Ejemplo n.º 1
0
def evalf_log(expr, prec, options):
    arg = expr.args[0]
    workprec = prec+10
    xre, xim, xacc, _ = evalf(arg, workprec, options)

    if xim:
        # XXX: use get_abs etc instead
        re = evalf_log(C.log(C.abs(arg, evaluate=False), evaluate=False), prec, options)
        im = mpf_atan2(xim, xre or fzero, prec)
        return re[0], im, re[2], prec

    imaginary_term = (mpf_cmp(xre, fzero) < 0)

    re = mpf_log(mpf_abs(xre), prec, round_nearest)
    size = fastlog(re)
    if prec - size > workprec:
        # We actually need to compute 1+x accurately, not x
        arg = C.Add(S.NegativeOne,arg,evaluate=False)
        xre, xim, xre_acc, xim_acc = evalf_add(arg, prec, options)
        prec2 = workprec - fastlog(xre)
        re = mpf_log(mpf_add(xre, fone, prec2), prec, round_nearest)

    re_acc = prec

    if imaginary_term:
        return re, mpf_pi(prec), re_acc, prec
    else:
        return re, None, re_acc, None
Ejemplo n.º 2
0
def npartitions(n, verbose=False):
    """
    Calculate the partition function P(n), i.e. the number of ways that
    n can be written as a sum of positive integers.

    P(n) is computed using the Hardy-Ramanujan-Rademacher formula,
    described e.g. at http://mathworld.wolfram.com/PartitionFunctionP.html

    The correctness of this implementation has been tested for 10**n
    up to n = 8.
    """
    n = int(n)
    if n < 0: return 0
    if n <= 5: return [1, 1, 2, 3, 5, 7][n]
    # Estimate number of bits in p(n). This formula could be tidied
    pbits = int((math.pi*(2*n/3.)**0.5-math.log(4*n))/math.log(10)+1)*\
        math.log(10,2)
    prec = p = int(pbits*1.1 + 100)
    s = fzero
    M = max(6, int(0.24*n**0.5+4))
    sq23pi = mpf_mul(mpf_sqrt(from_rational(2,3,p), p), mpf_pi(p), p)
    sqrt8 = mpf_sqrt(from_int(8), p)
    for q in xrange(1, M):
        a = A(n,q,p)
        d = D(n,q,p, sq23pi, sqrt8)
        s = mpf_add(s, mpf_mul(a, d), prec)
        if verbose:
            print "step", q, "of", M, to_str(a, 10), to_str(d, 10)
        # On average, the terms decrease rapidly in magnitude. Dynamically
        # reducing the precision greatly improves performance.
        p = bitcount(abs(to_int(d))) + 50
    np = to_int(mpf_add(s, fhalf, prec))
    return int(np)
Ejemplo n.º 3
0
def D(n, j, prec, sq23pi, sqrt8):
    """
    Compute the sinh term in the outer sum of the HRR formula.
    The constants sqrt(2/3*pi) and sqrt(8) must be precomputed.
    """
    j = from_int(j)
    pi = mpf_pi(prec)
    a = mpf_div(sq23pi, j, prec)
    b = mpf_sub(from_int(n), from_rational(1,24,prec), prec)
    c = mpf_sqrt(b, prec)
    ch, sh = cosh_sinh(mpf_mul(a,c), prec)
    D = mpf_div(mpf_sqrt(j,prec), mpf_mul(mpf_mul(sqrt8,b),pi), prec)
    E = mpf_sub(mpf_mul(a,ch), mpf_div(sh,c,prec), prec)
    return mpf_mul(D, E)
Ejemplo n.º 4
0
def _create_evalf_table():
    global evalf_table
    evalf_table = {
    C.Symbol : evalf_symbol,
    C.Dummy : evalf_symbol,
    C.Real : lambda x, prec, options: (x._mpf_, None, prec, None),
    C.Rational : lambda x, prec, options: (from_rational(x.p, x.q, prec), None, prec, None),
    C.Integer : lambda x, prec, options: (from_int(x.p, prec), None, prec, None),
    C.Zero : lambda x, prec, options: (None, None, prec, None),
    C.One : lambda x, prec, options: (fone, None, prec, None),
    C.Half : lambda x, prec, options: (fhalf, None, prec, None),
    C.Pi : lambda x, prec, options: (mpf_pi(prec), None, prec, None),
    C.Exp1 : lambda x, prec, options: (mpf_e(prec), None, prec, None),
    C.ImaginaryUnit : lambda x, prec, options: (None, fone, None, prec),
    C.NegativeOne : lambda x, prec, options: (fnone, None, prec, None),

    C.exp : lambda x, prec, options: evalf_pow(C.Pow(S.Exp1, x.args[0],
        evaluate=False), prec, options),

    C.cos : evalf_trig,
    C.sin : evalf_trig,

    C.Add : evalf_add,
    C.Mul : evalf_mul,
    C.Pow : evalf_pow,

    C.log : evalf_log,
    C.atan : evalf_atan,
    C.abs : evalf_abs,

    C.re : evalf_re,
    C.im : evalf_im,
    C.floor : evalf_floor,
    C.ceiling : evalf_ceiling,

    C.Integral : evalf_integral,
    C.Sum : evalf_sum,
    C.Piecewise : evalf_piecewise,

    C.bernoulli : evalf_bernoulli,
    }
Ejemplo n.º 5
0
 def _as_mpf_val(self, prec):
     return mpf_pi(prec)
Ejemplo n.º 6
0
 def _as_mpf_val(self, prec):
     return mpf_pi(prec)