Ejemplo n.º 1
0
 def test_dendrogramComputation(self):
     d = Dendrogram(self.data, minimum_npix=8, minimum_delta=0.3, minimum_flux=1.4, verbose=False)
     
     num_leaves = len(d.get_leaves())
     self.assertEqual(num_leaves,55) # This data with these parameters should produce 55 leaves
     
     # Now check every pixel in the data cube (this takes a while).
     # The following loop construct may look crazy, but it is a more
     # efficient way of iterating through the array than using a regular
     # nditer with multi_index.
     for coord in np.array(np.unravel_index( np.arange(self.data.size), self.data.shape)).transpose():
         coord = tuple(coord)
         f = self.data[coord]
         if (f < 1.4):
             self.assertEqual(d.item_at(coord), None)
         else:
             item = d.item_at(coord)
             if item:
                 # The current pixel is associated with part of the dendrogram.
                 self.assertIn(coord, item.coords, "Pixel at {0} is claimed to be part of {1}, but that item does not contain the coordinate {0}!".format(coord, item))
                 fmax_item, _, fmax = item.get_peak_recursive()
                 if fmax_item is item:
                     # The current pixel is the peak pixel in this item
                     pass
                 else:
                     self.assertTrue(fmax >= f)
Ejemplo n.º 2
0
 def test_4dim(self):
     " Test 4-dimensional data "
     data = np.zeros((5,5,5,5)) # Create a 5x5x5x5 array initialized to zero
     # N-dimensional data is hard to conceptualize so I've kept this simple.
     # Create a local maximum (value 5) at the centre
     data[2,2,2,2] = 5
     # add some points around it of intensity 3. Note that '1:4:2' is equivalent to saying indices '1' and '3'
     data[2,1:4:2,2,2] = data[2,2,1:4:2,2] = data[2,2,2,1:4:2] = 3
     # Add a trail of points of value 2 connecting one of those 3s to a 4
     data[0:3,0,2,2] = 2 # Sets [0,0,2,2], [1,0,2,2], and [2,0,2,2] all equal to 2 -> will connect to the '3' at [2,1,2,2]
     data[0,0,2,1] = 4
     
     # Now dendrogram it:
     d = Dendrogram(data, minimum_flux=1, verbose=False)
     # We expect two leaves:
     leaves = d.get_leaves()
     self.assertEqual(len(leaves), 2)
     # We expect one branch:
     branches = [i for i in d.all_items if type(i) is Branch]
     self.assertEqual(len(branches), 1)
     self.assertEqual(len(d.trunk), 1)
     self.assertEqual(d.trunk[0], branches[0])
     
     # The maxima of each leaf should be at [2,2,2,2] and [0,3,2,1]
     for leaf in leaves:
         self.assertIn(leaf.peak, ( ((2,2,2,2), 5.), ((0,0,2,1),4.) ) )
     self.assertNotEqual(leaves[0].peak, leaves[1].peak)
     
     # Check out a few more properties of the leaf around the global maximum:
     leaf = d.item_at((2,2,2,2))
     self.assertEqual(leaf.fmax, 5)
     self.assertEqual(leaf.fmin, 2)
     self.assertEqual(leaf.npix, 1+6+2) # Contains 1x '5', 6x '3', and 2x '2'. The other '2' should be in the branch
     # Check that the only pixel in the branch is a '2' at [0,0,2,2]
     self.assertEqual((branches[0].coords, branches[0].f), ( [(0,0,2,2),],[2.,] )) 
Ejemplo n.º 3
0
 def test_computing_level(self):
     d = Dendrogram(self.data, verbose=False)
     
     # Now pick an item near the middle of the dendrogram:
     mid_item = d.item_at((0, self.size//2))
     
     # Compute its level:
     sys.setrecursionlimit(100000)
     _ = mid_item.level
     
     # Now check the .level property of all items, in random order:
     import random
     items = random.sample(list(d.all_items), len(d.items_dict))
     for item in items:
         obj = item
         level = item.level
         while level > 0:
             obj = obj.parent
             level -= 1
         self.assertEqual(obj.parent, None)
         self.assertEqual(obj.level, 0)