def plus(va,vb):
app=va.find('.')
ap=app
if ap==-1:ap=len(va)
bpp=vb.find('.')
bp=bpp
if bp==-1:bp=len(vb)
if ap>bp:l=ap
else:l=bp
ar=len(va)-ap-1
if app==-1:ar=0
br=len(vb)-bp-1
if bpp==-1:br=0
if ar>br:m=ar
else:m=br
n=l+m+1
a=['5']*n
b=['5']*n
afor=l-ap+1
for i in va:
if i!='.':
a[afor]=i
afor+=1
bfor=l-bp+1
for i in vb:
if i!='.':
b[bfor]=i
bfor+=1
pab=l+1
chck=['5']*n
up=a
rsl=b
while up!=chck:
a=up
b=rsl
up=['5']*n
rsl=['5']*n
for i in range(n):
i+=1
out=see(a[-i],b[-i])
if out=='error':
print 'see .. crashed as supposed '
exit()
rsl[-i]=out[1]
if out[0]!='5':up[-i-1]=out[0]
re=''
j=0
for i in range(n):
re+=rsl[i]
if j==l:re+='.'
j+=1
return shape(re)
def plus(va, vb):
app = va.find('.')
ap = app
if ap == -1: ap = len(va)
bpp = vb.find('.')
bp = bpp
if bp == -1: bp = len(vb)
if ap > bp: l = ap
else: l = bp
ar = len(va) - ap - 1
if app == -1: ar = 0
br = len(vb) - bp - 1
if bpp == -1: br = 0
if ar > br: m = ar
else: m = br
n = l + m + 1
a = ['5'] * n
b = ['5'] * n
afor = l - ap + 1
for i in va:
if i != '.':
a[afor] = i
afor += 1
bfor = l - bp + 1
for i in vb:
if i != '.':
b[bfor] = i
bfor += 1
pab = l + 1
chck = ['5'] * n
up = a
rsl = b
while up != chck:
a = up
b = rsl
up = ['5'] * n
rsl = ['5'] * n
for i in range(n):
i += 1
out = see(a[-i], b[-i])
if out == 'error':
print 'see .. crashed as supposed '
exit()
rsl[-i] = out[1]
if out[0] != '5': up[-i - 1] = out[0]
re = ''
j = 0
for i in range(n):
re += rsl[i]
if j == l: re += '.'
j += 1
return shape(re)
刚开始的赋值比较复杂,为了骗过初始的循环条件
pab=l+1
chck=['5']*n
up=a
rsl=b
while up!=chck:
a=up
b=rsl
up=['5']*n
rsl=['5']*n
这里就是主体的,取出每一位的两个数对比
然后赋值给out,将out的两位分别赋值给up和rsl
for i in range(n):
i+=1
out=see(a[-i],b[-i])
if out=='error':
print 'see .. crashed as supposed '
exit()
rsl[-i]=out[1]
if out[0]!='5':up[-i-1]=out[0]
re=''
j=0
把小数点加回来,l是左边的整数长度
for i in range(n):
re+=rsl[i]
if j==l:re+='.'
j+=1
格式化后返回值