def relpath(self, path, start='.'):
# Since os.path.relpath() calls os.path.normpath()
# (see http://docs.python.org/library/os.path.html#os.path.abspath )
# it also removes trailing slashes and converts forward and backward
# slashes to the preferred slash os.sep.
start = self.abspath(start)
path = self.abspath(path)
if not path.lower().startswith(start.lower()):
# Then path is outside the directory given by start.
return None # FIXME: os.relpath still returns a path here.
rel_path = path[len(start):]
if not rel_path:
# Then the paths are the same.
pass
elif rel_path[0] == self.sep:
# It is probably sufficient to remove just the first character
# since os.path.normpath() collapses separators, but we use
# lstrip() just to be sure.
rel_path = rel_path.lstrip(self.sep)
else:
# We are in the case typified by the following example:
# path = "/tmp/foobar", start = "/tmp/foo" -> rel_path = "bar"
return None
return rel_path
def relpath(self, path, start='.'):
# Since os.path.relpath() calls os.path.normpath()
# (see http://docs.python.org/library/os.path.html#os.path.abspath )
# it also removes trailing slashes and converts forward and backward
# slashes to the preferred slash os.sep.
start = self.abspath(start)
path = self.abspath(path)
if not path.lower().startswith(start.lower()):
# path is outside the directory given by start; compute path from root
return '../' * start.count('/') + path
rel_path = path[len(start):]
if not rel_path:
# Then the paths are the same.
pass
elif rel_path[0] == self.sep:
# It is probably sufficient to remove just the first character
# since os.path.normpath() collapses separators, but we use
# lstrip() just to be sure.
rel_path = rel_path.lstrip(self.sep)
else:
# We are in the case typified by the following example:
# path = "/tmp/foobar", start = "/tmp/foo" -> rel_path = "bar"
# FIXME: We return a less-than-optimal result here.
return '../' * start.count('/') + path
return rel_path