Example #1
0
    def load(fn_ins, simplify=False, corner=None, rm_zero=False):
        zero_names = OrderedSet()

        Ads, b = loadc_Ads_b(fn_ins, corner=corner, ico=True)
        if rm_zero:
            zero_names = rm_zero_cols(Ads)
        if simplify:
            print('Simplifying corner %s' % (corner, ))
            Ads, b = simplify_rows(Ads, b, remove_zd=False, corner=corner)
        return State(Ads, zero_names=zero_names)
Example #2
0
def run(fout, fns_in, corner, verbose=0):
    Ads, b = loadc_Ads_b(fns_in, corner, ico=True)
    Ads, b = simplify_rows(Ads, b, corner=corner)

    fout.write('ico,fast_max fast_min slow_max slow_min,rows...\n')
    for row_b, row_ds in zip(b, Ads):
        # write in same format, but just stick to this corner
        out_b = [str(row_b) for _i in range(4)]
        ico = '1'
        items = [ico, ' '.join(out_b)]

        for k, v in sorted(row_ds.items()):
            items.append('%u %s' % (v, k))
        fout.write(','.join(items) + '\n')
Example #3
0
 def load(fn_ins, simplify=False, corner=None):
     Ads, b = loadc_Ads_b(fn_ins, corner=corner, ico=True)
     if simplify:
         print('Simplifying corner %s' % (corner, ))
         Ads, b = simplify_rows(Ads, b, remove_zd=False, corner=corner)
     return State(Ads)
Example #4
0
def massage_equations(Ads, b, verbose=False, corner=None):
    '''
    Subtract equations from each other to generate additional constraints
    Helps provide additional guidance to solver for realistic delays

    Ex: given:
    a >= 10
    a + b >= 100
    A valid solution is:
         a = 100
    However, a better solution is something like
        a = 10
        b = 90
    This creates derived constraints to provide more realistic results

    Equation pipeline
    Some operations may generate new equations
    Simplify after these to avoid unnecessary overhead on redundant constraints
    Similarly some operations may eliminate equations, potentially eliminating a column (ie variable)
    Remove these columns as necessary to speed up solving
    '''

    assert len(Ads) == len(b), 'Ads, b length mismatch'

    def check_cols():
        assert len(index_names(Ads)) == cols

    def debug(what):
        check_cols()
        if 1 or verbose:
            print('')
            print_eqns(Ads, b, verbose=verbose, label=what, lim=20)
            col_dist(Ads, what)
            #check_feasible_d(Ads, b)

    # Try to (intelligently) subtract equations to generate additional constraints
    # This helps avoid putting all delay in a single shared variable
    dstart = len(b)
    cols = len(index_names(Ads))

    # Each iteration one more column is allowed until all columns are included
    # (and the system is stable)
    col_lim = 15
    di = 0
    while True:
        print
        n_orig = len(b)

        print('Loop %d, lim %d' % (di + 1, col_lim))
        # Meat of the operation
        Ads, b = derive_eq_by_row(Ads, b, col_lim=col_lim, cmp_heuristic=True)
        debug("der_rows")
        # Run another simplify pass since new equations may have overlap with original
        Ads, b = simplify_rows(Ads, b, corner=corner)
        print('Derive row: %d => %d equations' % (n_orig, len(b)))
        debug("der_rows simp")

        # derive_cols is mostly degenerate case of derive_rows
        # however, it will sub out single variables a lot faster if there are a lot of them
        # linear vs above quadratic, might as well keep it in
        if 1:
            n_orig2 = len(b)
            # Meat of the operation
            Ads, b = derive_eq_by_col(Ads, b)
            debug("der_cols")
            # Run another simplify pass since new equations may have overlap with original
            Ads, b = simplify_rows(Ads, b, corner=corner)
            print('Derive col %d: %d => %d equations' %
                  (di + 1, n_orig2, len(b)))
            debug("der_cols simp")

        # Doesn't help computation, but helps debugging
        Ads, b = sort_equations(Ads, b)
        debug("loop done")
        col_dist(Ads, 'derive done iter %d, lim %d' % (di, col_lim), lim=12)

        rows = len(Ads)
        # possible that a new equation was generated and taken away, but close enough
        if n_orig == len(b) and col_lim >= cols:
            break
        col_lim += col_lim / 5
        di += 1

        dend = len(b)
        print('')
        print('Derive net: %d => %d' % (dstart, dend))
        print('')
        # Was experimentting to see how much the higher order columns really help

    # Helps debug readability
    Ads, b = sort_equations(Ads, b)
    debug("final (sorted)")
    print('')
    print('Massage final: %d => %d rows' % (dstart, dend))
    cols_end = len(index_names(Ads))
    print('Massage final: %d => %d cols' % (cols, cols_end))
    assert cols_end == cols
    return Ads, b
Example #5
0
def run(fns_in,
        corner,
        run_corner,
        sub_json=None,
        bounds_csv=None,
        dedup=True,
        massage=False,
        outfn=None,
        verbose=False,
        **kwargs):
    print('Loading data')
    Ads, b = loadc_Ads_b(fns_in, corner, ico=True)

    # Remove duplicate rows
    # is this necessary?
    # maybe better to just add them into the matrix directly
    if dedup:
        oldn = len(Ads)
        iold = instances(Ads)
        Ads, b = simplify_rows(Ads, b, corner=corner)
        print('Simplify %u => %u rows' % (oldn, len(Ads)))
        print('Simplify %u => %u instances' % (iold, instances(Ads)))

    if sub_json:
        print('Sub: %u rows' % len(Ads))
        iold = instances(Ads)
        names_old = index_names(Ads)
        run_sub_json(Ads, sub_json, verbose=verbose)
        names = index_names(Ads)
        print("Sub: %u => %u names" % (len(names_old), len(names)))
        print('Sub: %u => %u instances' % (iold, instances(Ads)))
    else:
        names = index_names(Ads)
    '''
    Substitution .csv
    Special .csv containing one variable per line
    Used primarily for multiple optimization passes, such as different algorithms or additional constraints
    '''
    if bounds_csv:
        Ads2, b2 = loadc_Ads_b([bounds_csv], corner, ico=True)
        bounds = Ads2bounds(Ads2, b2)
        assert len(bounds), 'Failed to load bounds'
        rows_old = len(Ads)
        Ads, b = filter_bounds(Ads, b, bounds, corner)
        print('Filter bounds: %s => %s + %s rows' %
              (rows_old, len(Ads), len(Ads2)))
        Ads = Ads + Ads2
        b = b + b2
        assert len(Ads) or allow_zero_eqns()
        assert len(Ads) == len(b), 'Ads, b length mismatch'

    if verbose:
        print
        print_eqns(Ads, b, verbose=verbose)

        #print
        #col_dist(A_ubd, 'final', names)
    if massage:
        try:
            Ads, b = massage_equations(Ads, b, corner=corner)
        except SimplifiedToZero:
            if not allow_zero_eqns():
                raise
            print('WARNING: simplified to zero equations')
            Ads = []
            b = []

    print('Converting to numpy...')
    names, Anp = A_ds2np(Ads)
    run_corner(Anp,
               np.asarray(b),
               names,
               corner,
               outfn=outfn,
               verbose=verbose,
               **kwargs)