def test_check_family_bold_italic_unique_for_nameid1():
"""Check that OS/2.fsSelection bold/italic settings are unique within each
Compatible Family group (i.e. group of up to 4 with same NameID1)"""
from fontbakery.profiles.os2 import \
com_adobe_fonts_check_family_bold_italic_unique_for_nameid1 as check
from fontbakery.constants import FsSelection
base_path = portable_path("data/test/source-sans-pro/OTF")
# these fonts have the same NameID1
font_names = [
'SourceSansPro-Regular.otf', 'SourceSansPro-Bold.otf',
'SourceSansPro-It.otf', 'SourceSansPro-BoldIt.otf'
]
font_paths = [os.path.join(base_path, n) for n in font_names]
test_fonts = [TTFont(x) for x in font_paths]
# the family should be correctly constructed
status, message = list(check(test_fonts))[-1]
assert status == PASS
# now hack the italic font to also have the bold bit set
test_fonts[2]['OS/2'].fsSelection |= FsSelection.BOLD
# we should get a failure due to two fonts with both bold & italic set
status, message = list(check(test_fonts))[-1]
expected_message = "Family 'Source Sans Pro' has 2 fonts (should be no " \
"more than 1) with the same OS/2.fsSelection " \
"bold & italic settings: Bold=True, Italic=True"
assert message == expected_message
assert status == FAIL
def test_check_family_max_4_fonts_per_family_name():
from fontbakery.profiles.name import \
com_adobe_fonts_check_family_max_4_fonts_per_family_name as check
base_path = portable_path("data/test/source-sans-pro/OTF")
font_names = [
'SourceSansPro-Black.otf', 'SourceSansPro-BlackIt.otf',
'SourceSansPro-Bold.otf', 'SourceSansPro-BoldIt.otf',
'SourceSansPro-ExtraLight.otf', 'SourceSansPro-ExtraLightIt.otf',
'SourceSansPro-It.otf', 'SourceSansPro-Light.otf',
'SourceSansPro-LightIt.otf', 'SourceSansPro-Regular.otf',
'SourceSansPro-Semibold.otf', 'SourceSansPro-SemiboldIt.otf'
]
font_paths = [os.path.join(base_path, n) for n in font_names]
test_fonts = [TTFont(x) for x in font_paths]
# try fonts with correct family name grouping
status, message = list(check(test_fonts))[-1]
assert status == PASS
# now set 5 of the fonts to have the same family name
for font in test_fonts[:5]:
name_records = font['name'].names
for name_record in name_records:
if name_record.nameID == 1:
# print(repr(name_record.string))
name_record.string = 'foobar'.encode('utf-16be')
status, message = list(check(test_fonts))[-1]
assert status == FAIL and message.code == "too-many"
def test_check_name_postscript_name_consistency():
from fontbakery.profiles.name import \
com_adobe_fonts_check_name_postscript_name_consistency as check
base_path = portable_path("data/test/source-sans-pro/TTF")
font_path = os.path.join(base_path, 'SourceSansPro-Regular.ttf')
test_font = TTFont(font_path)
# SourceSansPro-Regular only has one name ID 6 entry (for Windows),
# let's add another one for Mac that matches the Windows entry:
test_font['name'].setName(
'SourceSansPro-Regular',
NameID.POSTSCRIPT_NAME,
PlatformID.MACINTOSH,
WindowsEncodingID.UNICODE_BMP,
ENGLISH_LANG_ID
)
status, message = list(check(test_font))[-1]
assert status == PASS
# ...now let's change the Mac name ID 6 entry to something else:
test_font['name'].setName(
'YetAnotherFontName',
NameID.POSTSCRIPT_NAME,
PlatformID.MACINTOSH,
WindowsEncodingID.UNICODE_BMP,
ENGLISH_LANG_ID
)
status, message = list(check(test_font))[-1]
assert status == FAIL
def test_check_family_bold_italic_unique_for_nameid1():
"""Check that OS/2.fsSelection bold/italic settings are unique within each
Compatible Family group (i.e. group of up to 4 with same NameID1)"""
from fontbakery.profiles.os2 import \
com_adobe_fonts_check_family_bold_italic_unique_for_nameid1 as check
from fontbakery.constants import FsSelection
base_path = portable_path("data/test/source-sans-pro/OTF")
# these fonts have the same NameID1
font_names = ['SourceSansPro-Regular.otf',
'SourceSansPro-Bold.otf',
'SourceSansPro-It.otf',
'SourceSansPro-BoldIt.otf']
font_paths = [os.path.join(base_path, n) for n in font_names]
test_fonts = [TTFont(x) for x in font_paths]
# the family should be correctly constructed
status, message = list(check(test_fonts))[-1]
assert status == PASS
# now hack the italic font to also have the bold bit set
test_fonts[2]['OS/2'].fsSelection |= FsSelection.BOLD
# we should get a failure due to two fonts with both bold & italic set
status, message = list(check(test_fonts))[-1]
expected_message = "Family 'Source Sans Pro' has 2 fonts (should be no " \
"more than 1) with the same OS/2.fsSelection " \
"bold & italic settings: Bold=True, Italic=True"
assert message == expected_message
assert status == FAIL
def test_check_name_postscript_name_consistency():
from fontbakery.profiles.name import \
com_adobe_fonts_check_name_postscript_name_consistency as check
base_path = portable_path("data/test/source-sans-pro/TTF")
font_path = os.path.join(base_path, 'SourceSansPro-Regular.ttf')
test_font = TTFont(font_path)
# SourceSansPro-Regular only has one name ID 6 entry (for Windows),
# let's add another one for Mac that matches the Windows entry:
test_font['name'].setName('SourceSansPro-Regular', NameID.POSTSCRIPT_NAME,
PlatformID.MACINTOSH, MacintoshEncodingID.ROMAN,
MacintoshLanguageID.ENGLISH)
status, message = list(check(test_font))[-1]
assert status == PASS
# ...now let's change the Mac name ID 6 entry to something else:
test_font['name'].setName('YetAnotherFontName', NameID.POSTSCRIPT_NAME,
PlatformID.MACINTOSH, MacintoshEncodingID.ROMAN,
MacintoshLanguageID.ENGLISH)
status, message = list(check(test_font))[-1]
assert status == FAIL and message.code == "inconsistency"
def test_check_family_max_4_fonts_per_family_name():
from fontbakery.profiles.name import \
com_adobe_fonts_check_family_max_4_fonts_per_family_name as check
base_path = portable_path("data/test/source-sans-pro/OTF")
font_names = [
'SourceSansPro-Black.otf',
'SourceSansPro-BlackIt.otf',
'SourceSansPro-Bold.otf',
'SourceSansPro-BoldIt.otf',
'SourceSansPro-ExtraLight.otf',
'SourceSansPro-ExtraLightIt.otf',
'SourceSansPro-It.otf',
'SourceSansPro-Light.otf',
'SourceSansPro-LightIt.otf',
'SourceSansPro-Regular.otf',
'SourceSansPro-Semibold.otf',
'SourceSansPro-SemiboldIt.otf']
font_paths = [os.path.join(base_path, n) for n in font_names]
test_fonts = [TTFont(x) for x in font_paths]
# try fonts with correct family name grouping
status, message = list(check(test_fonts))[-1]
assert status == PASS
# now set 5 of the fonts to have the same family name
for font in test_fonts[:5]:
name_records = font['name'].names
for name_record in name_records:
if name_record.nameID == 1:
# print(repr(name_record.string))
name_record.string = 'foobar'.encode('utf-16be')
status, message = list(check(test_fonts))[-1]
assert status == FAIL
