def circle_area_microservice():
try:
radius = float(request.query.get('radius', '0.0'))
except ValueError:
radius = 0.0
area = algebra.area(radius)
return dict(service=request.path, radius=radius, area=area)
def circle_area_service():
response.set_header('Cache-Control', 'max-age=15')
try:
radius = float(request.query.get('radius', '0.0'))
except ValueError:
return dict(error='Must supply a floating point radius')
area = algebra.area(radius)
return dict(area=area, radius=radius, service=request.path)
except RuntimeError:
raise ValueError('Negative base or height not supported, use positive inputs instead')
algebra.area_triangle = better_area_triangle # Step 3: Monkey patch
orig_sqrt = math.sqrt # Step 1: Save reference to original
def better_sqrt(x): # Step 2: Write a wrapper function
'Wraps math.sqrt to add support for negative inputs'
if x >= 0.0:
return orig_sqrt(x)
return orig_sqrt(-x) * 1j
math.sqrt = better_sqrt # Step 3: Monkey patch
#############################################################################
if __name__ == '__main__':
print u'My sources tell me that \N{greek small letter pi} =', algebra.pi
print 'and that the area of a circle of radius ten is:', algebra.area(10)
print 'The area of the 1st triangle is', algebra.area_triangle(base=25, height=10)
try:
print 'The area of the 2nd triangle is', algebra.area_triangle(base=-5, height=20)
except ValueError:
print '... oops, I did it again!'
print u'The solutions to 12x\N{superscript two} + 23x + 10 = 0 are:'
print algebra.quadratic(a=12, b=23, c=10)
print u'The solutions to 12x\N{superscript two} + 8x + 10 = 0 are:'
print algebra.quadratic(a=12, b=8, c=10)
# -*- coding: utf-8 -*- """ Created on Fri Jan 19 10:02:54 2018 @author: md1eeb """ import algebra as c r = 5 print(c.area(r)) print(c.circumference(r)) from algebra import area r = 5 print(area(r)) from algebra import quad as q a = 1 b = 9 c = 6 print(q(a, b, c)) from algebra import largest list1 = [4, 6, 2, 4, 8, 12, 7] print(largest(list1)) """"""
raise ValueError('negative base or height not supported')
algebra.area_triangle = better_area_triangle # Step 3: monkey patch
orig_sqrt = math.sqrt # Step 1: Save the original function
def better_sqrt(x): # Step 2: Write a wrapper function
"Wrap math.sqrt() to add support for negative values."
if x >= 0.0:
return orig_sqrt(x)
else:
return orig_sqrt(-x) * 1j
math.sqrt = better_sqrt # Step 3: Monkey patch
if __name__ == '__main__':
print u'My sources tell me that \N{greek small letter pi} =', algebra.PI
print 'and that the unit circle has area', algebra.area(1)
print 'The area of the 1st triangle is', algebra.area_triangle(7, 5)
try:
print 'The area of the 2nd triangle is', algebra.area_triangle(-5, 10)
except ValueError:
print 'Doh! Sorry for the negative input'
print u'The solutions to 12x\N{superscript two} + 23x + 10 = 0 are:'
print algebra.quadratic(a=12, b=23, c=10)
print u'The solutions to 12x\N{superscript two} + 8x + 10 = 0 are:'
print algebra.quadratic(12, 8, 10)