def list_directory(self, path): """Helper to produce a directory listing (absent index.html). Return value is either a file object, or None (indicating an error). In either case, the headers are sent, making the interface the same as for send_head(). """ try: list = os.listdir(path) except os.error: self.send_error(404, "No permission to list directory") return None list.sort(key=lambda a: a.lower()) r = [] displaypath = html.escape(urllib_parse.unquote(self.path)) enc = sys.getfilesystemencoding() title = 'Directory listing for %s' % displaypath r.append('<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" ' '"http://www.w3.org/TR/html4/strict.dtd">') r.append('<html>\n<head>') r.append('<meta http-equiv="Content-Type" ' 'content="text/html; charset=%s">' % enc) r.append('<title>%s</title>\n</head>' % title) r.append('<body>\n<h1>%s</h1>' % title) r.append('<hr>\n<ul>') for name in list: fullname = os.path.join(path, name) displayname = linkname = name # Append / for directories or @ for symbolic links if os.path.isdir(fullname): displayname = name + "/" linkname = name + "/" if os.path.islink(fullname): displayname = name + "@" # Note: a link to a directory displays with @ and links with / r.append('<li><a href="%s">%s</a></li>' % (urllib_parse.quote(linkname), html.escape(displayname))) # # Use this instead: # r.append('<li><a href="%s">%s</a></li>' # % (urllib.quote(linkname), cgi.escape(displayname))) r.append('</ul>\n<hr>\n</body>\n</html>\n') encoded = '\n'.join(r).encode(enc) f = io.BytesIO() f.write(encoded) f.seek(0) self.send_response(200) self.send_header("Content-type", "text/html; charset=%s" % enc) self.send_header("Content-Length", str(len(encoded))) self.end_headers() return f