def parse_tabbed_list(last_count, current_count, last_type, last_line, line, next_line):
# Determine the type of the current list
this_type = ""
if line[0].isdigit():
this_type = "ol"
else:
this_type = "ul"
if last_count != current_count:
print("Last line and current line are different lists")
return_string = "<" + this_type + ">\n" + constructHTML.construct_list_item(line)
if current_count != count_whitespace("\t", next_line):
# This line and the next line don't have the same indentation
return_string += "</" + this_type + ">\n"
elif line[0].isdigit():
if next_line[count_whitespace("\t", next_line)].isdigit() == False:
return_string += "</" + this_type + ">\n"
return this_type, return_string
else:
# The current list item and the last line/list item have the same
# identation.
if last_type != this_type:
print("COMPILE ERROR: You cannot have two different types", end='')
print(" in the same list.", end='')
print("AT LINE:", line)
exit("")
else:
print("Last line and current line are same lists")
return this_type, constructHTML.construct_list_item(line)
def parse_list(last_type, list_type, line, next_line):
# Check to see if list and last type are the same
return_string = ""
if last_type != list_type:
if list_type == "ol":
return_string = "<ol>\n" + constructHTML.construct_list_item(line)
return "ol", return_string
elif list_type == "ul":
return_string = "<ul>\n" + constructHTML.construct_list_item(line)
return "ul", return_string
else:
if next_line == "EOF":
if list_type == "ol":
return_string = constructHTML.construct_list_item(line) + "</ol>\n"
return "ol", return_string
else:
return_string = constructHTML.construct_list_item(line) + "</ul>\n"
return "ul", return_string
elif list_type == "ul":
if next_line[0] == "*":
# next thing is still an unordered list so we don't care
# about closing this off
return_string = constructHTML.construct_list_item(line)
return "ul", return_string
else:
# next thing ISN'T an unordered list so we need to close
return_string = constructHTML.construct_list_item(line) + "</ul>\n"
return "ul", return_string
elif list_type == "ol":
if next_line[0].isdigit():
# next thing is still an ordered list so we don't care about
# closing this off
return_string = constructHTML.construct_list_item(line)
return "ol", return_string
else:
# next thing ISN'T an ordered list so we need to close
return_string = constructHTML.construct_list_item(line) + "</ol>\n"
return "ol", return_string
