def test_get_timer_recursive(self):
"""
If a function acquires a countdown timer with default scope,
then recursive calls to the function should re-acquire the
timer rather than creating a new one. That is only the last
recursive call's timer will take effect.
"""
self.server.start()
timer.configure(timer.LocalTimerClient(self.mp_queue))
# func should not time out
def func(n):
if n > 0:
with timer.expires(after=0.1):
func(n - 1)
time.sleep(0.05)
func(4)
# func2 should time out
def func2(n):
if n > 0:
with timer.expires(after=0.1):
func2(n - 1)
time.sleep(0.2)
p = mp.Process(target=func2, args=(2, ))
p.start()
p.join()
self.assertEqual(-signal.SIGKILL, p.exitcode)
def _stuck_function(rank, mp_queue):
timer.configure(timer.LocalTimerClient(mp_queue))
with timer.expires(after=1):
time.sleep(5)
def _run(mp_queue, timeout, duration):
client = timer.LocalTimerClient(mp_queue)
timer.configure(client)
with timer.expires(after=timeout):
time.sleep(duration)
def test_happy_path(self):
timer.configure(timer.LocalTimerClient(self.mp_queue))
with timer.expires(after=0.5):
time.sleep(0.1)
def test_no_client(self):
# no timer client configured; exception expected
timer.configure(None)
with self.assertRaises(RuntimeError):
with timer.expires(after=1):
pass
