def get_topmost_junction(cell: Cell) -> str:
# special case for 1st row's junctions
#
# [ X ] [X-east]
#
junction = UnicodeExporter.EAST + UnicodeExporter.WEST
if not cell.linked_to(cast(Cell, cell.east)):
junction += UnicodeExporter.SOUTH
return UnicodeExporter.JUNCTIONS[junction]
def test_linking() -> None:
a_cell = Cell(1, 1)
another_cell = Cell(1, 2)
yet_another_cell = Cell(2, 1)
assert a_cell.linked_to(another_cell) is False
assert another_cell.linked_to(a_cell) is False
assert a_cell.linked_to(yet_another_cell) is False
assert another_cell.linked_to(yet_another_cell) is False
a_cell.link(another_cell)
assert a_cell.linked_to(another_cell) is True
assert another_cell.linked_to(a_cell) is True
assert a_cell.linked_to(yet_another_cell) is False
assert another_cell.linked_to(yet_another_cell) is False
def get_south_east_junction(cell: Cell) -> str:
# Taking advantage that we always go forward east and south, just need to calculate available posibilities
#
# [ X ] [X-east]
#
# [ X-south] [X-southeast]
#
junction = 0
if cell.east:
if not cell.linked_to(cell.east):
junction += UnicodeExporter.NORTH
if not cell.east.south:
junction += UnicodeExporter.EAST
else:
junction += UnicodeExporter.NORTH
if cell.south:
if not cell.linked_to(cell.south):
junction += UnicodeExporter.WEST
if not cell.south.east:
junction += UnicodeExporter.SOUTH
else:
junction += UnicodeExporter.WEST
if cell.east and cell.south:
south_east_cell = cast(Cell, cell.south.east)
if not cell.east.linked_to(south_east_cell):
junction += UnicodeExporter.EAST
if not cell.south.linked_to(south_east_cell):
junction += UnicodeExporter.SOUTH
try:
return UnicodeExporter.JUNCTIONS[junction]
except IndexError as ie:
print("junction:{} error:{}".format(junction, ie))
return " "
def get_leftmost_junction(cell: Cell) -> str:
#
# [ X ]
#
# [ X-south]
#
junction = UnicodeExporter.NORTH
if cell.south:
junction += UnicodeExporter.SOUTH
if not cell.linked_to(cell.south):
junction += UnicodeExporter.EAST
else:
junction += UnicodeExporter.EAST
return UnicodeExporter.JUNCTIONS[junction]