Ejemplo n.º 1
0
def test_generate():
    from sympy.ntheory.generate import sieve
    sieve._reset()
    assert nextprime(-4) == 2
    assert nextprime(2) == 3
    assert nextprime(5) == 7
    assert nextprime(12) == 13
    assert prevprime(3) == 2
    assert prevprime(7) == 5
    assert prevprime(13) == 11
    assert prevprime(19) == 17
    assert prevprime(20) == 19

    sieve.extend_to_no(9)
    assert sieve._list[-1] == 23

    assert sieve._list[-1] < 31
    assert 31 in sieve

    assert nextprime(90) == 97
    assert nextprime(10**40) == (10**40 + 121)
    assert prevprime(97) == 89
    assert prevprime(10**40) == (10**40 - 17)
    assert list(sieve.primerange(10, 1)) == []
    assert list(primerange(10, 1)) == []
    assert list(primerange(2, 7)) == [2, 3, 5]
    assert list(primerange(2, 10)) == [2, 3, 5, 7]
    assert list(primerange(1050, 1100)) == [1051, 1061,
        1063, 1069, 1087, 1091, 1093, 1097]
    s = Sieve()
    for i in range(30, 2350, 376):
        for j in range(2, 5096, 1139):
            A = list(s.primerange(i, i + j))
            B = list(primerange(i, i + j))
            assert A == B
    s = Sieve()
    assert s[10] == 29

    assert nextprime(2, 2) == 5

    raises(ValueError, lambda: totient(0))

    raises(ValueError, lambda: reduced_totient(0))

    raises(ValueError, lambda: primorial(0))

    assert mr(1, [2]) is False

    func = lambda i: (i**2 + 1) % 51
    assert next(cycle_length(func, 4)) == (6, 2)
    assert list(cycle_length(func, 4, values=True)) == \
        [17, 35, 2, 5, 26, 14, 44, 50, 2, 5, 26, 14]
    assert next(cycle_length(func, 4, nmax=5)) == (5, None)
    assert list(cycle_length(func, 4, nmax=5, values=True)) == \
        [17, 35, 2, 5, 26]
    sieve.extend(3000)
    assert nextprime(2968) == 2969
    assert prevprime(2930) == 2927
    raises(ValueError, lambda: prevprime(1))
Ejemplo n.º 2
0
def generate_encodings(size: int) -> [int]:
    """
    Generate the encodings for size number of cards.
    We use prime numbers so when multiplied together,
    no two cards would generate the encoding of a third card.
    """
    sieve.extend_to_no(size)
    return list(sieve._list[:size])
Ejemplo n.º 3
0
def part_two_fn():
    b = 105700
    c = 122700
    ##    sieve._reset()
    sieve.extend_to_no(c)
    h = 0
    for i in range(b, c + 1, 17):
        if i not in sieve:
            h += 1
    return h
Ejemplo n.º 4
0
def problem7(nr_of_prime):
    """Problem 7 - 10001st prime"""

    # old code :)
    # primelist = []

    # i = 2
    # while len(primelist) < nr_of_prime:
    #     prime = True
    #     for x in primelist:
    #         if i % x == 0:
    #             prime = False
    #             break
    #     if prime:
    #         primelist.append(i)
    #     i = i+1

    sieve.extend_to_no(nr_of_prime)
    return sieve._list[nr_of_prime - 1]
Ejemplo n.º 5
0
"""
Find the smallest number n such that the number of divisors of n is equal to (2 ^ 500500)
"""

import heapq
from sympy import sieve

sieve.extend_to_no(500500)

H = [(3, 3, 1), (4, 2, 3)]
i = 3  # next prime to add from sieve (indexing starts at 1 so 3 would mean the 3rd prime (5))
n = 2  # number so far (mod 500500507)
for _ in range(2, 500501):
    p = heapq.heappop(H)
    if p[2] == 1:
        heapq.heappush(H, (sieve[i], sieve[i], 1))
        i += 1
    nextE = (p[2] + 1) * 2 - 1
    heapq.heappush(H, (p[1]**(nextE - p[2]), p[1], nextE))
    n *= p[0]
    n %= 500500507

print(n)
Ejemplo n.º 6
0
def test_generate():
    from sympy.ntheory.generate import sieve
    sieve._reset()
    assert nextprime(-4) == 2
    assert nextprime(2) == 3
    assert nextprime(5) == 7
    assert nextprime(12) == 13
    assert prevprime(3) == 2
    assert prevprime(7) == 5
    assert prevprime(13) == 11
    assert prevprime(19) == 17
    assert prevprime(20) == 19

    sieve.extend_to_no(9)
    assert sieve._list[-1] == 23

    assert sieve._list[-1] < 31
    assert 31 in sieve

    assert nextprime(90) == 97
    assert nextprime(10**40) == (10**40 + 121)
    assert prevprime(97) == 89
    assert prevprime(10**40) == (10**40 - 17)

    assert list(sieve.primerange(10, 1)) == []
    assert list(sieve.primerange(5, 9)) == [5, 7]
    sieve._reset(prime=True)
    assert list(sieve.primerange(2, 12)) == [2, 3, 5, 7, 11]

    assert list(sieve.totientrange(5, 15)) == [4, 2, 6, 4, 6, 4, 10, 4, 12, 6]
    sieve._reset(totient=True)
    assert list(sieve.totientrange(3, 13)) == [2, 2, 4, 2, 6, 4, 6, 4, 10, 4]
    assert list(sieve.totientrange(900, 1000)) == [totient(x) for x in range(900, 1000)]
    assert list(sieve.totientrange(0, 1)) == []
    assert list(sieve.totientrange(1, 2)) == [1]

    assert list(sieve.mobiusrange(5, 15)) == [-1, 1, -1, 0, 0, 1, -1, 0, -1, 1]
    sieve._reset(mobius=True)
    assert list(sieve.mobiusrange(3, 13)) == [-1, 0, -1, 1, -1, 0, 0, 1, -1, 0]
    assert list(sieve.mobiusrange(1050, 1100)) == [mobius(x) for x in range(1050, 1100)]
    assert list(sieve.mobiusrange(0, 1)) == []
    assert list(sieve.mobiusrange(1, 2)) == [1]

    assert list(primerange(10, 1)) == []
    assert list(primerange(2, 7)) == [2, 3, 5]
    assert list(primerange(2, 10)) == [2, 3, 5, 7]
    assert list(primerange(1050, 1100)) == [1051, 1061,
        1063, 1069, 1087, 1091, 1093, 1097]
    s = Sieve()
    for i in range(30, 2350, 376):
        for j in range(2, 5096, 1139):
            A = list(s.primerange(i, i + j))
            B = list(primerange(i, i + j))
            assert A == B
    s = Sieve()
    assert s[10] == 29

    assert nextprime(2, 2) == 5

    raises(ValueError, lambda: totient(0))

    raises(ValueError, lambda: reduced_totient(0))

    raises(ValueError, lambda: primorial(0))

    assert mr(1, [2]) is False

    func = lambda i: (i**2 + 1) % 51
    assert next(cycle_length(func, 4)) == (6, 2)
    assert list(cycle_length(func, 4, values=True)) == \
        [17, 35, 2, 5, 26, 14, 44, 50, 2, 5, 26, 14]
    assert next(cycle_length(func, 4, nmax=5)) == (5, None)
    assert list(cycle_length(func, 4, nmax=5, values=True)) == \
        [17, 35, 2, 5, 26]
    sieve.extend(3000)
    assert nextprime(2968) == 2969
    assert prevprime(2930) == 2927
    raises(ValueError, lambda: prevprime(1))
Ejemplo n.º 7
0
from sympy import ntheory
from sympy import sieve
from sympy import generate

sieve._reset(
)  # An infinite list of prime numbers, implemented as a dynamically growing sieve of Eratosthenes.#When a lookup is
# requested involving an odd number that has not been sieved,the sieve is automatically extended up to that number.

print(13 in sieve)  # prints 'True' if the input is prime,

sieve.extend(40)  #for input n grows the sieve to contain all primes <= n

print(sieve[10])  # returns n th prime

sieve.extend_to_no(15)  # extends upto n th prime

# mobiusrange(a,b) genarates Mobius numbers for the range [a,b), means output will be a list.
Mob_func = sieve.mobiusrange(7, 12)
print('\n Mobius function outputs in the given range:', [i for i in Mob_func])

# primerange(a,b) generates all prime numbers in the range [a,b)
Prime_list = sieve.primerange(1, 5)
print('\n Primes in the given range are :', [i for i in Prime_list])

#search(n) return the indices i, j of the primes that bound n. If n is prime then i == j. Although n can be an expression,
# if ceiling cannot convert it to an integer then an error will be raised.
x, y = sieve.search(25)
print('\n The given input is in between ', '(', x, ',', y, ')', 'th Primes \n')

#totientrange(a, b) generates all totient numbers for the range [a, b). Simply it is a list of outputs
Ejemplo n.º 8
0
#!/usr/bin/env python3

##### IMPORTS

from cryptography.hazmat.primitives import hashes
from cryptography.hazmat.backends import default_backend

from secrets import randbits
import socket
from sympy import gcd, isprime, primefactors, sieve

# sieve speed-up courtesy: Wiener, Michael J. "Safe Prime Generation with a Combined Sieve." IACR Cryptol. ePrint Arch. 2003 (2003): 186.
# create a sieve of values to avoid
sieve.extend_to_no(150)  # somewhere around here is best for my workstation
prime_list = list(sieve._list)[2:]
prime_avoid = [(r - 1) // 2 for r in prime_list]

##### METHODS


def split_ip_port(string):
    """Split the given string into an IP address and port number.
    
    PARAMETERS
    ==========
    string: A string of the form IP:PORT.

    RETURNS
    =======
    If successful, a tuple of the form (IP,PORT), where IP is a 
      string and PORT is a number. Otherwise, returns None.
from sympy import sieve
from sympy import factorint
from math import sqrt
import cProfile

pr = cProfile.Profile()
pr.enable()

max_n = 20000000

print("Solving factorizations up to n = {}".format(max_n))
print("Calculating all necessary primes...")
sieve.extend_to_no(max_n)

print("Factoring")
for x in range(2, max_n + 1):
    if x % 100000 == 0:
        print("Currently at: {}".format(x))
    factorint(x)

pr.disable()
pr.print_stats(sort='time')