def graph_implementation(arg_objs, size, data=None): """Extracts the diagonal of a matrix. Parameters ---------- arg_objs : list LinExpr for each argument. size : tuple The size of the resulting expression. data : Additional data required by the atom. Returns ------- tuple (LinOp for objective, list of constraints) """ return (lu.diag_mat(arg_objs[0]), [])
def graph_implementation(self, arg_objs, shape: Tuple[int, ...], data=None) -> Tuple[lo.LinOp, List[Constraint]]: """Extracts the diagonal of a matrix. Parameters ---------- arg_objs : list LinExpr for each argument. shape : tuple The shape of the resulting expression. data : Additional data required by the atom. Returns ------- tuple (LinOp for objective, list of constraints) """ return (lu.diag_mat(arg_objs[0]), [])
def graph_implementation(arg_objs, size, data=None): """Reduces the atom to an affine expression and list of constraints. Creates the equivalent problem:: maximize sum(log(D[i, i])) subject to: D diagonal diag(D) = diag(Z) Z is upper triangular. [D Z; Z.T A] is positive semidefinite The problem computes the LDL factorization: .. math:: A = (Z^TD^{-1})D(D^{-1}Z) This follows from the inequality: .. math:: \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D) >= \det(D) because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves det(A) = det(D) and the objective maximizes det(D). Parameters ---------- arg_objs : list LinExpr for each argument. size : tuple The size of the resulting expression. data : Additional data required by the atom. Returns ------- tuple (LinOp for objective, list of constraints) """ A = arg_objs[0] # n by n matrix. n, _ = A.size X = lu.create_var((2 * n, 2 * n)) X, constraints = Semidef(2 * n).canonical_form Z = lu.create_var((n, n)) D = lu.create_var((n, 1)) # Require that X and A are PSD. constraints += [SDP(A)] # Fix Z as upper triangular, D as diagonal, # and diag(D) as diag(Z). Z_lower_tri = lu.upper_tri(lu.transpose(Z)) constraints.append(lu.create_eq(Z_lower_tri)) # D[i, i] = Z[i, i] constraints.append(lu.create_eq(D, lu.diag_mat(Z))) # Fix X using the fact that A must be affine by the DCP rules. # X[0:n, 0:n] == D index.block_eq(X, lu.diag_vec(D), constraints, 0, n, 0, n) # X[0:n, n:2*n] == Z, index.block_eq(X, Z, constraints, 0, n, n, 2 * n) # X[n:2*n, n:2*n] == A index.block_eq(X, A, constraints, n, 2 * n, n, 2 * n) # Add the objective sum(log(D[i, i]) obj, constr = log.graph_implementation([D], (n, 1)) return (lu.sum_entries(obj), constraints + constr)
def graph_implementation(arg_objs, size, data=None): """Reduces the atom to an affine expression and list of constraints. Creates the equivalent problem:: maximize sum(log(D[i, i])) subject to: D diagonal diag(D) = diag(Z) Z is upper triangular. [D Z; Z.T A] is positive semidefinite The problem computes the LDL factorization: .. math:: A = (Z^TD^{-1})D(D^{-1}Z) This follows from the inequality: .. math:: \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D) >= \det(D) because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves det(A) = det(D) and the objective maximizes det(D). Parameters ---------- arg_objs : list LinExpr for each argument. size : tuple The size of the resulting expression. data : Additional data required by the atom. Returns ------- tuple (LinOp for objective, list of constraints) """ A = arg_objs[0] # n by n matrix. n, _ = A.size X = lu.create_var((2*n, 2*n)) Z = lu.create_var((n, n)) D = lu.create_var((n, n)) # Require that X and A are PSD. constraints = [SDP(X), SDP(A)] # Fix Z as upper triangular, D as diagonal, # and diag(D) as diag(Z). for i in xrange(n): for j in xrange(n): if i != j: # D[i, j] == 0 Dij = index.get_index(D, constraints, i, j) constraints.append(lu.create_eq(Dij)) if i > j: # Z[i, j] == 0 Zij = index.get_index(Z, constraints, i, j) constraints.append(lu.create_eq(Zij)) # D[i, i] = Z[i, i] constraints.append(lu.create_eq(lu.diag_mat(D), lu.diag_mat(Z))) # Fix X using the fact that A must be affine by the DCP rules. # X[0:n, 0:n] == D index.block_eq(X, D, constraints, 0, n, 0, n) # X[0:n, n:2*n] == Z, index.block_eq(X, Z, constraints, 0, n, n, 2*n) # X[n:2*n, n:2*n] == A index.block_eq(X, A, constraints, n, 2*n, n, 2*n) # Add the objective sum(log(D[i, i]) diag = lu.diag_mat(D) obj, constr = log.graph_implementation([diag], (n, 1)) return (lu.sum_entries(obj), constraints + constr)
def graph_implementation(arg_objs, size, data=None): """Reduces the atom to an affine expression and list of constraints. Creates the equivalent problem:: maximize sum(log(D[i, i])) subject to: D diagonal diag(D) = diag(Z) Z is upper triangular. [D Z; Z.T A] is positive semidefinite The problem computes the LDL factorization: .. math:: A = (Z^TD^{-1})D(D^{-1}Z) This follows from the inequality: .. math:: \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D) >= \det(D) because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves det(A) = det(D) and the objective maximizes det(D). Parameters ---------- arg_objs : list LinExpr for each argument. size : tuple The size of the resulting expression. data : Additional data required by the atom. Returns ------- tuple (LinOp for objective, list of constraints) """ A = arg_objs[0] # n by n matrix. n, _ = A.size X = lu.create_var((2 * n, 2 * n)) Z = lu.create_var((n, n)) D = lu.create_var((n, n)) # Require that X and A are PSD. constraints = [SDP(X), SDP(A)] # Fix Z as upper triangular, D as diagonal, # and diag(D) as diag(Z). for i in xrange(n): for j in xrange(n): if i != j: # D[i, j] == 0 Dij = index.get_index(D, constraints, i, j) constraints.append(lu.create_eq(Dij)) if i > j: # Z[i, j] == 0 Zij = index.get_index(Z, constraints, i, j) constraints.append(lu.create_eq(Zij)) # D[i, i] = Z[i, i] constraints.append(lu.create_eq(lu.diag_mat(D), lu.diag_mat(Z))) # Fix X using the fact that A must be affine by the DCP rules. # X[0:n, 0:n] == D index.block_eq(X, D, constraints, 0, n, 0, n) # X[0:n, n:2*n] == Z, index.block_eq(X, Z, constraints, 0, n, n, 2 * n) # X[n:2*n, n:2*n] == A index.block_eq(X, A, constraints, n, 2 * n, n, 2 * n) # Add the objective sum(log(D[i, i]) log_diag = [] for i in xrange(n): Dii = index.get_index(D, constraints, i, i) obj, constr = log.graph_implementation([Dii], (1, 1)) constraints += constr log_diag.append(obj) obj = lu.sum_expr(log_diag) return (obj, constraints)