b = example.new_intp()
c = example.new_intp()
example.intp_assign(a, 37)
example.intp_assign(b, 42)
print(" a =", a)
print(" b =", b)
print(" c =", c)
# 在指针对象上调用add函数
example.add(a, b, c)
# 得到结果
r = example.intp_value(c)
print(" 37 + 42 =", r)
# 清除指针
example.delete_intp(a)
example.delete_intp(b)
example.delete_intp(c)
# 现在尝试一下类型映射库(typemaps)
# 这样的方式会简单许多，因为不再需要操纵指针。
print("Trying the typemap library")
r = example.sub(37, 42)
print(" 37 - 42 =", r)
# 现在尝试一下具有多个返回值的函数
print("Testing multiple return values")
q, r = example.divide(42, 37)
print(" 42/37 = %d remainder %d" % (q, r))
def test_5_division_with_zero():
"""Test 1."""
with pytest.raises(ZeroDivisionError):
example.divide(1, 0)
def test_divide(self):
self.assertEquals(2, example.divide(4, 2))
self.assertTrue(example.divide(40, 20) == 2)
self.assertFalse(example.divide(33, 54) == 7)
def test_4_divide():
"""Test 1."""
assert example.divide(4, 2) == 2
print " a =", a print " b =", b print " c =", c # Call the add() function with some pointers example.add(a, b, c) # Now get the result r = example.intp_value(c) print " 37 + 42 =", r # Clean up the pointers example.delete_intp(a) example.delete_intp(b) example.delete_intp(c) # Now try the typemap library # This should be much easier. Now how it is no longer # necessary to manufacture pointers. print "Trying the typemap library" r = example.sub(37, 42) print " 37 - 42 =", r # Now try the version with multiple return values print "Testing multiple return values" q, r = example.divide(42, 37) print " 42/37 = %d remainder %d" % (q, r)