Python is_palindrome_two_pointer Examples

Example #1

File: test_strings.py Project: achapkowski/algorithms

 def test_is_palindrome_two_pointer(self):
     # 'Otto' is a old german name.
     self.assertTrue(is_palindrome_two_pointer("Otto"))
     self.assertFalse(is_palindrome_two_pointer("house"))

Example #2

File: test_strings.py Project: nolanding/algorithms

 def test_is_palindrome_two_pointer(self):
     # 'Otto' is a old german name.
     self.assertTrue(is_palindrome_two_pointer("Otto"))
     self.assertFalse(is_palindrome_two_pointer("house"))

Example #3

File: 13.Strings_is_palindrome.py Project: seanlab1/algorithms-1

"""
Given a string, determine if it is a palindrome,
considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.
Note:
Have you consider that the string might be empty?
This is a good question to ask during an interview.
For the purpose of this problem,
we define empty string as valid palindrome.
"""

from algorithms.strings import is_palindrome,remove_punctuation,is_palindrome_reverse,is_palindrome_two_pointer,is_palindrome_stack


s="abcdcba"

print(is_palindrome(s))

print(is_palindrome_reverse(s))

print(is_palindrome_two_pointer(s))

print(is_palindrome_stack(s))