def format(self, args):
# Format each package inside each result set
packages = []
for results in XML.getChildElements(XML.dig(args.message.xml, "message", "body", "builder")):
if results.nodeName == 'results':
for package in XML.getChildElements(results):
if package.nodeName == 'package':
packages.append(self.format_package(package))
return self.joinMessage(args.message, packages)
def component_files(self, element, args):
"""Format the contents of our <files> tag as a tree with nested lists"""
from LibCIA.Web import Template
files = XML.dig(args.message.xml, "message", "body", "commit", "files")
if not (files and XML.hasChildElements(files)):
return []
# First we organize the files into a tree of nested dictionaries.
# The dictionary we ultimately have FileTree render maps each node
# (file or directory) to a dictionary of its contents. The keys
# in these dictionaries can be any Nouvelle-renderable object
# produced by format_file.
#
# As a first step, we build a dictionary mapping path segment to
# [fileTag, children] lists. We then create a visual representation
# of each fileTag and generate the final dictionary.
fileTree = {}
for fileTag in XML.getChildElements(files):
if fileTag.nodeName == 'file':
# Separate the file into path segments and walk into our tree
node = [None, fileTree]
for segment in XML.shallowText(fileTag).split('/'):
if segment:
node = node[1].setdefault(segment, [None, {}])
# The leaf node owns this fileTag
node[0] = fileTag
return [Template.FileTree(self.format_file_tree(fileTree))]
def consolidateFiles(self, xmlFiles):
"""Given a <files> element, find the directory common to all files
and return a 2-tuple with that directory followed by
a list of files within that directory.
"""
files = []
if xmlFiles:
for fileTag in XML.getChildElements(xmlFiles):
if fileTag.nodeName == 'file':
files.append(XML.shallowText(fileTag))
# If we only have one file, return it as the prefix.
# This prevents the below regex from deleting the filename
# itself, assuming it was a partial filename.
if len(files) == 1:
return files[0], []
# Start with the prefix found by commonprefix,
# then actually make it end with a directory rather than
# possibly ending with part of a filename.
prefix = re.sub("[^/]*$", "", posixpath.commonprefix(files))
endings = []
for file in files:
ending = file[len(prefix):].strip()
if ending == '':
ending = '.'
endings.append(ending)
return prefix, endings
def format_results(self, package):
"""Given a package, returns a formatted representation of all results for that package"""
results = []
for element in XML.getChildElements(package):
f = getattr(self, 'result_' + element.nodeName, None)
if f:
results.append(f(element))
def component_files(self, element, args):
"""Format the contents of our <files> tag as a tree with nested lists"""
from LibCIA.Web import Template
files = XML.dig(args.message.xml, "message", "body", "commit", "files")
if not (files and XML.hasChildElements(files)):
return []
# First we organize the files into a tree of nested dictionaries.
# The dictionary we ultimately have FileTree render maps each node
# (file or directory) to a dictionary of its contents. The keys
# in these dictionaries can be any Nouvelle-renderable object
# produced by format_file.
#
# As a first step, we build a dictionary mapping path segment to
# [fileTag, children] lists. We then create a visual representation
# of each fileTag and generate the final dictionary.
fileTree = {}
for fileTag in XML.getChildElements(files):
if fileTag.nodeName == 'file':
# Separate the file into path segments and walk into our tree
node = [None, fileTree]
for segment in XML.shallowText(fileTag).split('/'):
if segment:
node = node[1].setdefault(segment, [None, {}])
# The leaf node owns this fileTag
node[0] = fileTag
return [Template.FileTree(self.format_file_tree(fileTree))]
def consolidateFiles(self, xmlFiles):
"""Given a <files> element, find the directory common to all files
and return a 2-tuple with that directory followed by
a list of files within that directory.
"""
files = []
if xmlFiles:
for fileTag in XML.getChildElements(xmlFiles):
if fileTag.nodeName == 'file':
files.append(XML.shallowText(fileTag))
# If we only have one file, return it as the prefix.
# This prevents the below regex from deleting the filename
# itself, assuming it was a partial filename.
if len(files) == 1:
return files[0], []
# Start with the prefix found by commonprefix,
# then actually make it end with a directory rather than
# possibly ending with part of a filename.
prefix = re.sub("[^/]*$", "", posixpath.commonprefix(files))
endings = []
for file in files:
ending = file[len(prefix):].strip()
if ending == '':
ending = '.'
endings.append(ending)
return prefix, endings
def getSvnRevision(self):
"""Return the current Subversion repository revision, or None
if we're not in an svn working copy or it can't be parsed.
"""
try:
entries = XML.parseString(open(".svn/entries").read()).documentElement
highestRev = 0
for tag in XML.getChildElements(entries):
if tag.nodeName == 'entry':
rev = tag.getAttributeNS(None, 'committed-rev')
if rev and rev > highestRev:
highestRev = rev
return highestRev
except:
return None
