def test_copy(self):
s = OrderedSet()
for i in range(1, 10):
to = TestObject(i)
s.add(to)
s1 = s.copy()
assert id(s1) != id(s)
objects = [t.ord_value() for t in s1]
assert objects == [1, 2, 3, 4, 5, 6, 7, 8, 9]
def _visit(self, p_map, v_note):
"""
Recursive method used to derive sets of solution to the constraints constraint problem.
:param p_map: PMap
:param v_note: ContextualNote, source key of PMap
:return: A set of pmaps
"""
if p_map[v_note].note is not None: # setting means visited
return {}
results = OrderedSet()
# list of tuples (v_note, {solution to v_note's policies})
result_values = self._build_potential_values(p_map, {v_note})
if len(result_values) == 0:
return results
for value in result_values[0][1]: # [0] is for v_note; [1] is the set of values.
p_map[v_note].note = value
value_results = OrderedSet() # results for this value for v_note + solutions for ALL peers to v_note
# Advantage in the following, setting above partially solves each policy v_note is involved in.
# For this 'value' for v_note, dive depth first through all v_note peers (all policies v_note is in)
# which collectively we call a branch.
# peer_candidates are all unassigned actors in v_note's policies.
peer_candidates = self._candidate_closure(p_map, v_note)
if len(peer_candidates) == 0:
# We reached the end of a branch, save the result.
if self._full_check_and_validate(p_map):
if self.instance_limit != -1 and self.__num_instances >= self.instance_limit:
return results
self.full_results.append(p_map.replicate())
self.__num_instances = self.__num_instances + 1
else:
value_results.add(p_map.replicate()) # We only need a shallow copy
else:
for c_note in peer_candidates:
if self.instance_limit != -1 and self.__num_instances >= self.instance_limit:
results = results.union(value_results)
return results
if len(value_results) == 0: # first time through this loop per value, visit with p_map!
value_results = self._visit(p_map, c_note)
if len(value_results) == 0: # Indicates failure to assign c_note, move to next value.
break # If one peer fails, they all will, for this 'value'!
else:
value_results_copy = value_results.copy()
# for peer c_note, if all r below fails (len(cand_results) == 0) should we also move on to
# next value? Add 'found' flag, set after union, after loop, check if False, to break
found = False
for r in value_results_copy:
if r[c_note].note is None:
cand_results = self._visit(r, c_note)
if len(cand_results) != 0:
value_results = value_results.union(cand_results)
found = True
value_results.remove(r) # r has no c_note assigned, what was returned did!
# If not, r's peers cannot be assigned!
if found is False: # Same as if part, if c_note produces no results, it cannot be assigned.
break # If one peer fails, they all will!
results = results.union(value_results)
p_map[v_note].note = None
return results