def test_enumerate_options_bankrupt(self):
# simulate having only one die left and rolling a 3
s = State(2)
s.rolled_dice = [Dice(3)]
s.can_roll = 0
assert s.enumerate_options() == []
def test_enumerate_finds_straight(self):
s = State(2)
s.can_roll
s.rolled_dice = [Dice(i) for i in range(1, 7)]
actions = s.enumerate_options()
want = Action({i: 1 for i in range(1, 7)}, "1-2-3-4-5-6", 3000)
assert want in actions
def test_enumerate_roll_and_stop(self):
# the condition for having roll and stop is if we've scored
# any dice with the current roll
s = State(2).roll() # don't care what roll is, just that it sets can_roll to 0
assert s.can_roll == 0
actions = s.enumerate_options()
roll = Action({}, "roll", 0)
stop = Action({}, "stop", 0)
assert roll not in actions
assert stop not in actions
# now change can_roll
s.can_roll = 1
actions2 = s.enumerate_options()
assert roll in actions2
assert stop in actions2
def test_enumerate_finds_three_pairs(self):
s = State(2)
s.rolled_dice = [Dice(2), Dice(2), Dice(3), Dice(3), Dice(4), Dice(4)]
s.can_roll = 0
actions = s.enumerate_options()
want = [Action({2: 2, 3: 2, 4: 2}, "Three pairs", 1500)]
assert len(actions) == len(want)
assert all(a in want for a in actions)
def test_enumerate_finds_three_singles(self):
s = State(2)
s.can_rol = 0
for num in range(1, 7):
other = 2 if num != 2 else 3
s.rolled_dice = [Dice(num)] * 3 + [Dice(other)] * 3
actions = s.enumerate_options()
points = 1000 if num == 1 else num * 100
want = Action({num: 3}, f"Three {num}'s", points)
assert want in actions
def test_enumerate_finds_four_five_six_kind(self):
s = State(2)
s.can_roll = 0
for num in range(1, 7):
for n in range(4, 7):
other = 2 if num != 2 else 3
s.rolled_dice = [Dice(num)] * n + [Dice(other)] * (6 - n)
actions = s.enumerate_options()
name = {4: "Four", 5: "Five", 6: "Six"}[n]
points = {4: 1000, 5: 2000, 6: 3000}[n]
want = Action({num: n}, f"{name} {num}'s", points)
assert want in actions