def match(sig, pubs, msg): # for every pubkey in pubs for p in pubs: # verify is a simple verification method for signed messages if tools.verify(msg, sig, p): return {'bool': True, 'pub': p} return {'bool': False}
def spend_verify(tx, txs, DB): tx_copy=copy.copy(tx) tx_copy.pop('signature') msg=tools.det_hash(tx_copy) if not tools.verify(msg, tx['signature'], tx['id']): return False if tx['amount']<custom.fee: return False if int(blockchain.db_get(tx['id'], DB)['amount'])<int(tx['amount']): return False return True
def sigs_match(sigs, pubs, msg): for sig in sigs: for pub in pubs: try: if tools.verify(msg, sig, pub): sigs.remove(sig) pubs.remove(pub) except: pass return len(sigs)==0
def sigs_match(sigs, pubs, msg): for sig in sigs: for pub in pubs: try: if tools.verify(msg, sig, pub): sigs.remove(sig) pubs.remove(pub) except: pass return len(sigs) == 0
62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450""" numstr = "".join(numstr_readable.split()) # Answer: # 40824 def solve(): return xiter (xrange(len(numstr) - 4)) \ .map (lambda start: numstr[start:start + 5]) \ .map (lambda substring: xiter(int(n) for n in substring)) \ .map (lambda numbers: numbers.product()) \ .max() verify(solve(), 40824)
# Each new term in the Fibonacci sequence is generated by adding the previous two # terms. By starting with 1 and 2, the first 10 terms will be: # 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... # By considering the terms in the Fibonacci sequence whose values do not exceed # four million, find the sum of the even-valued terms. # Answer: # 4613732 from tools import fibonacci, divides, verify def solve(): return fibonacci() \ .takewhile (lambda n: n <= 4000000) \ .filter (lambda n: divides(2, n)) \ .sum() verify(solve(), 4613732)
def sigs_match(sigs, pubs, msg): return all(tools.verify(msg, sig, pub) for sig in sigs for pub in pubs)
# 2520 is the smallest number that can be divided by each of the numbers from 1 to # 10 without any remainder. # What is the smallest positive number that is evenly divisible by all of the # numbers from 1 to 20? # Answer: # 232792560 from tools import factors, verify def solve(): return factors(*range(1, 21), reduce_with = max).product() verify(solve(), 232792560)
# If we list all the natural numbers below 10 that are multiples of 3 or 5, we # get 3, 5, 6 and 9. The sum of these multiples is 23. # Find the sum of all the multiples of 3 or 5 below 1000. # Answer: # 233168 from xiter import xiter from tools import verify, divides def solve(): return xiter(xrange(1, 1000)) \ .filter (lambda n: divides(3, n) or divides(5, n)) \ .sum() verify(solve(), 233168)
def match(sig, pubs, msg): for p in pubs: if tools.verify(msg, sig, p): return {'bool':True, 'pub':p} return {'bool':False}
# The sum of the squares of the first ten natural numbers is, # 12 + 22 + ... + 102 = 385 # # The square of the sum of the first ten natural numbers is, # (1 + 2 + ... + 10)2 = 552 = 3025 # # Hence the difference between the sum of the squares of the first ten natural # numbers and the square of the sum is 3025 385 = 2640. # Find the difference between the sum of the squares of the first one hundred # natural numbers and the square of the sum. # Answer: # 25164150 from tools import verify, naturals def square(x): return x ** 2 def solve(): i1, i2 = naturals().slice(100).tee(2) return square(i2.sum()) - i1.map(square).sum() verify(solve(), 25164150)
# The prime factors of 13195 are 5, 7, 13 and 29. # What is the largest prime factor of the number 600851475143 ? # Answer: # 6857 from tools import factors, verify def solve(): return factors(600851475143).max() verify(solve(), 6857)
# A palindromic number reads the same both ways. The largest palindrome made # from the product of two 2-digit numbers is 9009 = 91 99. # Find the largest palindrome made from the product of two 3-digit numbers. # Answer: # 906609 from xiter import xiter from tools import verify, is_palindrome def products(): for x in xrange(100, 1000): for y in xrange(100, x): yield x * y def solve(): return xiter(products()) \ .filter(is_palindrome) \ .max() verify(solve(), 906609)
def verify_transaction(self, transaction, sender_pk): return verify(sender_pk, transaction.signature, transaction.hash_val)
def block_check(block): def log_(txt): pass # return tools.log(txt) def check_txs(txs): start = copy.deepcopy(txs) out = [] start_copy = [] # until starting copy of transactions are empty while start != start_copy: if start == []: return False # Block passes this test start_copy = copy.deepcopy(start) # if transaction is valid, then add the transaction to the out list if transactions.tx_check[start[-1]['type']](start[-1], out, ['']): out.append(start.pop()) else: return True # Block is invalid return True # Block is invalid # if block is not a dict, return false if not isinstance(block, dict): return False # block contains error if 'error' in block: return False # E_check function is responsible for checking the block(dict) if it has a length attribute which is int if not tools.E_check(block, 'length', [int]): log_('no length') return False # get the length of blockchain length = tools.db_get('length') # check length if it is integer, yeah yeah we have done that so what? if type(block['length']) != type(1): log_('wrong length type') return False # check length condition. It must be one bigger than our current blockchain length, or we would be missing something if int(block['length']) != int(length) + 1: log_('wrong longth') return False # checking if prevHash was actually the previous block's hash if length >= 0: if tools.det_hash(tools.db_get(length)) != block['prevHash']: log_('det hash error') return False # --------------------- START OF THE NEW PROOF-OF-WORK CHECK--------------------------------- # Returns a dictionary with auth_sign and halfHash of block. # Authority must sign the block with its pubkey. This way, we are going to know which authority signed the block half_way = tools.make_half_way(block) if not half_way.get('auth_pubkey') in tools.db_get('authorities'): print 'no auth pubkey' return False if not tools.verify(half_way.get('halfHash'), half_way.get('auth_sign'), half_way.get('auth_pubkey')): print 'no verify' return False # --------------------- END OF THE NEW PROOF-OF-WORK CHECK----------------------------------- # recent_blockthings returns a map with get_val function and range starting from 100 early blocks to most recent block # then earliest is the median of sorted blocks earliest = median(recent_blockthings('times', custom.mmm)) # time has to be present in block if 'time' not in block: log_('no time') return False # it is late to check this block if block['time'] > time.time() + 60 * 6: log_('too late') return False # block does not seem to be created at correct time if block['time'] < earliest: log_('too early') return False # check the transactions in the block # this function returns True on negative situation, because f**k the logic! # please someone fix this. I left it for now to show how a joken source this project is! if check_txs(block['txs']): log_('tx check') return False return True
# By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see # that the 6th prime is 13. # What is the 10.001st prime number? # Answer: # 104743 from tools import primes, verify def solve(): return primes().drop(10000).next() verify(solve(), 104743)
# The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. # Find the sum of all the primes below two million. # Answer: # 142913828922 from tools import verify, primes def solve(): return primes() \ .takewhile(lambda prime: prime < 2000000) \ .sum() verify(solve(), 142913828922)
def match(sig, pubs, msg): for p in pubs: if tools.verify(msg, sig, p): return {"bool": True, "pub": p} return {"bool": False}
def match(sig, pubs, msg): for p in pubs: if tools.verify(msg, sig, p): return {'bool': True, 'pub': p} return {'bool': False}
# A Pythagorean triplet is a set of three natural numbers, a b c, for which, # a**2 + b**2 = c**2 # For example, 32 + 42 = 9 + 16 = 25 = 52. # There exists exactly one Pythagorean triplet for which a + b + c = 1000. # Find the product abc. # Answer: # 31875000 from xiter import xiter from tools import verify def triplets(): for x in xrange(1, 999): for y in xrange(1, 1000 - x): yield (x, y, 1000 - x - y) def solve(): ntuple = xiter(triplets()) \ .filter(lambda (x, y, z): x**2 + y**2 == z**2) \ .next() return reduce(lambda x, y: x * y, ntuple) verify(solve(), 31875000)