Ejemplo n.º 1
0
    def test_replace(self):

        var1 = MyVariable("var1")
        var2 = MyVariable("var2")
        var3 = op1(var2, var1)
        var4 = op2(var3, var2)
        var5 = op3(var4, var2, var2)
        fg = FunctionGraph([var1, var2], [var3, var5], clone=False)

        with pytest.raises(Exception, match="Cannot replace.*"):
            var4.fgraph = object()
            # Trigger a `FunctionGraph` ownership error
            fg.replace(var4, var1, verbose=True)

        var4.fgraph = fg

        with pytest.raises(BadOptimization):
            var0 = MyVariable2("var0")
            # The types don't match and one cannot be converted to the other
            fg.replace(var3, var0)

        # Test a basic replacement
        fg.replace_all([(var3, var1)])
        assert var3 not in fg.variables
        assert fg.apply_nodes == {var4.owner, var5.owner}
        assert var4.owner.inputs == [var1, var2]
Ejemplo n.º 2
0
    def test_replace_circular(self):
        """`FunctionGraph` allows cycles--for better or worse."""

        var1 = MyVariable("var1")
        var2 = MyVariable("var2")
        var3 = op1(var2, var1)
        var4 = op2(var3, var2)
        var5 = op3(var4, var2, var2)
        fg = FunctionGraph([var1, var2], [var3, var5], clone=False)

        fg.replace_all([(var3, var4)])

        # The following works (and is kind of gross), because `var4` has been
        # mutated in-place
        assert fg.apply_nodes == {var4.owner, var5.owner}
        assert var4.owner.inputs == [var4, var2]