def __pow__(s, t): cls, new, (prec, rounding) = s._ctxdata if isinstance(t, int_types): v = new(cls) v._mpc_ = mpc_pow_int(s._mpc_, t, prec, rounding) return v t = s.mpc_convert_lhs(t) if t is NotImplemented: return t v = new(cls) if hasattr(t, '_mpf_'): v._mpc_ = mpc_pow_mpf(s._mpc_, t._mpf_, prec, rounding) else: v._mpc_ = mpc_pow(s._mpc_, t._mpc_, prec, rounding) return v
def fsum(ctx, terms, absolute=False, squared=False): """ Calculates a sum containing a finite number of terms (for infinite series, see :func:`nsum`). The terms will be converted to mpmath numbers. For len(terms) > 2, this function is generally faster and produces more accurate results than the builtin Python function :func:`sum`. >>> from mpmath import * >>> mp.dps = 15; mp.pretty = False >>> fsum([1, 2, 0.5, 7]) mpf('10.5') With squared=True each term is squared, and with absolute=True the absolute value of each term is used. """ prec, rnd = ctx._prec_rounding real = [] imag = [] other = 0 for term in terms: reval = imval = 0 if hasattr(term, "_mpf_"): reval = term._mpf_ elif hasattr(term, "_mpc_"): reval, imval = term._mpc_ else: term = ctx.convert(term) if hasattr(term, "_mpf_"): reval = term._mpf_ elif hasattr(term, "_mpc_"): reval, imval = term._mpc_ else: if absolute: term = ctx.absmax(term) if squared: term = term**2 other += term continue if imval: if squared: if absolute: real.append(mpf_mul(reval, reval)) real.append(mpf_mul(imval, imval)) else: reval, imval = mpc_pow_int((reval, imval), 2, prec + 10) real.append(reval) imag.append(imval) elif absolute: real.append(mpc_abs((reval, imval), prec)) else: real.append(reval) imag.append(imval) else: if squared: reval = mpf_mul(reval, reval) elif absolute: reval = mpf_abs(reval) real.append(reval) s = mpf_sum(real, prec, rnd, absolute) if imag: s = ctx.make_mpc((s, mpf_sum(imag, prec, rnd))) else: s = ctx.make_mpf(s) if other is 0: return s else: return s + other
def fsum(ctx, terms, absolute=False, squared=False): """ Calculates a sum containing a finite number of terms (for infinite series, see :func:`nsum`). The terms will be converted to mpmath numbers. For len(terms) > 2, this function is generally faster and produces more accurate results than the builtin Python function :func:`sum`. >>> from mpmath import * >>> mp.dps = 15; mp.pretty = False >>> fsum([1, 2, 0.5, 7]) mpf('10.5') With squared=True each term is squared, and with absolute=True the absolute value of each term is used. """ prec, rnd = ctx._prec_rounding real = [] imag = [] other = 0 for term in terms: reval = imval = 0 if hasattr(term, "_mpf_"): reval = term._mpf_ elif hasattr(term, "_mpc_"): reval, imval = term._mpc_ else: term = ctx.convert(term) if hasattr(term, "_mpf_"): reval = term._mpf_ elif hasattr(term, "_mpc_"): reval, imval = term._mpc_ else: if absolute: term = ctx.absmax(term) if squared: term = term**2 other += term continue if imval: if squared: if absolute: real.append(mpf_mul(reval,reval)) real.append(mpf_mul(imval,imval)) else: reval, imval = mpc_pow_int((reval,imval),2,prec+10) real.append(reval) imag.append(imval) elif absolute: real.append(mpc_abs((reval,imval), prec)) else: real.append(reval) imag.append(imval) else: if squared: reval = mpf_mul(reval, reval) elif absolute: reval = mpf_abs(reval) real.append(reval) s = mpf_sum(real, prec, rnd, absolute) if imag: s = ctx.make_mpc((s, mpf_sum(imag, prec, rnd))) else: s = ctx.make_mpf(s) if other is 0: return s else: return s + other