def max_linear_flow(Diam, HeadlossCDC, Ratio_Error, KMinor):
"""Return the maximum flow that will meet the linear requirement.
Maximum flow that can be put through a tube of a given diameter without
exceeding the allowable deviation from linear head loss behavior
"""
flow = (pc.area_circle(Diam)).magnitude * np.sqrt(
(2 * Ratio_Error * HeadlossCDC * pc.gravity) / KMinor)
return flow.magnitude
def lfom_drillbit_area(FLOW, HL_LFOM, drill_series_uom):
return pc.area_circle(
lfom_drillbit_diameter(FLOW, HL_LFOM, drill_series_uom))
def drillbit_area(FLOW, HL_LFOM, drill_bits):
return pc.area_circle(orifice_diameter(FLOW, HL_LFOM, drill_bits))
def __drillbit_area(self):
return pc.area_circle(self.drillbit_diameter())
from aide_design import physchem as pc from aide_design.units import unit_registry as u from aide_design import utility as ut # h_drive = height of drive pipe # A_drive = Area of drive pipe # x_max = maximum spring compression distance, equal to plate ampltitude # h_eff = Necessary pumping height # A_eff = Area of effluent flow # Minimum force balance # k_min = minimum k value needed to open from closed position temp = u.Quantity(22, u.degC) # Assume room temperature. rho = pc.density_water(temp) g = pc.gravity x_max = .045 * u.m h_drive = .51 * u.m d_drive = 0.025273 * u.m A_drive = pc.area_circle(d_drive) P_hydrostatic = rho * g * h_drive k_min = P_hydrostatic * A_drive / x_max # Equation for k value # k = EA/L # L_opt = optimal spring length # A_spring = Area of spring # Spring force = rho*g*h_drive*A_drive = E*A_spring*x/L # L_opt = E*A_spring*x/(rho*g*h_drive*A_drive)