def test_interned(self):
salt = uuid4().hex
def make_string():
# We need to actually create a new string so that it has refcount
# one. We use a uuid so that we know the string could not already
# be in the intern table.
return ''.join(('testing: ', salt))
# This should work, the string has one reference on the stack.
move_into_mutable_buffer(make_string())
refcount = [None] # nonlocal
def ref_capture(ob):
# Subtract two because those are the references owned by this
# frame:
# 1. The local variables of this stack frame.
# 2. The python data stack of this stack frame.
refcount[0] = sys.getrefcount(ob) - 2
return ob
with pytest.raises(BadMove):
# If we intern the string it will still have one reference but now
# it is in the intern table so if other people intern the same
# string while the mutable buffer holds the first string they will
# be the same instance.
move_into_mutable_buffer(ref_capture(intern(make_string()))) # noqa
assert refcount[0] == 1
def test_interned(self):
salt = uuid4().hex
def make_string():
# We need to actually create a new string so that it has refcount
# one. We use a uuid so that we know the string could not already
# be in the intern table.
return ''.join(('testing: ', salt))
# This should work, the string has one reference on the stack.
move_into_mutable_buffer(make_string())
refcount = [None] # nonlocal
def ref_capture(ob):
# Subtract two because those are the references owned by this
# frame:
# 1. The local variables of this stack frame.
# 2. The python data stack of this stack frame.
refcount[0] = sys.getrefcount(ob) - 2
return ob
with pytest.raises(BadMove):
# If we intern the string it will still have one reference but now
# it is in the intern table so if other people intern the same
# string while the mutable buffer holds the first string they will
# be the same instance.
move_into_mutable_buffer(ref_capture(intern(make_string()))) # noqa
assert refcount[0] == 1