def nsolve(*args, **kwargs): """ Solve a nonlinear equation system numerically. nsolve(f, [args,] x0, modules=['mpmath'], **kwargs) f is a vector function of symbolic expressions representing the system. args are the variables. If there is only one variable, this argument can be omitted. x0 is a starting vector close to a solution. Use the modules keyword to specify which modules should be used to evaluate the function and the Jacobian matrix. Make sure to use a module that supports matrices. For more information on the syntax, please see the docstring of lambdify. Overdetermined systems are supported. >>> from sympy import Symbol, nsolve >>> import sympy >>> sympy.mpmath.mp.dps = 15 >>> x1 = Symbol('x1') >>> x2 = Symbol('x2') >>> f1 = 3 * x1**2 - 2 * x2**2 - 1 >>> f2 = x1**2 - 2 * x1 + x2**2 + 2 * x2 - 8 >>> print nsolve((f1, f2), (x1, x2), (-1, 1)) [-1.19287309935246] [ 1.27844411169911] For one-dimensional functions the syntax is simplified: >>> from sympy import sin, nsolve >>> from sympy.abc import x >>> nsolve(sin(x), x, 2) 3.14159265358979 >>> nsolve(sin(x), 2) 3.14159265358979 mpmath.findroot is used, you can find there more extensive documentation, especially concerning keyword parameters and available solvers. """ # interpret arguments if len(args) == 3: f = args[0] fargs = args[1] x0 = args[2] elif len(args) == 2: f = args[0] fargs = None x0 = args[1] elif len(args) < 2: raise TypeError("nsolve expected at least 2 arguments, got %i" % len(args)) else: raise TypeError("nsolve expected at most 3 arguments, got %i" % len(args)) modules = kwargs.get("modules", ["mpmath"]) if isinstance(f, (list, tuple)): f = Matrix(f).T if not isinstance(f, Matrix): # assume it's a sympy expression if isinstance(f, Equality): f = f.lhs - f.rhs f = f.evalf() atoms = f.atoms(Symbol) if fargs is None: fargs = atoms.copy().pop() if not (len(atoms) == 1 and (fargs in atoms or fargs[0] in atoms)): raise ValueError("expected a one-dimensional and numerical function") # the function is much better behaved if there is no denominator f = f.as_numer_denom()[0] f = lambdify(fargs, f, modules) return findroot(f, x0, **kwargs) if len(fargs) > f.cols: raise NotImplementedError("need at least as many equations as variables") verbose = kwargs.get("verbose", False) if verbose: print "f(x):" print f # derive Jacobian J = f.jacobian(fargs) if verbose: print "J(x):" print J # create functions f = lambdify(fargs, f.T, modules) J = lambdify(fargs, J, modules) # solve the system numerically x = findroot(f, x0, J=J, **kwargs) return x
def nsolve(*args, **kwargs): """ Solve a nonlinear equation system numerically. nsolve(f, [args,] x0, modules=['mpmath'], **kwargs) f is a vector function of symbolic expressions representing the system. args are the variables. If there is only one variable, this argument can be omitted. x0 is a starting vector close to a solution. Use the modules keyword to specify which modules should be used to evaluate the function and the Jacobian matrix. Make sure to use a module that supports matrices. For more information on the syntax, please see the docstring of lambdify. Overdetermined systems are supported. >>> from sympy import Symbol, nsolve >>> import sympy >>> sympy.mpmath.mp.dps = 15 >>> x1 = Symbol('x1') >>> x2 = Symbol('x2') >>> f1 = 3 * x1**2 - 2 * x2**2 - 1 >>> f2 = x1**2 - 2 * x1 + x2**2 + 2 * x2 - 8 >>> print nsolve((f1, f2), (x1, x2), (-1, 1)) [-1.19287309935246] [ 1.27844411169911] For one-dimensional functions the syntax is simplified: >>> from sympy import sin, nsolve >>> from sympy.abc import x >>> nsolve(sin(x), x, 2) 3.14159265358979 >>> nsolve(sin(x), 2) 3.14159265358979 mpmath.findroot is used, you can find there more extensive documentation, especially concerning keyword parameters and available solvers. """ # interpret arguments if len(args) == 3: f = args[0] fargs = args[1] x0 = args[2] elif len(args) == 2: f = args[0] fargs = None x0 = args[1] elif len(args) < 2: raise TypeError('nsolve expected at least 2 arguments, got %i' % len(args)) else: raise TypeError('nsolve expected at most 3 arguments, got %i' % len(args)) modules = kwargs.get('modules', ['mpmath']) if isinstance(f, (list, tuple)): f = Matrix(f).T if not isinstance(f, Matrix): # assume it's a sympy expression if isinstance(f, Equality): f = f.lhs - f.rhs f = f.evalf() atoms = f.atoms(Symbol) if fargs is None: fargs = atoms.copy().pop() if not (len(atoms) == 1 and (fargs in atoms or fargs[0] in atoms)): raise ValueError( 'expected a one-dimensional and numerical function') # the function is much better behaved if there is no denominator f = f.as_numer_denom()[0] f = lambdify(fargs, f, modules) return findroot(f, x0, **kwargs) if len(fargs) > f.cols: raise NotImplementedError( 'need at least as many equations as variables') verbose = kwargs.get('verbose', False) if verbose: print 'f(x):' print f # derive Jacobian J = f.jacobian(fargs) if verbose: print 'J(x):' print J # create functions f = lambdify(fargs, f.T, modules) J = lambdify(fargs, J, modules) # solve the system numerically x = findroot(f, x0, J=J, **kwargs) return x