractaddress, amount, tokenid in utxos:
            if contractaddress.lower() == to_contractaddress[2:].lower():
                if amount > provide_amount:
                    tx = Transaction(blknum, txindex, oindex, 0, 0, 0,
                                     utils.normalize_address(self.address),
                                     utils.normalize_address(contractaddress),
                                     provide_amount, 0,
                                     utils.normalize_address(self.address),
                                     utils.normalize_address(contractaddress),
                                     amount - provide_amount, 0)
                    tx.sign1(
                        utils.normalize_key(plasma_config["AUTHORITY_KEY"]))
                    tx.sign2(
                        utils.normalize_key(plasma_config["AUTHORITY_KEY"]))
                    self.child_chain.apply_transaction(
                        rlp.encode(tx, Transaction).hex())
                    break
        else:
            raise ValueError("no available utxo")
        utxos = self.get_utxos()
        for blknum, txindex, oindex, contractaddress, amount, tokenid in utxos:
            if contractaddress.lower() == to_contractaddress[2:].lower():
                if amount == provide_amount:
                    return blknum, txindex, oindex, contractaddress, amount, tokenid
        raise Exception("Something went wrong")
Beispiel #7
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def test_transaction(t):
    blknum1, txindex1, oindex1 = 1, 1, 0
    blknum2, txindex2, oindex2 = 2, 2, 1
    newowner1, amount1 = t.a1, 100
    newowner2, amount2 = t.a2, 150
    fee = 5
    oldowner1, oldowner2 = t.a1, t.a2
    key1, key2 = t.k1, t.k2
    tx = Transaction(blknum1, txindex1, oindex1,
                     blknum2, txindex2, oindex2,
                     newowner1, amount1,
                     newowner2, amount2,
                     fee)
    assert tx.blknum1 == blknum1
    assert tx.txindex1 == txindex1
    assert tx.oindex1 == oindex1
    assert tx.blknum2 == blknum2
    assert txindex2 == txindex2
    assert tx.oindex2 == oindex2
    assert tx.newowner1 == newowner1
    assert tx.amount1 == amount1
    assert tx.newowner2 == newowner2
    assert tx.amount2 == amount2
    assert tx.sig1 == b'\x00' * 65
    assert tx.sig2 == b'\x00' * 65
    tx.sign1(key1)
    assert tx.sender1 == oldowner1
    tx.sign2(key2)
    assert tx.sender2 == oldowner2
Beispiel #8
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def test_send_tx_with_sig(child_chain):
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner1, amount2, b'\x00' * 20, 0, 0)

    # Sign the transaction
    tx3.sign1(tx_key)
    tx3.sign2(tx_key)

    child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #9
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def test_send_tx_invalid_sig(child_chain):
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner1, amount2, b'\x00' * 20, 0, 0)

    # Sign with an invalid key
    tx3.sign1(invalid_tx_key)
    tx3.sign2(invalid_tx_key)

    with pytest.raises(InvalidTxSignatureException):
        child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #10
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def test_challenge_exit(t, u, root_chain, assert_tx_failed):
    owner, value_1, key = t.a1, 100, t.k1
    null_address = b'\x00' * 20
    tx1 = Transaction(0, 0, 0, 0, 0, 0, owner, value_1, null_address, 0, 0)
    deposit_tx_hash = get_deposit_hash(owner, value_1)
    utxo_pos1 = root_chain.getDepositBlock() * 1000000000 + 1
    root_chain.deposit(value=value_1, sender=key)
    utxo_pos2 = root_chain.getDepositBlock() * 1000000000
    root_chain.deposit(value=value_1, sender=key)
    merkle = FixedMerkle(16, [deposit_tx_hash], True)
    proof = merkle.create_membership_proof(deposit_tx_hash)
    confirmSig1 = confirm_tx(tx1, root_chain.getChildChain(utxo_pos1)[0], key)
    sigs = tx1.sig1 + tx1.sig2 + confirmSig1
    root_chain.startDepositExit(utxo_pos1, tx1.amount1, sender=key)
    tx3 = Transaction(utxo_pos2, 0, 0, 0, 0, 0, owner, value_1, null_address,
                      0, 0)
    tx3.sign1(key)
    tx_bytes3 = rlp.encode(tx3, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx3.merkle_hash], True)
    proof = merkle.create_membership_proof(tx3.merkle_hash)
    child_blknum = root_chain.currentChildBlock()
    root_chain.submitBlock(merkle.root)
    confirmSig = confirm_tx(tx3,
                            root_chain.getChildChain(child_blknum)[0], key)
    sigs = tx3.sig1 + tx3.sig2
    utxo_pos3 = child_blknum * 1000000000 + 10000 * 0 + 0
    tx4 = Transaction(utxo_pos1, 0, 0, 0, 0, 0, owner, value_1, null_address,
                      0, 0)
    tx4.sign1(key)
    tx_bytes4 = rlp.encode(tx4, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx4.merkle_hash], True)
    proof = merkle.create_membership_proof(tx4.merkle_hash)
    child_blknum = root_chain.currentChildBlock()
    root_chain.submitBlock(merkle.root)
    confirmSig = confirm_tx(tx4,
                            root_chain.getChildChain(child_blknum)[0], key)
    sigs = tx4.sig1 + tx4.sig2
    utxo_pos4 = child_blknum * 1000000000 + 10000 * 0 + 0
    oindex1 = 0
    assert root_chain.exits(utxo_pos1) == ['0x' + owner.hex(), 100]
    # Fails if transaction after exit doesn't reference the utxo being exited
    assert_tx_failed(lambda: root_chain.challengeExit(
        utxo_pos3, utxo_pos1, tx_bytes3, proof, sigs, confirmSig))
    # Fails if transaction proof is incorrect
    assert_tx_failed(lambda: root_chain.challengeExit(
        utxo_pos4, utxo_pos1, tx_bytes4, proof[::-1], sigs, confirmSig))
    # Fails if transaction confirmation is incorrect
    assert_tx_failed(lambda: root_chain.challengeExit(
        utxo_pos4, utxo_pos1, tx_bytes4, proof, sigs, confirmSig[::-1]))
    root_chain.challengeExit(utxo_pos4, oindex1, tx_bytes4, proof, sigs,
                             confirmSig)
    assert root_chain.exits(utxo_pos1) == [
        '0x0000000000000000000000000000000000000000', value_1
    ]
Beispiel #11
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def test_send_tx_double_spend(child_chain, u):
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner1, amount2, b'\x00' * 20, 0, 0)

    tx3.sign1(key1)
    tx3.sign2(key1)

    # Submit once
    child_chain.apply_transaction(rlp.encode(tx3).hex())

    # Try to submit again
    with pytest.raises(AssertionError):
        child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #12
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def test_send_tx_with_sig(child_chain):
    # Valid key
    key = b'8b76243a95f959bf101248474e6bdacdedc8ad995d287c24616a41bd51642965'

    newowner, amount2 = '0x4b3ec6c9dc67079e82152d6d55d8dd96a8e6aa26', 400
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner, amount2, b'\x00' * 20, 0, 0)

    # Sign the transaction
    tx3.sign1(key)
    tx3.sign2(key)

    child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #13
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def test_send_tx_double_spend(child_chain):
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner1, amount2, b'\x00' * 20, 0, 0)

    tx3.sign1(tx_key)
    tx3.sign2(tx_key)

    # Submit once
    child_chain.apply_transaction(rlp.encode(tx3).hex())

    # Try to submit again
    with pytest.raises(TxAlreadySpentException):
        child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #14
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def test_send_tx_invalid_sig(child_chain):
    # Invalid key
    key = b'8a76243a95f959bf101248474e6bdacdedc8ad995d287c24616a41bd51642965'

    newowner, amount2 = '0x4b3ec6c9dc67079e82152d6d55d8dd96a8e6aa26', 400
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner, amount2, b'\x00' * 20, 0, 0)

    # Sign with an invalid key
    tx3.sign1(key)
    tx3.sign2(key)

    with pytest.raises(AssertionError):
        child_chain.apply_transaction(rlp.encode(tx3).hex())
Beispiel #15
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    def transfer(self,
                 input1,
                 oindex1,
                 newowner1,
                 amount1,
                 signatory1,
                 input2=None,
                 oindex2=0,
                 newowner2=None,
                 amount2=None,
                 signatory2=None):
        newowner_address1 = newowner1['address']
        amount1 = int(amount1)

        newowner_address2 = NULL_ADDRESS
        if newowner2 is not None:
            newowner_address2 = newowner2['address']
        amount2 = int(amount2) if amount2 is not None else 0

        encoded_input_tx1 = rlp.encode(self.transactions[input1]['tx']).hex()
        blknum1, txindex1 = self.child_chain.get_tx_pos(encoded_input_tx1)

        blknum2, txindex2 = 0, 0
        if input2 is not None:
            encoded_input_tx2 = rlp.encode(
                self.transactions[input2]['tx']).hex()
            blknum2, txindex2 = self.child_chain.get_tx_pos(encoded_input_tx2)

        tx = Transaction(blknum1, txindex1, oindex1, blknum2, txindex2,
                         oindex2, newowner_address1, amount1,
                         newowner_address2, amount2)

        if signatory1 is not None:
            key1 = signatory1['key']
            tx.sign1(key1)

        if signatory2 is not None:
            key2 = signatory2['key']
            tx.sign2(key2)

        encoded_tx = rlp.encode(tx).hex()

        self.child_chain.apply_transaction(encoded_tx)

        self.transactions.append({
            'tx': tx,
            'confirm_sigs': b'',
            'is_deposit': False
        })
        return len(self.transactions) - 1
Beispiel #16
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def test_send_tx_double_spend(child_chain):
    key = b'8b76243a95f959bf101248474e6bdacdedc8ad995d287c24616a41bd51642965'

    newowner, amount2 = '0x4b3ec6c9dc67079e82152d6d55d8dd96a8e6aa26', 400
    tx3 = Transaction(1, 0, 0, 1, 1, 0, newowner, amount2, b'\x00' * 20, 0, 0)

    tx3.sign1(key)
    tx3.sign2(key)

    # Submit once
    child_chain.apply_transaction(rlp.encode(tx3).hex())

    # Try to submit again
    with pytest.raises(AssertionError):
        child_chain.apply_transaction(rlp.encode(tx3).hex())
    def create_partially_signed_transaction(self, from_contractaddress,
                                            to_contractaddress, amount):
        exchange_rate = self.get_exchange_rate(from_contractaddress,
                                               to_contractaddress, amount)
        if exchange_rate is None:
            return None
        provide_amount = amount * exchange_rate
        blknum1, txindex1, oindex1, contractaddress2, amount2, tokenid2 = self.create_utxo(
            to_contractaddress, provide_amount)

        ps_tx = Transaction(
            blknum1, txindex1, oindex1, 0, 0, 0,
            utils.normalize_address(self.address), b'\x00' *
            20 if from_contractaddress == "0x0" else from_contractaddress,
            amount, 0, b'\x00' * 20, contractaddress2, amount2, tokenid2)
        ps_tx.sign1(utils.normalize_key(plasma_config["AUTHORITY_KEY"]))
        return ps_tx.to_json()
Beispiel #18
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def sendtx(client, blknum1, txindex1, oindex1, blknum2, txindex2, oindex2,
           amount1, newowner1, amount2, newowner2, fee, key1, key2):
    if newowner1 == "0x0":
        newowner1 = NULL_ADDRESS
    if newowner2 == "0x0":
        newowner2 = NULL_ADDRESS

    # Form a transaction
    tx = Transaction(blknum1, txindex1, oindex1, blknum2, txindex2, oindex2,
                     utils.normalize_address(newowner1), amount1,
                     utils.normalize_address(newowner2), amount2, fee)

    # Sign it
    if key1:
        tx.sign1(utils.normalize_key(key1))
    if key2:
        tx.sign2(utils.normalize_key(key2))

    client_call(client.apply_transaction, [tx], "Sent transaction")
Beispiel #19
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 def send_tx(self):
     if len(self.inp) != 14 and len(self.inp) != 13:
         raise Exception(
             "Wrong number of inputs for sending a transaction!")
     blknum1, tx_pos1, utxo_pos1 = int(self.inp[1]), int(self.inp[2]), int(
         self.inp[3])
     blknum2, tx_pos2, utxo_pos2 = int(self.inp[4]), int(self.inp[5]), int(
         self.inp[6])
     newowner1 = utils.normalize_address(self.inp[7])
     amount1 = int(self.inp[8])
     newowner2 = utils.normalize_address(self.inp[9])
     amount2 = int(self.inp[10])
     fee = int(self.inp[11])
     key1 = utils.normalize_key(self.inp[12])
     key2 = utils.normalize_key(self.inp[13]) if len(
         self.inp) == 14 else b''
     tx = Transaction(blknum1, tx_pos1, utxo_pos1, blknum2, tx_pos2,
                      utxo_pos2, newowner1, amount1, newowner2, amount2,
                      fee)
     tx.sign1(key1)
     if key2:
         tx.sign2(key2)
     self.client.apply_transaction(tx)
     print("Succesfully added transaction!")
Beispiel #20
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def test_start_exit(t, root_chain, assert_tx_failed):
    week_and_a_half = 60 * 60 * 24 * 13
    owner, value_1, key = t.a1, 100, t.k1
    null_address = b'\x00' * 20
    tx1 = Transaction(0, 0, 0, 0, 0, 0, null_address, owner, value_1,
                      null_address, 0)
    deposit_tx_hash = get_deposit_hash(owner, null_address, value_1)
    dep_blknum = root_chain.getDepositBlock()
    assert dep_blknum == 1
    root_chain.deposit(value=value_1, sender=key)
    merkle = FixedMerkle(16, [deposit_tx_hash], True)
    proof = merkle.create_membership_proof(deposit_tx_hash)
    confirmSig1 = confirm_tx(tx1, root_chain.getChildChain(dep_blknum)[0], key)
    priority1 = dep_blknum * 1000000000 + 10000 * 0 + 1
    snapshot = t.chain.snapshot()
    sigs = tx1.sig1 + tx1.sig2 + confirmSig1
    utxoId = dep_blknum * 1000000000 + 10000 * 0 + 1
    # Deposit exit
    root_chain.startDepositExit(utxoId, null_address, tx1.amount1, sender=key)

    t.chain.head_state.timestamp += week_and_a_half
    # Cannot exit twice off of the same utxo
    utxo_pos1 = dep_blknum * 1000000000 + 10000 * 0 + 1
    assert_tx_failed(lambda: root_chain.startExit(
        utxo_pos1, deposit_tx_hash, proof, sigs, sender=key))
    enc_null_address = "0x" + "00" * 20
    assert root_chain.getExit(priority1) == [
        '0x' + owner.hex(), enc_null_address, 100
    ]
    t.chain.revert(snapshot)

    tx2 = Transaction(dep_blknum, 0, 0, 0, 0, 0, null_address, owner, value_1,
                      null_address, 0)
    tx2.sign1(key)
    tx_bytes2 = rlp.encode(tx2, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx2.merkle_hash], True)
    proof = merkle.create_membership_proof(tx2.merkle_hash)
    child_blknum = root_chain.currentChildBlock()
    assert child_blknum == 1000
    root_chain.submitBlock(merkle.root)
    confirmSig1 = confirm_tx(tx2,
                             root_chain.getChildChain(child_blknum)[0], key)
    priority2 = child_blknum * 1000000000 + 10000 * 0 + 0
    sigs = tx2.sig1 + tx2.sig2 + confirmSig1
    snapshot = t.chain.snapshot()
    # # Single input exit
    utxo_pos2 = child_blknum * 1000000000 + 10000 * 0 + 0
    root_chain.startExit(utxo_pos2, tx_bytes2, proof, sigs, sender=key)
    assert root_chain.getExit(priority2) == [
        '0x' + owner.hex(), enc_null_address, 100
    ]
    t.chain.revert(snapshot)
    dep2_blknum = root_chain.getDepositBlock()
    assert dep2_blknum == 1001
    root_chain.deposit(value=value_1, sender=key)
    tx3 = Transaction(child_blknum, 0, 0, dep2_blknum, 0, 0, null_address,
                      owner, value_1, null_address, 0, 0)
    tx3.sign1(key)
    tx3.sign2(key)
    tx_bytes3 = rlp.encode(tx3, UnsignedTransaction)
    merkle = FixedMerkle(16, [tx3.merkle_hash], True)
    proof = merkle.create_membership_proof(tx3.merkle_hash)
    child2_blknum = root_chain.currentChildBlock()
    assert child2_blknum == 2000
    root_chain.submitBlock(merkle.root)
    confirmSig1 = confirm_tx(tx3,
                             root_chain.getChildChain(child2_blknum)[0], key)
    confirmSig2 = confirm_tx(tx3,
                             root_chain.getChildChain(child2_blknum)[0], key)
    priority3 = child2_blknum * 1000000000 + 10000 * 0 + 0
    sigs = tx3.sig1 + tx3.sig2 + confirmSig1 + confirmSig2
    # Double input exit
    utxoPos3 = child2_blknum * 1000000000 + 10000 * 0 + 0
    root_chain.startExit(utxoPos3, tx_bytes3, proof, sigs, sender=key)
    assert root_chain.getExit(priority3) == [
        '0x' + owner.hex(), enc_null_address, 100
    ]