def get_ticketoshow(ticket_id):
from ditic_kanban.rt_api import get_ticketdetail
from ditic_kanban.rt_api import get_ticket_links
from ditic_kanban.rt_api import get_tickethistory
result = create_default_result()
if request.query.o == "" or not user_auth.check_id(request.query.o):
result.update({"message": ""})
return template("auth", result)
ticket = get_ticketdetail(
user_auth.get_rt_object_from_email(user_auth.get_email_from_id(request.query.o)), ticket_id
)
links = get_ticket_links(
user_auth.get_rt_object_from_email(user_auth.get_email_from_id(request.query.o)), ticket_id
)
history = get_tickethistory(
user_auth.get_rt_object_from_email(user_auth.get_email_from_id(request.query.o)), ticket_id
)
result = create_default_result()
result.update({"ticket": ticket})
result.update({"links": links})
result.update({"history": history})
return template("show_ticket", result)
def __get_root_parent(rt_object, element):
# Get links for this element
result = get_ticket_links(rt_object, element)
parent = 0
for line in result:
if 'memberof' in line:
if parent:
raise ValueError('More than one parent... sorry, but it is not allowed by now :(')
parent = int(line[1])
if parent == 0:
return element
else:
return __get_root_parent(rt_object, parent)
def __insert_into_project_management(rt_object, project_management_object, element, parent=0):
# TODO this operation takes too long! One possible resolution is:
# TODO - get all tickets using only get_ticket_links function
# TODO - with all tickets ID, perform only one query for all info of all objects
# TODO even so, this will take too long... :(
element_dict = get_list_of_tickets(rt_object, 'id='+str(element))[0]
project_management_object.add_element(element, parent, element_dict)
# Get links for this element
result = get_ticket_links(rt_object, element)
for line in result:
if line[0] == 'members':
__insert_into_project_management(rt_object, project_management_object, int(line[1]), int(element))
return
def __get_root_parent(rt_object, element):
# Get links for this element
result = get_ticket_links(rt_object, element)
parent = 0
for line in result:
if 'memberof' in line:
if parent:
raise ValueError(
'More than one parent... sorry, but it is not allowed by now :('
)
parent = int(line[1])
if parent == 0:
return element
else:
return __get_root_parent(rt_object, parent)
def test_get_ticket_links():
rt_object = RTApiMock()
rt_object.set_return(
[
u'rt/4.0.6 200 ok',
u'',
u'id: ticket/885775/links',
u'',
u'members: fsck.com-rt://uc.pt/ticket/887677,',
u'fsck.com-rt://uc.pt/ticket/897183,',
u'fsck.com-rt://uc.pt/ticket/899145',
u'',
u''
]
)
result = get_ticket_links(rt_object, 885775)
assert result == [[u'members', u'887677'], [u'members', u'897183'], [u'members', u'899145']]
def __insert_into_project_management(rt_object,
project_management_object,
element,
parent=0):
# TODO this operation takes too long! One possible resolution is:
# TODO - get all tickets using only get_ticket_links function
# TODO - with all tickets ID, perform only one query for all info of all objects
# TODO even so, this will take too long... :(
element_dict = get_list_of_tickets(rt_object, 'id=' + str(element))[0]
project_management_object.add_element(element, parent, element_dict)
# Get links for this element
result = get_ticket_links(rt_object, element)
for line in result:
if line[0] == 'members':
__insert_into_project_management(rt_object,
project_management_object,
int(line[1]), int(element))
return
