def generateKey(keySize):
    # Creates public/private keys keySize bits in size.
    p = 0
    q = 0
    # Step 1: Create two prime numbers, p and q. Calculate n = p * q:
    print('Generating p prime...')
    while p == q:
        p = primeNum.generateLargePrime(keySize)
        q = primeNum.generateLargePrime(keySize)
    n = p * q
    # Step 2: Create a number e that is relatively prime to (p-1)*(q-1):
    print('Generating e that is relatively prime to (p-1)*(q-1)...')
    while True:
        # Keep trying random numbers for e until one is valid:
        e = random.randrange(2**(keySize - 1), 2**(keySize))
        if cryptomath.gcd(e, (p - 1) * (q - 1)) == 1:
            break
    # Step 3: Calculate d, the mod inverse of e:
    print('Calculating d that is mod inverse of e...')
    d = cryptomath.findModInverse(e, (p - 1) * (q - 1))
    publicKey = (n, e)
    privateKey = (n, d)
    print('Public key:', publicKey)
    print('Private key:', privateKey)
    return (publicKey, privateKey)
Example #2
0
def generateKey(keySize):
    p = 0
    q = 0
    # Step1: create two prime numbers, p and q. calculate n = p * q:
    print('Generating p prime...')
    while p == q:
        p = primeNum.generateLargePrime(keySize)
        q = primeNum.generateLargePrime(keySize)
    n = p * q

    # Step2: Create a number e that is relatively prime to (p-1)*(q-1):
    print('Generating e that is relatively prime to (p-1)*(q-1)...')
    x = (p - 1) * (q - 1)
    while True:
        e = random.randrange(2**(keySize - 1), 2**(keySize))
        if cryptomath.gcd(e, x) == 1:
            break

    # Step3: Calculate d, the mod inverse of e:
    print('Calculating d that is mod inverse of e...')
    d = cryptomath.findModInverse(e, x)

    publicKey = (n, e)
    privateKey = (n, d)

    print('Public Key:\n', publicKey)
    print('Private Key:\n', privateKey)

    return (publicKey, privateKey)
def generateKey(keysize):
    p = 0
    q = 0

    print('Generating p prime...')
    while p == q:
        p = primeNum.generateLargePrime(keysize)
        q = primeNum.generateLargePrime(keysize)
    n = p * q

    print('Generating e that is relatively prime to (p-1)*(q-1)...')
    while True:
        e = random.randrange(2**(keysize - 1), 2**(keysize))
        if cryptomath.gcd(e, (p - 1) * (q - 1)) == 1:
            break

    print('Calculating d that is mod inverse of e...')
    d = cryptomath.findModInverse(e, (p - 1) * (q - 1))

    publicKey = (n, e)
    privateKey = (n, d)

    print('Public key:', publicKey)
    print('Private key:', privateKey)

    return (publicKey, privateKey)
Example #4
0
def generateKey(keySize):
    # Create public/private keys keySize bits in size
    p = 0
    q = 0
    # Create two primes, p and q. Calculate n = p * q
    print("Generating p prime...")
    while p == q:
        p = primeNum.generateLargePrime(keySize)
        q = primeNum.generateLargePrime(keySize)
    n = p * q

    # Create number e that is relatively prime to (p-1)*(q-1)
    print("Generating e that is relatively prime to (p-1) * (q-1)...")
    while True:
        # Keep trying rand numbers for e until one is valid
        e = random.randrange(2**(keySize - 1), 2**keySize)
        if cryptomath.gcd(e, (p - 1) * (q - 1)) == 1:
            break

    # Calculate d, mod inverse of e
    print("Calculating d that is the mod inverse of e...")
    d = cryptomath.findModInverse(e, (p - 1) * (q - 1))

    publicKey = (n, e)
    privateKey = (n, d)

    print(f"Public key: {publicKey}")
    print(f"Private key: {privateKey}")

    return publicKey, privateKey
Example #5
0
def generateKey(keySize):
    # Creates a public/private key pair with keys that are keySize bits in size.
    #This function may take a while to run

    # Step 1: Create two prime numbers, p and q. Calculate n = p * q.
    print("Generating p prime...")
    p = primeNum.generateLargePrime(keySize)
    print("Generating q prime...")
    q = primeNum.generateLargePrime(keySize)
    n = p * q

    # Step 2: Create a number e that is relatively prime to (p-1)*(q-1).
    print("Generating e that is relitively prime to (p-1)*(q-1)...")
    while True:
        # keep trying random numbers for e until a valid one is found
        e = random.randrange(2**(keySize - 1), 2**(keySize))
        if cryptomath.gcd(e, (p - 1) * (q - 1)) == 1:
            break

    # step 3: calculate d, the mod inverse of e
    print("calculating d, the mod inverse of e")
    d = cryptomath.findModInverse(e, (p - 1) * (q - 1))

    publicKey = (n, e)
    privateKey = (n, d)

    print("Public Key")
    print("Private Key")

    return (publicKey, privateKey)
def generateKey(keySize):
    p = 0
    q = 0
    while p == q:
        p = primeNum.generateLargePrime(keySize)
        q = primeNum.generateLargePrime(keySize)
    n = p * q
    while True:
        e = random.randrange(2**(keySize - 1), 2**keySize)
        if cryptoMath.gcd(e, (p - 1) * (q - 1)) == 1:
            break
    d = cryptoMath.findModInverse(e, (p - 1) * (q - 1))
    publicKey = (n, e)
    privateKey = (n, d)

    return publicKey, privateKey
def generateKey(keySize):
    p = 0
    q = 0
    while p == q:
        p = primeNum.generateLargePrime(keySize)
        q = primeNum.generateLargePrime(keySize)
    n = p * q

    print('Generating e that is realativly prime to (p-1)*(q-1)...')
    while True:
        e = random.randrange(2**(keySize - 1), 2**(keySize))
        if cryptomath.gcd(e, (p - 1) * (q - 1)) == 1:
            break

    d = cryptomath.findModInverse(e, (p - 1) * (q - 1))
    publicKey = (n, e)
    privateKey = (n, d)

    print('Public key', publicKey)
    print('Private key', privateKey)

    return publicKey, privateKey
Example #8
0
def createKey(keysize):
    p = 0
    q = 0
    e = 0
    d = 0
    print('finding p, q, and n')
    while q == p:
        q = primeNum.generateLargePrime(keysize=1024)
        p = primeNum.generateLargePrime(keysize=1024)
    n = p * q

    print('finding e')
    while cryptoMath.gcd(e, (p - 1) * (q - 1)) != 1:
        e = random.randrange(2**(keysize - 1), 2**(keysize))

    print('finding d')
    d = cryptoMath.findModInverse(e, (p - 1) * (q - 1))

    publicKey = (n, e)
    privateKey = (n, d)

    return (publicKey, privateKey)