def test_bip68_not_consensus(self):
assert (get_bip9_status(self.nodes[0], 'csv')['status'] != 'active')
txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 2)
tx1 = from_hex(CTransaction(), self.nodes[0].getrawtransaction(txid))
tx1.rehash()
# Make an anyone-can-spend transaction
tx2 = CTransaction()
tx2.nVersion = 1
tx2.vin = [CTxIn(COutPoint(tx1.x16r, 0), n_sequence=0)]
tx2.vout = [
CTxOut(int(tx1.vout[0].nValue - self.relayfee * COIN),
CScript([b'a']))
]
# sign tx2
tx2_raw = self.nodes[0].signrawtransaction(to_hex(tx2))["hex"]
tx2 = from_hex(tx2, tx2_raw)
tx2.rehash()
self.nodes[0].sendrawtransaction(to_hex(tx2))
# Now make an invalid spend of tx2 according to BIP68
sequence_value = 100 # 100 block relative locktime
tx3 = CTransaction()
tx3.nVersion = 2
tx3.vin = [CTxIn(COutPoint(tx2.x16r, 0), n_sequence=sequence_value)]
tx3.vout = [
CTxOut(int(tx2.vout[0].nValue - self.relayfee * COIN),
CScript([b'a']))
]
tx3.rehash()
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
self.nodes[0].sendrawtransaction, to_hex(tx3))
# make a block that violates bip68; ensure that the tip updates
tip = int(self.nodes[0].getbestblockhash(), 16)
block = create_block(
tip, create_coinbase(self.nodes[0].getblockcount() + 1))
block.nVersion = 3
block.vtx.extend([tx1, tx2, tx3])
block.hashMerkleRoot = block.calc_merkle_root()
block.rehash()
block.solve()
self.nodes[0].submitblock(to_hex(block))
assert_equal(self.nodes[0].getbestblockhash(), block.hash)
def test_nonzero_locks(orig_tx, node, relayfee, use_height_lock):
sequence_value = 1
if not use_height_lock:
sequence_value |= SEQUENCE_LOCKTIME_TYPE_FLAG
tx = CTransaction()
tx.nVersion = 2
tx.vin = [
CTxIn(COutPoint(orig_tx.x16r, 0), n_sequence=sequence_value)
]
tx.vout = [
CTxOut(int(orig_tx.vout[0].nValue - relayfee * COIN),
CScript([b'a']))
]
tx.rehash()
if orig_tx.hash in node.getrawmempool():
# sendrawtransaction should fail if the tx is in the mempool
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
node.sendrawtransaction, to_hex(tx))
else:
# sendrawtransaction should succeed if the tx is not in the mempool
node.sendrawtransaction(to_hex(tx))
return tx
def test_disable_flag(self):
# Create some unconfirmed inputs
new_addr = self.nodes[0].getnewaddress()
self.nodes[0].sendtoaddress(new_addr, 2) # send 2 RVN
utxos = self.nodes[0].listunspent(0, 0)
assert (len(utxos) > 0)
utxo = utxos[0]
tx1 = CTransaction()
value = int(satoshi_round(utxo["amount"] - self.relayfee) * COIN)
# Check that the disable flag disables relative locktime.
# If sequence locks were used, this would require 1 block for the
# input to mature.
sequence_value = SEQUENCE_LOCKTIME_DISABLE_FLAG | 1
tx1.vin = [
CTxIn(COutPoint(int(utxo["txid"], 16), utxo["vout"]),
n_sequence=sequence_value)
]
tx1.vout = [CTxOut(value, CScript([b'a']))]
tx1_signed = self.nodes[0].signrawtransaction(to_hex(tx1))["hex"]
tx1_id = self.nodes[0].sendrawtransaction(tx1_signed)
tx1_id = int(tx1_id, 16)
# This transaction will enable sequence-locks, so this transaction should
# fail
tx2 = CTransaction()
tx2.nVersion = 2
sequence_value = sequence_value & 0x7fffffff
tx2.vin = [CTxIn(COutPoint(tx1_id, 0), n_sequence=sequence_value)]
tx2.vout = [CTxOut(int(value - self.relayfee * COIN), CScript([b'a']))]
tx2.rehash()
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
self.nodes[0].sendrawtransaction, to_hex(tx2))
# Setting the version back down to 1 should disable the sequence lock,
# so this should be accepted.
tx2.nVersion = 1
self.nodes[0].sendrawtransaction(to_hex(tx2))
def test_sequence_lock_confirmed_inputs(self):
# Create lots of confirmed utxos, and use them to generate lots of random
# transactions.
max_outputs = 50
addresses = []
while len(addresses) < max_outputs:
addresses.append(self.nodes[0].getnewaddress())
while len(self.nodes[0].listunspent()) < 200:
random.shuffle(addresses)
num_outputs = random.randint(1, max_outputs)
outputs = {}
for i in range(num_outputs):
outputs[addresses[i]] = random.randint(1, 20) * 0.01
self.nodes[0].sendmany("", outputs)
self.nodes[0].generate(1)
utxos = self.nodes[0].listunspent()
# Try creating a lot of random transactions.
# Each time, choose a random number of inputs, and randomly set
# some of those inputs to be sequence locked (and randomly choose
# between height/time locking). Small random chance of making the locks
# all pass.
for i in range(400):
# Randomly choose up to 10 inputs
num_inputs = random.randint(1, 10)
random.shuffle(utxos)
# Track whether any sequence locks used should fail
should_pass = True
# Track whether this transaction was built with sequence locks
using_sequence_locks = False
tx = CTransaction()
tx.nVersion = 2
value = 0
for j in range(num_inputs):
sequence_value = 0xfffffffe # this disables sequence locks
# 50% chance we enable sequence locks
if random.randint(0, 1):
using_sequence_locks = True
# 10% of the time, make the input sequence value pass
input_will_pass = (random.randint(1, 10) == 1)
sequence_value = utxos[j]["confirmations"]
if not input_will_pass:
sequence_value += 1
should_pass = False
# Figure out what the median-time-past was for the confirmed input
# Note that if an input has N confirmations, we're going back N blocks
# from the tip so that we're looking up MTP of the block
# PRIOR to the one the input appears in, as per the BIP68 spec.
orig_time = self.get_median_time_past(
utxos[j]["confirmations"])
cur_time = self.get_median_time_past(0) # MTP of the tip
# can only timelock this input if it's not too old -- otherwise use height
can_time_lock = True
if ((cur_time - orig_time) >> SEQUENCE_LOCKTIME_GRANULARITY
) >= SEQUENCE_LOCKTIME_MASK:
can_time_lock = False
# if time-lockable, then 50% chance we make this a time lock
if random.randint(0, 1) and can_time_lock:
# Find first time-lock value that fails, or latest one that succeeds
time_delta = sequence_value << SEQUENCE_LOCKTIME_GRANULARITY
if input_will_pass and time_delta > cur_time - orig_time:
sequence_value = ((cur_time - orig_time) >>
SEQUENCE_LOCKTIME_GRANULARITY)
elif not input_will_pass and time_delta <= cur_time - orig_time:
sequence_value = (
(cur_time - orig_time) >>
SEQUENCE_LOCKTIME_GRANULARITY) + 1
sequence_value |= SEQUENCE_LOCKTIME_TYPE_FLAG
tx.vin.append(
CTxIn(COutPoint(int(utxos[j]["txid"], 16),
utxos[j]["vout"]),
n_sequence=sequence_value))
value += utxos[j]["amount"] * COIN
# Overestimate the size of the tx - signatures should be less than 120 bytes, and leave 50 for the output
tx_size = len(to_hex(tx)) // 2 + 120 * num_inputs + 50
tx.vout.append(
CTxOut(int(value - self.relayfee * tx_size * COIN / 1000),
CScript([b'a'])))
rawtx = self.nodes[0].signrawtransaction(to_hex(tx))["hex"]
if using_sequence_locks and not should_pass:
# This transaction should be rejected
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
self.nodes[0].sendrawtransaction,
rawtx)
else:
# This raw transaction should be accepted
self.nodes[0].sendrawtransaction(rawtx)
utxos = self.nodes[0].listunspent()
def test_sequence_lock_unconfirmed_inputs(self):
# Store height so we can easily reset the chain at the end of the test
cur_height = self.nodes[0].getblockcount()
# Create a mempool tx.
txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 2)
tx1 = from_hex(CTransaction(), self.nodes[0].getrawtransaction(txid))
tx1.rehash()
# Anyone-can-spend mempool tx.
# Sequence lock of 0 should pass.
tx2 = CTransaction()
tx2.nVersion = 2
tx2.vin = [CTxIn(COutPoint(tx1.x16r, 0), n_sequence=0)]
tx2.vout = [
CTxOut(int(tx1.vout[0].nValue - self.relayfee * COIN),
CScript([b'a']))
]
tx2_raw = self.nodes[0].signrawtransaction(to_hex(tx2))["hex"]
tx2 = from_hex(tx2, tx2_raw)
tx2.rehash()
self.nodes[0].sendrawtransaction(tx2_raw)
# Create a spend of the 0th output of orig_tx with a sequence lock
# of 1, and test what happens when submitting.
# orig_tx.vout[0] must be an anyone-can-spend output
def test_nonzero_locks(orig_tx, node, relayfee, use_height_lock):
sequence_value = 1
if not use_height_lock:
sequence_value |= SEQUENCE_LOCKTIME_TYPE_FLAG
tx = CTransaction()
tx.nVersion = 2
tx.vin = [
CTxIn(COutPoint(orig_tx.x16r, 0), n_sequence=sequence_value)
]
tx.vout = [
CTxOut(int(orig_tx.vout[0].nValue - relayfee * COIN),
CScript([b'a']))
]
tx.rehash()
if orig_tx.hash in node.getrawmempool():
# sendrawtransaction should fail if the tx is in the mempool
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
node.sendrawtransaction, to_hex(tx))
else:
# sendrawtransaction should succeed if the tx is not in the mempool
node.sendrawtransaction(to_hex(tx))
return tx
test_nonzero_locks(tx2,
self.nodes[0],
self.relayfee,
use_height_lock=True)
test_nonzero_locks(tx2,
self.nodes[0],
self.relayfee,
use_height_lock=False)
# Now mine some blocks, but make sure tx2 doesn't get mined.
# Use prioritisetransaction to lower the effective feerate to 0
self.nodes[0].prioritisetransaction(txid=tx2.hash,
fee_delta=int(-self.relayfee *
COIN))
cur_time = int(time.time())
for _ in range(10):
self.nodes[0].setmocktime(cur_time + 600)
self.nodes[0].generate(1)
cur_time += 600
assert (tx2.hash in self.nodes[0].getrawmempool())
test_nonzero_locks(tx2,
self.nodes[0],
self.relayfee,
use_height_lock=True)
test_nonzero_locks(tx2,
self.nodes[0],
self.relayfee,
use_height_lock=False)
# Mine tx2, and then try again
self.nodes[0].prioritisetransaction(txid=tx2.hash,
fee_delta=int(self.relayfee *
COIN))
# Advance the time on the node so that we can test timelocks
self.nodes[0].setmocktime(cur_time + 600)
self.nodes[0].generate(1)
assert (tx2.hash not in self.nodes[0].getrawmempool())
# Now that tx2 is not in the mempool, a sequence locked spend should
# succeed
tx3 = test_nonzero_locks(tx2,
self.nodes[0],
self.relayfee,
use_height_lock=False)
assert (tx3.hash in self.nodes[0].getrawmempool())
self.nodes[0].generate(1)
assert (tx3.hash not in self.nodes[0].getrawmempool())
# One more test, this time using height locks
tx4 = test_nonzero_locks(tx3,
self.nodes[0],
self.relayfee,
use_height_lock=True)
assert (tx4.hash in self.nodes[0].getrawmempool())
# Now try combining confirmed and unconfirmed inputs
tx5 = test_nonzero_locks(tx4,
self.nodes[0],
self.relayfee,
use_height_lock=True)
assert (tx5.hash not in self.nodes[0].getrawmempool())
utxos = self.nodes[0].listunspent()
tx5.vin.append(
CTxIn(COutPoint(int(utxos[0]["txid"], 16), utxos[0]["vout"]),
n_sequence=1))
tx5.vout[0].nValue += int(utxos[0]["amount"] * COIN)
raw_tx5 = self.nodes[0].signrawtransaction(to_hex(tx5))["hex"]
assert_raises_rpc_error(-26, NOT_FINAL_ERROR,
self.nodes[0].sendrawtransaction, raw_tx5)
# Test mempool-BIP68 consistency after reorg
#
# State of the transactions in the last blocks:
# ... -> [ tx2 ] -> [ tx3 ]
# tip-1 tip
# And currently tx4 is in the mempool.
#
# If we invalidate the tip, tx3 should get added to the mempool, causing
# tx4 to be removed (fails sequence-lock).
self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
assert (tx4.hash not in self.nodes[0].getrawmempool())
assert (tx3.hash in self.nodes[0].getrawmempool())
# Now mine 2 empty blocks to reorg out the current tip (labeled tip-1 in
# diagram above).
# This would cause tx2 to be added back to the mempool, which in turn causes
# tx3 to be removed.
tip = int(
self.nodes[0].getblockhash(self.nodes[0].getblockcount() - 1), 16)
height = self.nodes[0].getblockcount()
for _ in range(2):
block = create_block(tip, create_coinbase(height), cur_time)
block.nVersion = 3
block.rehash()
block.solve()
tip = block.x16r
height += 1
self.nodes[0].submitblock(to_hex(block))
cur_time += 1
mempool = self.nodes[0].getrawmempool()
assert (tx3.hash not in mempool)
assert (tx2.hash in mempool)
# Reset the chain and get rid of the mocktimed-blocks
self.nodes[0].setmocktime(0)
self.nodes[0].invalidateblock(self.nodes[0].getblockhash(cur_height +
1))
self.nodes[0].generate(10)