Ejemplo n.º 1
0
 def insertIntoBST(self, root: TreeNode, val: int) -> TreeNode:
     if not root: return TreeNode(val)
     if val > root.val:
         root.right = self.insertIntoBST(root.right, val)
     else:
         root.left = self.insertIntoBST(root.left, val)
     return root
Ejemplo n.º 2
0
# def inorderTraversalTest(root: TreeNode) -> List[int]:
#     stack, res = [root], []
#     # 中序是先左后中后右
#     while stack:
#         temp = stack.pop()
#         if temp:
#             if temp.left:
#                 stack.append(temp.left)
#                 res.append(temp.left.val)
#             if temp.right:
#                 stack.append(temp.right)
#             res.append(temp.val)
#     return res

if __name__ == '__main__':
    tree = TreeNode(6)
    tree.left = TreeNode(8)
    tree.right = TreeNode(4)
    # tree.left.left = TreeNode(9)
    # tree.left.right = TreeNode(7)
    # tree.right.left = TreeNode(5)
    # tree.right.right = TreeNode(3)
    print(bfs(tree))
    print("---------")
    print(dfs(tree))
    print('---------')
    print(f'inorder is {inorderTraversal(tree)}')
    print(f'dfs preorder is {dfsPreorder(tree)}')
    print(f'dfs postorder is {dfsPostorder(tree)}')
    # print(f'inorderTravsalTest is {inorderTraversalTest(tree)}')
Ejemplo n.º 3
0
from base.tree.tree_node import TreeNode


class Solution:
    def lowestCommonAncestor(self, root: TreeNode, p: TreeNode, q: TreeNode) -> TreeNode:
        if root is None:
            return None
        if root == p or root == q:
            return root
        left = self.lowestCommonAncestor(root.left, p, q)
        right = self.lowestCommonAncestor(root.right, p, q)
        if left and right:
            return root
        if left is None and right is None:
            return None
        if left is None:
            return right
        else:
            return left


if __name__ == '__main__':
    root = [6, 2, 8, 0, 4, 7, 9, None, None, 3, 5]
    p = 2
    q = 8
    tree = TreeNode.from_list(root)
    print(tree)
Ejemplo n.º 4
0
class Solution:
    def isUnivalTree(self, root: TreeNode) -> bool:
        res = []

        def dfs(root):
            queue = [root]
            while queue:
                element = queue.pop(0)
                res.append(element.val)
                if element.left:
                    dfs(root.left)
                if element.right:
                    dfs(root.right)

        dfs(root)
        return len(set(res)) == 1


if __name__ == '__main__':
    sol = Solution()
    tree = TreeNode.from_list([
        2,
        2,
        2,
        2,
        5,
    ])
    print(tree)
    print(sol.isUnivalTree(tree))
Ejemplo n.º 5
0
from base.tree.tree_node import TreeNode


class Solution:
    def convertBST(self, root: TreeNode) -> TreeNode:
        pass


if __name__ == '__main__':
    a = TreeNode.from_list(
        [4, 1, 6, 0, 2, 5, 7, None, None, None, 3, None, None, None, 8])
    sol = Solution()
    print(sol.convertBST(a))
Ejemplo n.º 6
0
# Definition for a binary tree node.
from base.tree.tree_node import TreeNode


class Solution:
    def deleteNode(self, root: TreeNode, key: int) -> TreeNode:
        pass


if __name__ == '__main__':
    b = [5, 3, 6, 2, 4, None, 7]
    t = TreeNode.from_list(b)
    print(t)
Ejemplo n.º 7
0
from base.tree.tree_node import TreeNode


class Solution:
    # TODO
    def mergeTrees(self, root1: TreeNode, root2: TreeNode) -> TreeNode:
        pass


if __name__ == '__main__':
    root1 = TreeNode()
    root2 = TreeNode()
    sol = Solution()
    print(sol.mergeTrees(root1, root2))
from base.tree.tree_node import TreeNode


class Solution:
    def findBottomLeftValue(self, root: TreeNode) -> int:
        level_values, queue = [], [root]
        while queue:
            next_level, curr_vals = [], []
            for i in queue:
                if i.val is not None:
                    curr_vals.append(i.val)
                if i.left:
                    next_level.append(i.left)
                if i.right:
                    next_level.append(i.right)
            queue = next_level
            level_values = curr_vals
        return level_values[0]


if __name__ == '__main__':
    tree = TreeNode.from_list([2, 1, 3])
    sol = Solution()
    print(sol.findBottomLeftValue(tree))
Ejemplo n.º 9
0
        if root is None:
            return 0
        result, queue = [], [root]
        while queue:
            next_level, vals = [], []
            for node in queue:
                if node.val is not None:
                    vals.append(node.val)
                    if node.left:
                        next_level.append(node.left)
                    if node.right:
                        next_level.append(node.right)
            queue = next_level
            result.append(vals)
        odd = 0
        even = 0
        for i, v in enumerate(result):
            if i % 2 == 0:
                even += sum(v)
            else:
                odd += sum(v)
        return max(odd, even)


if __name__ == '__main__':
    sol = Solution()
    # tree = TreeNode.from_list([3, 2, 3, None, 3, None, 1])
    tree = TreeNode.from_list([4, 1, None, 2, None, 3])
    print(tree)
    print(sol.rob(tree))
 def mirrorTree(self, root: TreeNode) -> Optional[TreeNode]:
     if not root:
         return
     root.left, root.right = self.mirrorTree(root.right), self.mirrorTree(
         root.left)
     return root
from base.tree.tree_node import TreeNode
from typing import Optional


class Solution:
    def mirrorTree(self, root: TreeNode) -> Optional[TreeNode]:
        if not root:
            return
        root.left, root.right = self.mirrorTree(root.right), self.mirrorTree(
            root.left)
        return root


if __name__ == '__main__':
    tree = TreeNode.from_list([4, 2, 7, 1, 3, 6, 9])
    sol = Solution()
    a = sol.mirrorTree(tree)
    print(a)
Ejemplo n.º 12
0
#  todo
#  错误的,想仿照排列数和组合数进行回溯,因为是树型结构,但是没成功
class Solution:
    def pathSum(self, root: TreeNode, total: int) -> List[List[int]]:
        res = []

        def dfs(root: TreeNode, total: int, one_ans):
            if sum(one_ans) == total:
                res.append(one_ans)
            if root.left:
                one_ans.append(root.val)
                dfs(root.left, total, one_ans)
                one_ans.pop()
            if root.right:
                one_ans.append(root.val)
                dfs(root.right, total, one_ans)
                one_ans.pop()

        one_ans = []
        dfs(root, total, one_ans)
        return res


if __name__ == '__main__':
    tree = TreeNode.from_list(
        [5, 4, 8, 11, None, 13, 4, 7, 2, None, None, None, None, 5, 1])
    print(tree)
    sol = Solution()
    print(sol.pathSum(tree, 22))
Ejemplo n.º 13
0
from base.tree.tree_node import TreeNode


class Solution:
    def minDiffInBST(self, root: TreeNode) -> int:
        res = []

        def inorder(root: TreeNode):
            if root:
                inorder(root.left)
                if root.val is not None:
                    res.append(root.val)
                inorder(root.right)

        inorder(root)
        min_val = float("inf")
        for i in range(1, len(res)):
            val = res[i] - res[i - 1]
            if val < min_val:
                min_val = val
        return min_val


if __name__ == '__main__':
    sol = Solution()
    tree = TreeNode.bst_from_list([4, 2, 6, 1, 3])
    a = sol.minDiffInBST(tree)
    print(a)
Ejemplo n.º 14
0
from base.tree.tree_node import TreeNode


class Solution:
    def kthSmallest(self, root: TreeNode, k: int) -> int:
        a = []

        def inorder(root, a):
            if len(a) == k:
                return
            if root:
                inorder(root.left, a)
                a.append(root.val)
                inorder(root.right, a)

        inorder(root, a)
        return a[k - 1]


if __name__ == '__main__':
    treeNode = TreeNode(3)
    treeNode.left = TreeNode(1)
    treeNode.right = TreeNode(4)
    treeNode.left.right = TreeNode(2)
    sol = Solution()
    print(sol.kthSmallest(treeNode, 1))
Ejemplo n.º 15
0
        #  Tree problem -> travserd -> two parts -> the second part need some element
        # 1. None ->  True
        # 2. False
        # 3. travserd the  until True or Flase
        # ptr is ALL
        if root is None:
            return True
        if root.val <= largerThan or root.val >= lessThan:
            return False
        return self.isValidBSTRec(root.left, min(
            lessThan, root.val), largerThan) and self.isValidBSTRec(
                root.right, lessThan, max(root.val, largerThan))


if __name__ == '__main__':
    tree1 = TreeNode(2)
    tree1.left = TreeNode(1)
    tree1.right = TreeNode(3)
    sol = Solution()
    assert sol.isValidBST(tree1) == True

    tree2 = TreeNode(5)
    tree2.left = TreeNode(1)
    tree2.right = TreeNode(4)
    tree2.right.left = TreeNode(3)
    tree2.right.right = TreeNode(6)
    assert sol.isValidBST(tree2) == False

    tree3 = TreeNode(1)
    tree3.left = TreeNode(1)
    assert sol.isValidBST(tree3) == False
Ejemplo n.º 16
0
            return True

        res, queue = [], [root]
        a = 1
        while queue:
            next_level, curr_vals = [], []
            for i in queue:
                if i and i.val is not None:
                    curr_vals.append(i.val)
                if i.left:
                    next_level.append(i.left)
                if i.right:
                    next_level.append(i.right)
            queue = next_level
            if a % 2 == 1:
                if is_odd(curr_vals) is False:
                    return False
            else:
                if is_even(curr_vals) is False:
                    return False
            a += 1
        return True


if __name__ == '__main__':
    tree = TreeNode.from_list([1, 10, 4, 3, None, 7, 9, 12, 8, 6, None, None, 2])

    sol = Solution()
    t = sol.isEvenOddTree(tree)
    print(t)
Ejemplo n.º 17
0
from collections import deque

from base.tree.tree_node import TreeNode


class Solution:
    def levelOrder(self, root: TreeNode):
        if root is None:
            return []
        result, queue = [], [root]
        while queue:
            next_level, curr_vals = [], []
            for node in queue:
                if node.val is not None:
                    curr_vals.append(node.val)
                if node.left:
                    next_level.append(node.left)
                if node.right:
                    next_level.append(node.right)
            queue = next_level
            result.append(curr_vals)
        return result


if __name__ == '__main__':
    tree = TreeNode.from_list([3, 9, 20, None, None, 15, 7])
    print(tree)
    sol = Solution()
    t = sol.levelOrder(tree)
    print(t)
Ejemplo n.º 18
0
def preorderNonRecursive(self, root):
    if root is None:
        return []
    stack, res = [root], []
    while stack:
        node = stack.pop()
        res.append(node.val)
        if node.right is not None:
            stack.append(node.right)
        if node.left is not None:
            stack.append(node.left)
    return res


if __name__ == '__main__':
    tree = TreeNode(6)
    tree.left = TreeNode(8)
    tree.right = TreeNode(4)
    tree.left.left = TreeNode(9)
    tree.left.right = TreeNode(7)
    tree.right.left = TreeNode(5)
    tree.right.right = TreeNode(3)
    print(bfs(tree))
    print("---------")
    # print(dfs(tree))
    print('---------')
    print(f'inorder is {inorderTraversal(tree)}')
    print(f'dfs preorder is {dfsPreorder(tree)}')
    print(f'dfs postorder is {dfsPostorder(tree)}')
    # print(f'inorderTravsalTest is {inorderTraversalTest(tree)}')